4.
\begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{a98d4a7f-1e6d-4294-9b5c-c945e8fbe83e-05_650_1143_223_427}
\captionsetup{labelformat=empty}
\caption{Figure 1}
\end{figure}
Figure 1 shows a sketch of part of the curve with equation \(y = \frac { x } { 1 + \sqrt { } x }\). The finite region \(R\), shown shaded in Figure 1, is bounded by the curve, the \(x\)-axis, the line with equation \(x = 1\) and the line with equation \(x = 4\).
- Complete the table with the value of \(y\) corresponding to \(x = 3\), giving your answer to 4 decimal places.
(1)
| \(x\) | 1 | 2 | 3 | 4 |
| \(y\) | 0.5 | 0.8284 | | 1.3333 |
- Use the trapezium rule, with all the values of \(y\) in the completed table, to obtain an estimate of the area of the region \(R\), giving your answer to 3 decimal places.
- Use the substitution \(u = 1 + \sqrt { } x\), to find, by integrating, the exact area of \(R\).
\begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{a98d4a7f-1e6d-4294-9b5c-c945e8fbe83e-07_743_1568_219_182}
\captionsetup{labelformat=empty}
\caption{Figure 2}
\end{figure}
Figure 2 shows a sketch of part of the curve \(C\) with parametric equations
$$x = 1 - \frac { 1 } { 2 } t , \quad y = 2 ^ { t } - 1$$
The curve crosses the \(y\)-axis at the point \(A\) and crosses the \(x\)-axis at the point \(B\).