Edexcel C1 2013 June — Question 3 4 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Year2013
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard Integrals and Reverse Chain Rule
TypeFind indefinite integral of polynomial/power
DifficultyEasy -1.3 This is a straightforward C1 integration question requiring only direct application of the power rule to two terms. Students need to recall that x^n integrates to x^(n+1)/(n+1) and rewrite 1/x² as x^(-2), then add the constant of integration. No problem-solving, substitution, or multi-step reasoning required—purely routine manipulation.
Spec1.08b Integrate x^n: where n != -1 and sums1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)

Find $$\int \left( 3 x ^ { 2 } - \frac { 4 } { x ^ { 2 } } \right) \mathrm { d } x$$ giving each term in its simplest form.

Question 3:
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\int 3x^2 - \frac{4}{x^2}dx = 3\frac{x^3}{3} - 4\frac{x^{-1}}{-1}\)M1, A1, A1 M1: \(x^n \to x^{n+1}\) for either term. A1: \(3\frac{x^3}{3}\) or \(-4\frac{x^{-1}}{-1}\) (one correct term, may be unsimplified). A1: both terms correct (may be unsimplified). Note M1A0A1 is not possible
\(= x^3 + \frac{4}{x} + c\) or \(x^3 + 4x^{-1} + c\)A1 Fully correct simplified answer with \(+c\) all appearing on the same line
## Question 3:

| Answer/Working | Mark | Guidance |
|---|---|---|
| $\int 3x^2 - \frac{4}{x^2}dx = 3\frac{x^3}{3} - 4\frac{x^{-1}}{-1}$ | M1, A1, A1 | M1: $x^n \to x^{n+1}$ for either term. A1: $3\frac{x^3}{3}$ **or** $-4\frac{x^{-1}}{-1}$ (one correct term, may be unsimplified). A1: both terms correct (may be unsimplified). Note M1A0A1 is not possible |
| $= x^3 + \frac{4}{x} + c$ or $x^3 + 4x^{-1} + c$ | A1 | Fully correct simplified answer with $+c$ all appearing on the same line |

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Find

$$\int \left( 3 x ^ { 2 } - \frac { 4 } { x ^ { 2 } } \right) \mathrm { d } x$$

giving each term in its simplest form.\\

\hfill \mbox{\textit{Edexcel C1 2013 Q3 [4]}}