5.03a Continuous random variables: pdf and cdf

617 questions

Sort by: Default | Easiest first | Hardest first
Edexcel S2 Q7
17 marks Standard +0.3
7. The fraction of sky covered by cloud is modelled by the random variable \(X\) with probability density function $$\begin{array} { l l } \mathrm { f } ( x ) = 0 & x < 0 \\ \mathrm { f } ( x ) = k x ^ { 2 } ( 1 - x ) & 0 \leq x \leq 1 , \\ \mathrm { f } ( x ) = 0 & x > 1 . \end{array}$$
  1. Find \(k\) and sketch the graph of \(\mathrm { f } ( x )\).
  2. Find the mean and the variance of \(X\).
  3. Find the cumulative distribution function \(\mathrm { F } ( x )\).
  4. Given that flying is prohibited when \(85 \%\) of the sky is covered by cloud, show that cloud conditions allow flying nearly \(90 \%\) of the time.
Edexcel S2 Q1
7 marks Moderate -0.3
  1. The continuous random variable \(X\) has the following cumulative distribution function:
$$F ( x ) = \begin{cases} 0 , & x < 2 \\ k \left( 19 x - x ^ { 2 } - 34 \right) , & 2 \leq x \leq 5 \\ 1 , & x > 5 \end{cases}$$
  1. Show that \(k = \frac { 1 } { 36 }\).
  2. Find \(\mathrm { P } ( X > 4 )\).
  3. Find and specify fully the probability density function \(\mathrm { f } ( x )\) of \(X\).
Edexcel S2 Q5
10 marks Moderate -0.3
5. In a party game, a bottle is spun and whoever it points to when it stops has to play next. The acute angle, in degrees, that the bottle makes with the side of the room is modelled by a rectangular distribution over the interval [0,90]. Find the probability that on one spin this angle is
  1. between \(25 ^ { \circ }\) and \(38 ^ { \circ }\),
  2. \(45 ^ { \circ }\) to the nearest degree. The bottle is spun ten times.
  3. Find the probability that the acute angle it makes with the side of the room is less than \(10 ^ { \circ }\) more than twice.
Edexcel S2 Q7
18 marks Standard +0.3
7. In a competition at a funfair, participants have to stay on a log being rotated in a pool of water for as long as possible. The length of time, in tens of seconds, that the competitors stay on the log is modelled by the random variable \(T\) with the following probability density function: $$\mathrm { f } ( t ) = \begin{cases} k ( t - 3 ) ^ { 2 } , & 0 \leq t \leq 3 \\ 0 , & \text { otherwise } \end{cases}$$
  1. Show that \(k = \frac { 1 } { 9 }\).
  2. Sketch f \(( t )\) for all values of \(t\).
  3. Show that the mean time that competitors stay on the \(\log\) is 7.5 seconds. When the competition is next run the organisers decide to make it easier at first by spinning the log more slowly and then increasing the speed of rotation. The length of time, in tens of seconds, that the competitors now stay on the log is modelled by the random variable \(S\) with the following probability density function: $$f ( s ) = \begin{cases} \frac { 1 } { 12 } \left( 8 - s ^ { 3 } \right) , & 0 \leq s \leq 2 \\ 0 , & \text { otherwise } \end{cases}$$
  4. Find the change in the mean time that competitors stay on the log.
Edexcel S2 Q3
9 marks Standard +0.3
3. In an old computer game a white square representing a ball appears at random at the top of the playing area, which is 24 cm wide, and moves down the screen. The continuous random variable \(X\) represents the distance, in centimetres, of the dot from the left-hand edge of the screen when it appears. The distribution of \(X\) is rectangular over the interval [4,28].
  1. Find the mean and variance of \(X\).
  2. Find \(\mathrm { P } ( | X - 16 | < 3 )\). During a single game, a player receives 12 "balls".
  3. Find the probability that the ball appears within 3 cm of the middle of the top edge of the playing area more than four times in a single game.
    (3 marks)
Edexcel S2 Q6
19 marks Standard +0.3
6. The continuous random variable \(X\) has the following probability density function: $$f ( x ) = \begin{cases} \frac { 1 } { 16 } x , & 2 \leq x \leq 6 \\ 0 , & \text { otherwise } \end{cases}$$
  1. Sketch \(\mathrm { f } ( x )\) for all values of \(x\).
  2. Find \(\mathrm { E } ( X )\).
  3. Show that \(\operatorname { Var } ( X ) = \frac { 11 } { 9 }\).
  4. Define fully the cumulative distribution function \(\mathrm { F } ( x )\) of \(X\).
  5. Show that the interquartile range of \(X\) is \(2 ( \sqrt { } 7 - \sqrt { 3 } )\). END
Edexcel S4 2006 June Q6
17 marks Standard +0.3
6. \begin{figure}[h]
\captionsetup{labelformat=empty} \caption{Figure 1} \includegraphics[alt={},max width=\textwidth]{f7137ba8-5526-4107-bccd-047de235d7d1-5_392_407_281_852}
\end{figure} Figure 1 shows a square of side \(t\) and area \(t ^ { 2 }\) which lies in the first quadrant with one vertex at the origin. A point \(P\) with coordinates ( \(X , Y\) ) is selected at random inside the square and the coordinates are used to estimate \(t ^ { 2 }\). It is assumed that \(X\) and \(Y\) are independent random variables each having a continuous uniform distribution over the interval \([ 0 , t ]\).
