Edexcel C1 2013 January — Question 3 6 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Year2013
SessionJanuary
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndices and Surds
TypeExpand and simplify surd expressions
DifficultyEasy -1.3 This is a routine C1 surds question testing standard techniques: expanding brackets with surds and simplifying/rationalizing expressions. Both parts require only direct application of basic surd rules with no problem-solving or insight needed, making it easier than average.
Spec1.02b Surds: manipulation and rationalising denominators

  1. Express $$( 5 - \sqrt { } 8 ) ( 1 + \sqrt { } 2 )$$ in the form \(a + b \sqrt { } 2\), where \(a\) and \(b\) are integers.
  2. Express $$\sqrt { } 80 + \frac { 30 } { \sqrt { } 5 }$$ in the form \(c \sqrt { } 5\), where \(c\) is an integer.

Question 3:
Part (i)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\((5-\sqrt{8})(1+\sqrt{2})\) expanded to four terms: \(= 5 + 5\sqrt{2} - \sqrt{8} - 4\)M1 Multiplies out brackets correctly giving four correct terms or simplifying to correct expansion
\(\sqrt{8} = 2\sqrt{2}\) used: \(= 5 + 5\sqrt{2} - 2\sqrt{2} - 4\)B1 \(\sqrt{8} = 2\sqrt{2}\), seen or implied at any point
\(= 1 + 3\sqrt{2}\)A1 Fully simplified to \(1 + 3\sqrt{2}\) or \(a=1\) and \(b=3\)
Part (ii)
AnswerMarks Guidance
Answer/WorkingMark Guidance
Rationalise: \(\sqrt{80} + \frac{30}{\sqrt{5}}\cdot\frac{\sqrt{5}}{\sqrt{5}}\) or equivalent methodM1 Rationalises denominator, multiplies \(\frac{k}{\sqrt{5}}\) by \(\frac{\sqrt{5}}{\sqrt{5}}\) or \(\frac{-\sqrt{5}}{-\sqrt{5}}\), seen or implied
\(\sqrt{80} = 4\sqrt{5}\) statedB1 Independent mark: \(\sqrt{80}=4\sqrt{5}\), or \(\sqrt{400}=20\), or \(\sqrt{80}\cdot\sqrt{5}=20\)
\(= 4\sqrt{5} + 6\sqrt{5} = 10\sqrt{5}\)A1 \(10\sqrt{5}\) or \(c=10\)
## Question 3:

### Part (i)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $(5-\sqrt{8})(1+\sqrt{2})$ expanded to four terms: $= 5 + 5\sqrt{2} - \sqrt{8} - 4$ | M1 | Multiplies out brackets correctly giving four correct terms or simplifying to correct expansion |
| $\sqrt{8} = 2\sqrt{2}$ used: $= 5 + 5\sqrt{2} - 2\sqrt{2} - 4$ | B1 | $\sqrt{8} = 2\sqrt{2}$, seen or implied at any point |
| $= 1 + 3\sqrt{2}$ | A1 | Fully simplified to $1 + 3\sqrt{2}$ or $a=1$ and $b=3$ |

### Part (ii)
| Answer/Working | Mark | Guidance |
|---|---|---|
| Rationalise: $\sqrt{80} + \frac{30}{\sqrt{5}}\cdot\frac{\sqrt{5}}{\sqrt{5}}$ or equivalent method | M1 | Rationalises denominator, multiplies $\frac{k}{\sqrt{5}}$ by $\frac{\sqrt{5}}{\sqrt{5}}$ or $\frac{-\sqrt{5}}{-\sqrt{5}}$, seen or implied |
| $\sqrt{80} = 4\sqrt{5}$ stated | B1 | Independent mark: $\sqrt{80}=4\sqrt{5}$, or $\sqrt{400}=20$, or $\sqrt{80}\cdot\sqrt{5}=20$ |
| $= 4\sqrt{5} + 6\sqrt{5} = 10\sqrt{5}$ | A1 | $10\sqrt{5}$ or $c=10$ |

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(i) Express

$$( 5 - \sqrt { } 8 ) ( 1 + \sqrt { } 2 )$$

in the form $a + b \sqrt { } 2$, where $a$ and $b$ are integers.\\
(ii) Express

$$\sqrt { } 80 + \frac { 30 } { \sqrt { } 5 }$$

in the form $c \sqrt { } 5$, where $c$ is an integer.\\

\hfill \mbox{\textit{Edexcel C1 2013 Q3 [6]}}