7 Fig. 7 shows the graph of \(y = \mathrm { f } ( x )\) for values of \(x\) from 0 to 1 .
\begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{662c2d48-228a-4b94-a4b4-cdd31634ef21-6_693_673_390_696}
\captionsetup{labelformat=empty}
\caption{Fig. 7}
\end{figure}
The following spreadsheet printout shows estimates of \(\int _ { 0 } ^ { 1 } f ( x ) d x\) found using the midpoint and trapezium rules for different values of \(h\), the strip width.
| A | A | B | C |
| 1 | \(h\) | Midpoint | Trapezium |
| 2 | 1 | 1.99851742 | 1.751283839 |
| 3 | 0.5 | 1.9638591 | 1.874900631 |
| 4 | 0.25 | 1.95135259 | 1.919379864 |
| 5 | 0.125 | 1.94682102 | 1.935366229 |
- Without doing any further calculation, write down the smallest possible interval which contains the value of the integral. Justify your answer.
- (A) - Calculate the ratio of differences, \(r\), for the sequence of estimates calculated using the trapezium rule.
- Hence suggest a value for \(r\) correct to 2 significant figures.
- Comment on your suggested value for \(r\).
(B) - Use extrapolation to find an improved approximation to the value of the integral. - State the value of the integral to two decimal places.
- Explain why this precision is secure.
Using a similar approach with the sequence of estimates calculated using the midpoint rule, the approximation to the integral from extrapolation was found to be 1.94427 correct to 5 decimal places. - Andrea uses the extrapolated midpoint rule value and the value found in part (ii) ( \(B\) ) to write down an interval which contains the value of the integral. Comment on the validity of Andrea's method.
- Use the values from the spreadsheet output to calculate an approximation to the integral using Simpson's rule with \(h = 0.125\). Give your answer to 5 decimal places.
Approximations to the integral using Simpson's rule are given in the spreadsheet output below. The number of applications of Simpson's rule is given in column N.
| N | O | P | Q |
| \(n\) | Simpson | differences | ratio |
| 1 | 1.91610623 | 0.01810005 | 0.3584931 |
| 2 | 1.93420628 | 0.00648874 | 0.3556525 |
| 4 | 1.94069502 | 0.00230774 | 0.3544828 |
| 8 | 1.94300275 | 0.00081805 | 0.3539885 |
| 16 | 1.94382081 | 0.00028958 | 0.3537638 |
| 32 | 1.94411039 | 0.00010244 | 0.3536568 |
| 64 | 1.94421283 | \(3.623 \mathrm { E } - 05\) | |
| 128 | 1.94424906 | | |
| | | |
- Use the spreadsheet output to find the value of the integral as accurately as possible. Justify the precision quoted.
\section*{END OF QUESTION PAPER}
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