Edexcel C2 2009 January — Question 2 5 marks

Exam BoardEdexcel
ModuleC2 (Core Mathematics 2)
Year2009
SessionJanuary
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAreas by integration
TypeArea under polynomial curve
DifficultyModerate -0.5 This is a straightforward C2 integration question requiring expansion of the quadratic, integration using standard power rule, and evaluation between given limits. The boundaries are provided, eliminating any problem-solving element, making it slightly easier than average but still requiring correct algebraic manipulation and integration technique.
Spec1.08e Area between curve and x-axis: using definite integrals

\begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{12e54724-64a3-4dc0-b7d5-6ef6cc04124c-03_870_1027_205_406} \captionsetup{labelformat=empty} \caption{Figure 1}
\end{figure} Figure 1 shows part of the curve \(C\) with equation \(y = ( 1 + x ) ( 4 - x )\).
The curve intersects the \(x\)-axis at \(x = - 1\) and \(x = 4\). The region \(R\), shown shaded in Figure 1, is bounded by \(C\) and the \(x\)-axis. Use calculus to find the exact area of \(R\).

Question 2:
AnswerMarks Guidance
Working/AnswerMarks Guidance
\(y=(1+x)(4-x)=4+3x-x^2\)M1 Expand, giving 3 or 4 terms
\(\int(4+3x-x^2)dx = 4x+\frac{3x^2}{2}-\frac{x^3}{3}\)M1 A1 M1: \(x^n \to x^{n+1}\) for at least one term; A1 correct, allow \(+c\)
\(=\left(16+24-\frac{64}{3}\right)-\left(-4+\frac{3}{2}+\frac{1}{3}\right)=\frac{125}{6}\)M1 A1 M1: substitute limits 4 and \(-1\) and subtract; A1 must be exact (\(=20\frac{5}{6}\))
Total: [5]
## Question 2:

| Working/Answer | Marks | Guidance |
|---|---|---|
| $y=(1+x)(4-x)=4+3x-x^2$ | M1 | Expand, giving 3 or 4 terms |
| $\int(4+3x-x^2)dx = 4x+\frac{3x^2}{2}-\frac{x^3}{3}$ | M1 A1 | M1: $x^n \to x^{n+1}$ for at least one term; A1 correct, allow $+c$ |
| $=\left(16+24-\frac{64}{3}\right)-\left(-4+\frac{3}{2}+\frac{1}{3}\right)=\frac{125}{6}$ | M1 A1 | M1: substitute limits 4 and $-1$ and subtract; A1 must be exact ($=20\frac{5}{6}$) |
| **Total: [5]** | | |

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\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{12e54724-64a3-4dc0-b7d5-6ef6cc04124c-03_870_1027_205_406}
\captionsetup{labelformat=empty}
\caption{Figure 1}
\end{center}
\end{figure}

Figure 1 shows part of the curve $C$ with equation $y = ( 1 + x ) ( 4 - x )$.\\
The curve intersects the $x$-axis at $x = - 1$ and $x = 4$. The region $R$, shown shaded in Figure 1, is bounded by $C$ and the $x$-axis.

Use calculus to find the exact area of $R$.\\

\hfill \mbox{\textit{Edexcel C2 2009 Q2 [5]}}