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For a cone with base radius \(r\), height \(h\) and slant height \(l\), the following formulae are given.
Curved surface area, \(S = \pi r l\)
Volume, \(V = \frac { 1 } { 3 } \pi r ^ { 2 } h\)
A container is to be designed in the shape of an inverted cone with no lid. The base radius is \(r \mathrm {~m}\) and the volume is \(V \mathrm {~m} ^ { 3 }\).
The area of the material to be used for the cone is \(4 \pi \mathrm {~m} ^ { 2 }\).
- Show that \(V = \frac { 1 } { 3 } \pi \sqrt { 16 r ^ { 2 } - r ^ { 6 } }\).
- In this question you must show detailed reasoning.
It is given that \(V\) has a maximum value for a certain value of \(r\).
Find the maximum value of \(V\), giving your answer correct to 3 significant figures.