4 The curve sketched below passes through the point \(A ( - 2,0 )\).
\includegraphics[max width=\textwidth, alt={}, center]{889639d6-0a31-4569-8370-1e72291a0c47-3_538_734_365_662}
The curve has equation \(y = 14 - x - x ^ { 4 }\) and the point \(P ( 1,12 )\) lies on the curve.
- Find the gradient of the curve at the point \(P\).
- Hence find the equation of the tangent to the curve at the point \(P\), giving your answer in the form \(y = m x + c\).
- Find \(\int _ { - 2 } ^ { 1 } \left( 14 - x - x ^ { 4 } \right) \mathrm { d } x\).
- Hence find the area of the shaded region bounded by the curve \(y = 14 - x - x ^ { 4 }\) and the line \(A P\).
(2 marks)