Edexcel FP2 2010 June — Question 2 5 marks

Exam BoardEdexcel
ModuleFP2 (Further Pure Mathematics 2)
Year2010
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTaylor series
TypeExplicit differential equation series solution
DifficultyChallenging +1.2 This is a standard Further Maths technique requiring successive differentiation of the differential equation to find Taylor coefficients. While it involves multiple steps and careful algebraic manipulation, it follows a well-established algorithmic procedure taught explicitly in FP2. The initial conditions are given directly, making this a methodical rather than insightful problem—harder than average A-level but routine for Further Maths students.
Spec1.07d Second derivatives: d^2y/dx^2 notation1.07e Second derivative: as rate of change of gradient4.08a Maclaurin series: find series for function4.10a General/particular solutions: of differential equations

2. The displacement \(x\) metres of a particle at time \(t\) seconds is given by the differential equation $$\frac { \mathrm { d } ^ { 2 } x } { \mathrm {~d} t ^ { 2 } } + x + \cos x = 0$$ When \(t = 0 , x = 0\) and \(\frac { \mathrm { d } x } { \mathrm {~d} t } = \frac { 1 } { 2 }\).
Find a Taylor series solution for \(x\) in ascending powers of \(t\), up to and including the term in \(t ^ { 3 }\).

Question 2:
AnswerMarks Guidance
AnswerMarks Guidance
\(f''(t) = -x - \cos x\), \(\quad f''(0) = -1\)B1
\(f'''(t) = (-1 + \sin x)\frac{dx}{dt}\), \(\quad f'''(0) = -0.5\)M1 A1
\(f(t) = f(0) + tf'(0) + \frac{t^2}{2}f''(0) + \frac{t^3}{3!}f'''(0) + \ldots\)M1 A1
\(= 0.5t - 0.5t^2 - \frac{1}{12}t^3 + \ldots\) (5 marks)
## Question 2:

| Answer | Marks | Guidance |
|--------|-------|----------|
| $f''(t) = -x - \cos x$, $\quad f''(0) = -1$ | B1 | |
| $f'''(t) = (-1 + \sin x)\frac{dx}{dt}$, $\quad f'''(0) = -0.5$ | M1 A1 | |
| $f(t) = f(0) + tf'(0) + \frac{t^2}{2}f''(0) + \frac{t^3}{3!}f'''(0) + \ldots$ | M1 A1 | |
| $= 0.5t - 0.5t^2 - \frac{1}{12}t^3 + \ldots$ | | (5 marks) |

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2. The displacement $x$ metres of a particle at time $t$ seconds is given by the differential equation

$$\frac { \mathrm { d } ^ { 2 } x } { \mathrm {~d} t ^ { 2 } } + x + \cos x = 0$$

When $t = 0 , x = 0$ and $\frac { \mathrm { d } x } { \mathrm {~d} t } = \frac { 1 } { 2 }$.\\
Find a Taylor series solution for $x$ in ascending powers of $t$, up to and including the term in $t ^ { 3 }$.\\

\hfill \mbox{\textit{Edexcel FP2 2010 Q2 [5]}}