CAIE P1 2016 November — Question 8 8 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2016
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComposite & Inverse Functions
TypeFind composite function expression
DifficultyModerate -0.3 This is a straightforward composite and inverse function question requiring standard techniques: substituting one function into another, simplifying algebraic fractions, finding an inverse by swapping x and y, and determining domain/range from the given constraints. All steps are routine for P1 level with no novel problem-solving required, making it slightly easier than average.
Spec1.02u Functions: definition and vocabulary (domain, range, mapping)1.02v Inverse and composite functions: graphs and conditions for existence

8 The functions \(f\) and \(g\) are defined by $$\begin{aligned} & \mathrm { f } ( x ) = \frac { 4 } { x } - 2 \quad \text { for } x > 0 \\ & \mathrm {~g} ( x ) = \frac { 4 } { 5 x + 2 } \quad \text { for } x \geqslant 0 \end{aligned}$$
  1. Find and simplify an expression for \(\mathrm { fg } ( x )\) and state the range of fg.
  2. Find an expression for \(\mathrm { g } ^ { - 1 } ( x )\) and find the domain of \(\mathrm { g } ^ { - 1 }\).

Question 8:
Part (i):
AnswerMarks Guidance
\(fg(x) = 5x\)M1A1
Range of \(fg\) is \(y \geqslant 0\) oeB1 [3] Accept \(y > 0\)
Part (ii):
AnswerMarks Guidance
\(y = 4/(5x+2) \Rightarrow x = (4-2y)/5y\) oeM1 Must be a function of \(x\)
\(g^{-1}(x) = (4-2x)/5x\) oeA1
\(0, 2\) with no incorrect inequalityB1,B1
\(0 < x \leqslant 2\) oe, c.a.o.B1 [5]
## Question 8:

### Part (i):
$fg(x) = 5x$ | **M1A1** |
Range of $fg$ is $y \geqslant 0$ oe | **B1** [3] | Accept $y > 0$

### Part (ii):
$y = 4/(5x+2) \Rightarrow x = (4-2y)/5y$ oe | **M1** | Must be a function of $x$
$g^{-1}(x) = (4-2x)/5x$ oe | **A1** |
$0, 2$ with no incorrect inequality | **B1,B1** |
$0 < x \leqslant 2$ oe, c.a.o. | **B1** [5] |

---
8 The functions $f$ and $g$ are defined by

$$\begin{aligned}
& \mathrm { f } ( x ) = \frac { 4 } { x } - 2 \quad \text { for } x > 0 \\
& \mathrm {~g} ( x ) = \frac { 4 } { 5 x + 2 } \quad \text { for } x \geqslant 0
\end{aligned}$$

(i) Find and simplify an expression for $\mathrm { fg } ( x )$ and state the range of fg.\\
(ii) Find an expression for $\mathrm { g } ^ { - 1 } ( x )$ and find the domain of $\mathrm { g } ^ { - 1 }$.

\hfill \mbox{\textit{CAIE P1 2016 Q8 [8]}}