| Exam Board | Edexcel |
|---|---|
| Module | FP2 (Further Pure Mathematics 2) |
| Year | 2004 |
| Session | June |
| Marks | 11 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Modulus function |
| Type | Sketch modulus functions involving quadratic or other non-linear |
| Difficulty | Standard +0.3 This is a standard Further Maths modulus question requiring sketching a quadratic with modulus, solving equations by cases, and interpreting graphically for an inequality. While it involves multiple steps (11 marks total), the techniques are routine for FP2: sketch the parabola then reflect negative parts, split into two cases based on where (x-2)(x-4) is positive/negative, solve resulting quadratics, and read off the inequality solution from the graph. No novel insight required, just systematic application of standard modulus methods. |
| Spec | 1.02l Modulus function: notation, relations, equations and inequalities1.02s Modulus graphs: sketch graph of |ax+b| |
I don't see any mark scheme content in your message. You've provided "Question 3: 3" but there's no actual marking scheme text to clean up.
Please provide the extracted mark scheme content you'd like me to format, and I'll convert it to clean LaTeX notation while preserving all marking annotations and guidance notes.3. (a) Sketch, on the same axes, the graph of $y = | ( x - 2 ) ( x - 4 ) |$, and the line with equation $y = 6 - 2 x$.\\
(b) Find the exact values of $x$ for which $| ( x - 2 ) ( x - 4 ) | = 6 - 2 x$.\\
(c) Hence solve the inequality $| ( x - 2 ) ( x - 4 ) | < 6 - 2 x$.\\
(2)(Total 11 marks)\\
\hfill \mbox{\textit{Edexcel FP2 2004 Q3 [11]}}