Edexcel F1 2022 June — Question 2 9 marks

Exam BoardEdexcel
ModuleF1 (Further Pure Mathematics 1)
Year2022
SessionJune
Marks9
PaperDownload PDF ↗
TopicNewton-Raphson method
TypeNewton-Raphson with complex derivative required
DifficultyStandard +0.3 This is a straightforward Further Pure 1 question requiring standard differentiation (including negative and fractional powers), one iteration of Newton-Raphson, and linear interpolation. While the derivative involves multiple terms with fractional/negative indices, these are routine A-level techniques. The question is structured with clear guidance through parts (a)-(d), requiring no novel insight—just careful application of standard methods. Slightly above average difficulty due to the algebraic complexity of the derivative, but well within typical Further Maths expectations.
Spec1.07i Differentiate x^n: for rational n and sums1.09a Sign change methods: locate roots1.09d Newton-Raphson method1.09f Trapezium rule: numerical integration

2. $$f ( x ) = 10 - 2 x - \frac { 1 } { 2 \sqrt { x } } - \frac { 1 } { x ^ { 3 } } \quad x > 0$$
  1. Show that the equation \(\mathrm { f } ( x ) = 0\) has a root \(\alpha\) in the interval [0.4, 0.5]
  2. Determine \(\mathrm { f } ^ { \prime } ( x )\).
  3. Using \(x _ { 0 } = 0.5\) as a first approximation to \(\alpha\), apply the Newton-Raphson procedure once to \(\mathrm { f } ( x )\) to find a second approximation to \(\alpha\), giving your answer to 3 decimal places. The equation \(\mathrm { f } ( x ) = 0\) has another root \(\beta\) in the interval [4.8, 4.9]
    [0pt]
  4. Use linear interpolation once on the interval [4.8, 4.9] to find an approximation to \(\beta\), giving your answer to 3 decimal places.

2.

$$f ( x ) = 10 - 2 x - \frac { 1 } { 2 \sqrt { x } } - \frac { 1 } { x ^ { 3 } } \quad x > 0$$
\begin{enumerate}[label=(\alph*)]
\item Show that the equation $\mathrm { f } ( x ) = 0$ has a root $\alpha$ in the interval [0.4, 0.5]
\item Determine $\mathrm { f } ^ { \prime } ( x )$.
\item Using $x _ { 0 } = 0.5$ as a first approximation to $\alpha$, apply the Newton-Raphson procedure once to $\mathrm { f } ( x )$ to find a second approximation to $\alpha$, giving your answer to 3 decimal places.

The equation $\mathrm { f } ( x ) = 0$ has another root $\beta$ in the interval [4.8, 4.9]\\[0pt]
\item Use linear interpolation once on the interval [4.8, 4.9] to find an approximation to $\beta$, giving your answer to 3 decimal places.
\end{enumerate}

\hfill \mbox{\textit{Edexcel F1 2022 Q2 [9]}}