Symmetric properties of normal

Use symmetry of the normal distribution about its mean to deduce probabilities without calculation (e.g., if P(X > μ+a) is given, find P(X < μ-a)).

7 questions · Moderate -0.3

2.04e Normal distribution: as model N(mu, sigma^2)2.04f Find normal probabilities: Z transformation
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CAIE S1 2014 November Q6
10 marks Moderate -0.3
6 A farmer finds that the weights of sheep on his farm have a normal distribution with mean 66.4 kg and standard deviation 5.6 kg .
  1. 250 sheep are chosen at random. Estimate the number of sheep which have a weight of between 70 kg and 72.5 kg .
  2. The proportion of sheep weighing less than 59.2 kg is equal to the proportion weighing more than \(y \mathrm {~kg}\). Find the value of \(y\). Another farmer finds that the weights of sheep on his farm have a normal distribution with mean \(\mu \mathrm { kg }\) and standard deviation 4.92 kg . 25\% of these sheep weigh more than 67.5 kg .
  3. Find the value of \(\mu\).
Edexcel S1 2016 October Q1
5 marks Moderate -0.8
  1. The random variable \(X \sim \mathrm {~N} \left( \mu , \sigma ^ { 2 } \right)\)
Given that \(\mathrm { P } ( X > \mu + a ) = 0.35\) where \(a\) is a constant, find
  1. \(\mathrm { P } ( X > \mu - a )\)
  2. \(\mathrm { P } ( \mu - a < X < \mu + a )\)
  3. \(\mathrm { P } ( X < \mu + a \mid X > \mu - a )\)
Edexcel S1 2005 January Q7
13 marks Standard +0.3
7. The random variable \(X\) is normally distributed with mean 79 and variance 144 . Find
  1. \(\mathrm { P } ( X < 70 )\),
  2. \(\mathrm { P } ( 64 < X < 96 )\). It is known that \(\mathrm { P } ( 79 - a \leq X \leq 79 + b ) = 0.6463\). This information is shown in the figure below. \includegraphics[max width=\textwidth, alt={}, center]{df898ff4-c3ef-400c-b4f7-f4df3757941d-6_581_983_818_590} Given that \(\mathrm { P } ( X \geq 79 + b ) = 2 \mathrm { P } ( X \leq 79 - a )\),
  3. show that the area of the shaded region is 0.1179 .
  4. Find the value of \(b\).
Edexcel S1 2018 June Q3
5 marks Moderate -0.8
3. The random variable \(Y\) has a normal distribution with mean \(\mu\) and standard deviation \(\sigma\) The \(\mathrm { P } ( Y > 17 ) = 0.4\) Find
  1. \(\mathrm { P } ( \mu < Y < 17 )\)
  2. \(\mathrm { P } ( \mu - \sigma < Y < 17 )\)
OCR MEI Paper 2 2019 June Q15
6 marks Challenging +1.2
15 You must show detailed reasoning in this question. The screenshot in Fig. 15 shows the probability distribution for the continuous random variable \(X\), where \(X \sim \mathrm {~N} \left( \mu , \sigma ^ { 2 } \right)\). \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{95eb3bcc-6d3c-4f7e-9b27-5e046ab57ec5-11_387_954_1599_260} \captionsetup{labelformat=empty} \caption{Fig. 15}
\end{figure} The distribution is symmetrical about the line \(x = 35\) and there is a point of inflection at \(x = 31\).
Fifty independent readings of \(X\) are made. Show that the probability that at least 45 of these readings are between 30 and 40 is less than 0.05 .
OCR H240/02 2018 March Q8
9 marks Standard +0.3
8 The masses, \(X\) grams, of tomatoes are normally distributed. Half of the tomatoes have masses greater than 56.0 g and \(70 \%\) of the tomatoes have masses greater than 53.0 g .
  1. Find the percentage of tomatoes with masses greater than 59.0 g .
  2. Find the percentage of tomatoes with masses greater than 65.0 g .
  3. Given that \(\mathrm { P } ( a < X < 50 ) = 0.1\), find \(a\).
OCR MEI Paper 2 2022 June Q6
2 marks Easy -1.8
\(X\) is a continuous random variable such that \(X \sim N(\mu, \sigma^2)\). On the sketch of this Normal distribution in the Printed Answer Booklet, shade the area bounded by the curve, the \(x\)-axis and the lines \(x = \mu \pm \sigma\). [2]