7.
\begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{0da9cd5b-6f6f-4607-bd4f-c8ae164466ae-24_721_1367_280_349}
\captionsetup{labelformat=empty}
\caption{Figure 2}
\end{figure}
A small smooth snooker ball is projected from the corner \(A\) of a horizontal rectangular snooker table \(A B C D\).
The ball is projected so it first hits the side \(D C\) at the point \(P\), then hits the side \(C B\) at the point \(Q\) and then returns to \(A\).
Angle \(A P D = \alpha\), Angle \(Q P C = \beta\), Angle \(A Q B = \gamma\)
The ball moves along \(A P\) with speed \(U\), along \(P Q\) with speed \(V\) and along \(Q A\) with speed \(W\), as shown in Figure 2.
The coefficient of restitution between the ball and side \(D C\) is \(e _ { 1 }\)
The coefficient of restitution between the ball and side \(C B\) is \(e _ { 2 }\)
The ball is modelled as a particle.
\section*{Use the model to answer all parts of this question.}
- Show that \(\tan \beta = e _ { 1 } \tan \alpha\)
- Hence show that \(e _ { 1 } \tan \alpha = e _ { 2 } \cot \gamma\)
- By considering (angle \(A P Q\) + angle \(A Q P\) ) or otherwise, show that it would be possible for the ball to return to \(A\) only if \(e _ { 2 } > e _ { 1 }\)
If instead \(e _ { 1 } = e _ { 2 }\), the ball would not return to \(A\).
Given that \(e _ { 1 } = e _ { 2 }\) - use the result from part (b) to describe the path of the ball after it hits \(C B\) at \(Q\), explaining your answer.