Linear transformation of normal

Work with a linear function of a normal variable (e.g., cost = price × quantity) to find the distribution and probabilities of the transformed variable.

6 questions · Moderate -0.5

2.04e Normal distribution: as model N(mu, sigma^2)2.04f Find normal probabilities: Z transformation
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OCR MEI S3 2011 January Q1
19 marks Standard +0.3
1 Each month the amount of electricity, measured in kilowatt-hours ( kWh ), used by a particular household is Normally distributed with mean 406 and standard deviation 12.
  1. Find the probability that, in a randomly chosen month, less than 420 kWh is used. The charge for electricity used is 14.6 pence per kWh .
  2. Write down the distribution of the total charge for the amount of electricity used in any one month. Hence find the probability that, in a randomly chosen month, the total charge is more than \(\pounds 60\).
  3. The household receives a bill every three months. Assume that successive months may be regarded as independent of each other. Find the value of \(b\) such that the probability that a randomly chosen bill is less than \(\pounds b\) is 0.99 . In a different household, the amount of electricity used per month was Normally distributed with mean 432 kWh . This household buys a new washing machine that is claimed to be cheaper to run than the old one. Over the next six months the amounts of electricity used, in kWh , are as follows. $$\begin{array} { l l l l l l } 404 & 433 & 420 & 423 & 413 & 440 \end{array}$$
  4. Treating this as a random sample, carry out an appropriate test, with a \(5 \%\) significance level, to see if there is any evidence to suggest that the amount of electricity used per month by this household has decreased on average.
CAIE FP2 2010 June Q6
5 marks Moderate -0.3
6 The lifetime, \(X\) days, of a particular insect is such that \(\log _ { 10 } X\) has a normal distribution with mean 1.5 and standard deviation 0.2. Find the median lifetime. Find also \(\mathrm { P } ( X \geq 50 )\).
AQA S1 2012 January Q3
12 marks Moderate -0.8
3 During June 2011, the volume, \(X\) litres, of unleaded petrol purchased per visit at a supermarket's filling station by private-car customers could be modelled by a normal distribution with a mean of 32 and a standard deviation of 10 .
  1. Determine:
    1. \(\mathrm { P } ( X < 40 )\);
    2. \(\mathrm { P } ( X > 25 )\);
    3. \(\mathrm { P } ( 25 < X < 40 )\).
  2. Given that during June 2011 unleaded petrol cost \(\pounds 1.34\) per litre, calculate the probability that the unleaded petrol bill for a visit during June 2011 by a private-car customer exceeded \(\pounds 65\).
  3. Give two reasons, in context, why the model \(\mathrm { N } \left( 32,10 ^ { 2 } \right)\) is unlikely to be valid for a visit by any customer purchasing fuel at this filling station during June 2011.
    (2 marks)
CAIE FP2 2010 June Q6
5 marks Standard +0.3
The lifetime, \(X\) days, of a particular insect is such that \(\log_{10} X\) has a normal distribution with mean \(1.5\) and standard deviation \(0.2\). Find the median lifetime. [3] Find also P\((X \geqslant 50)\). [2]
AQA Paper 3 2022 June Q11
1 marks Easy -1.8
\(X \sim \text{N}(14, 0.35)\) Find the standard deviation of \(X\), correct to two decimal places. Circle your answer. [1 mark] 0.12 \quad\quad 0.35 \quad\quad 0.59 \quad\quad 1.78
OCR MEI Paper 2 Specimen Q6
4 marks Moderate -0.8
Each day, for many years, the maximum temperature in degrees Celsius at a particular location is recorded. The maximum temperatures for days in October can be modelled by a Normal distribution. The appropriate Normal curve is shown in Fig. 6. \includegraphics{figure_6}
    1. Use the model to write down the mean of the maximum temperatures. [1]
    2. Explain why the curve indicates that the standard deviation is approximately 3 degrees Celsius. [1]
Temperatures can be converted from Celsius to Fahrenheit using the formula \(F = 1.8C + 32\), where \(F\) is the temperature in degrees Fahrenheit and \(C\) is the temperature in degrees Celsius.
  1. For maximum temperature in October in degrees Fahrenheit, estimate
    [2]