\includegraphics{figure_10}
A hollow sphere has centre O and internal radius \(r\). A bowl is formed by removing part of the sphere. The bowl is fixed to a horizontal floor, with its circular rim horizontal and the centre of the rim vertically above O.
The point A lies on the rim of the bowl such that AO makes an angle of \(30°\) with the horizontal (see diagram).
A particle P of mass \(m\) is projected from A, with speed \(u\), where \(u > \sqrt{\frac{gr}{2}}\), in a direction perpendicular to AO and moves on the smooth inner surface of the bowl.
The motion of P takes place in the vertical plane containing O and A. The particle P passes through a point B on the inner surface, where OB makes an acute angle \(\theta\) with the vertical.
- Determine, in terms of \(m\), \(g\), \(u\), \(r\) and \(\theta\), the magnitude of the force exerted on P by the bowl when P is at B. [7]
The difference between the magnitudes of the force exerted on P by the bowl when P is at points A and B is \(4mg\).
- Determine, in terms of \(r\), the vertical distance of B above the floor. [4]
It is given that when P leaves the inner surface of the bowl it does not fall back into the bowl.
- Show that \(u^2 > 2gr\). [5]