A technician is trying to estimate the area \(\mu^2\) of a metal square. The independent random variables \(X_1\) and \(X_2\) are each distributed \(\text{N}(\mu, \sigma^2)\) and represent two measurements of the sides of the square. Two estimators of the area, \(A_1\) and \(A_2\), are proposed where
$$A_1 = X_1X_2 \text{ and } A_2 = \left(\frac{X_1 + X_2}{2}\right)^2.$$
[You may assume that if \(X_1\) and \(X_2\) are independent random variables then
$$\text{E}(X_1X_2) = \text{E}(X_1)\text{E}(X_2)$$]
- Find \(\text{E}(A_1)\) and show that \(\text{E}(A_2) = \mu^2 + \frac{\sigma^2}{2}\).
[4]
- Find the bias of each of these estimators.
[2]
The technician is told that \(\text{Var}(A_1) = \sigma^4 + 2\mu^2\sigma^2\) and \(\text{Var}(A_2) = \frac{1}{2}\sigma^4 + 2\mu^2\sigma^2\). The technician decided to use \(A_1\) as the estimator for \(\mu^2\).
- Suggest a possible reason for this decision.
[1]
A statistician suggests taking a random sample of \(n\) measurements of sides of the square and finding the mean \(\overline{X}\). He knows that \(\text{E}(\overline{X}^2) = \mu^2 + \frac{\sigma^2}{n}\) and
$$\text{Var}(\overline{X}^2) = \frac{2\sigma^4}{n^2} + \frac{4\sigma^2\mu^2}{n}.$$
- Explain whether or not \(\overline{X}^2\) is a consistent estimator of \(\mu^2\).
[3]