The cubic equation
$$2x^3 + 6x^2 - 3x + 12 = 0$$
has roots \(\alpha\), \(\beta\) and \(\gamma\).
Without solving the equation, find the cubic equation whose roots are \((\alpha + 3)\), \((\beta + 3)\) and \((\gamma + 3)\), giving your answer in the form \(pw^3 + qw^2 + rw + s = 0\), where \(p\), \(q\), \(r\) and \(s\) are integers to be found. [5]