[0pt] [You may assume that \(\mathrm { E } \left( X ^ { n } Y ^ { n } \right) = \mathrm { E } \left( X ^ { n } \right) \mathrm { E } \left( Y ^ { n } \right)\), where \(n\) is a positive integer.]
  1. Use integration to show that \(\mathrm { E } \left( X ^ { n } \right) = \frac { t ^ { n } } { n + 1 }\). The random variable \(S = k X Y\), where \(k\) is a constant, is an unbiased estimator for \(t ^ { 2 }\).
  2. Find the value of \(k\).
  3. Show that \(\operatorname { Var } S = \frac { 7 t ^ { 4 } } { 9 }\). The random variable \(U = q \left( X ^ { 2 } + Y ^ { 2 } \right)\), where \(q\) is a constant, is also an unbiased estimator for \(t ^ { 2 }\).
  4. Show that the value of \(q = \frac { 3 } { 2 }\).
  5. Find Var \(U\).
  6. State, giving a reason, which of \(S\) and \(U\) is the better estimator of \(t ^ { 2 }\). The point \(( 2,3 )\) is selected from inside the square.
  7. Use the estimator chosen in part (f) to find an estimate for the area of the square.
Edexcel S4 2011 June Q6
16 marks Challenging +1.2
  1. A random sample \(X _ { 1 } , X _ { 2 } , \ldots , X _ { n }\) is taken from a population where each of the \(X _ { i }\) have a continuous uniform distribution over the interval \([ 0 , \beta ]\).
    The random variable \(Y = \max \left\{ X _ { 1 } , X _ { 2 } , \ldots , X _ { n } \right\}\).
    The probability density function of \(Y\) is given by
$$f ( y ) = \left\{ \begin{array} { c c } \frac { n } { \beta ^ { n } } y ^ { n - 1 } & 0 \leqslant y \leqslant \beta \\ 0 & \text { otherwise } \end{array} \right.$$
  1. Show that \(\mathrm { E } \left( Y ^ { m } \right) = \frac { n } { n + m } \beta ^ { m }\).
  2. Write down \(\mathrm { E } ( Y )\).
  3. Using your answers to parts (a) and (b), or otherwise, show that $$\operatorname { Var } ( Y ) = \frac { n } { ( n + 1 ) ^ { 2 } ( n + 2 ) } \beta ^ { 2 }$$
  4. State, giving your reasons, whether or not \(Y\) is a consistent estimator of \(\beta\). The random variables \(M = 2 \bar { X }\), where \(\bar { X } = \frac { 1 } { n } \left( X _ { 1 } + X _ { 2 } + \ldots + X _ { n } \right)\), and \(S = k Y\), where \(k\) is a constant, are both unbiased estimators of \(\beta\).
  5. Find the value of \(k\) in terms of \(n\).
  6. State, giving your reasons, which of \(M\) and \(S\) is the better estimator of \(\beta\) in this case. Five observations of \(X\) are: \(\quad \begin{array} { l l l l l } 8.5 & 6.3 & 5.4 & 9.1 & 7.6 \end{array}\)
  7. Calculate the better estimate of \(\beta\).
Edexcel S4 2014 June Q6
19 marks Challenging +1.2
6. Emily is monitoring the level of pollution in a river. Over a period of time she has found that the amount of pollution, \(X\), in a 100 ml sample of river water has a continuous distribution with probability density function \(\mathrm { f } ( x )\) given by $$f ( x ) = \left\{ \begin{array} { c c } \frac { 2 x } { a ^ { 2 } } & 0 \leqslant x \leqslant a \\ 0 & \text { otherwise } \end{array} \right.$$ where \(a\) is a constant. Emily takes a random sample \(X _ { 1 } , X _ { 2 } , X _ { 3 } , \ldots , X _ { n }\) to try to estimate the value of \(a\).
  1. Show that \(\mathrm { E } ( \bar { X } ) = \frac { 2 a } { 3 }\) and \(\operatorname { Var } ( \bar { X } ) = \frac { a ^ { 2 } } { 18 n }\) The random variable \(S = p \bar { X }\), where \(p\) is a constant, is an unbiased estimator of \(a\).
  2. Write down the value of \(p\) and find \(\operatorname { Var } ( S )\). Felix suggests using the statistic \(M = \max \left\{ X _ { 1 } , X _ { 2 } , X _ { 3 } , \ldots , X _ { n } \right\}\) as an estimator of \(a\).
    He calculates \(\mathrm { E } ( M ) = \frac { 2 n } { 2 n + 1 } a\) and \(\operatorname { Var } ( M ) = \frac { n } { ( n + 1 ) ( 2 n + 1 ) ^ { 2 } } a ^ { 2 }\)
  3. State, giving your reasons, whether or not \(M\) is a consistent estimator of \(a\). The random variable \(T = q M\), where \(q\) is a constant, is an unbiased estimator of \(a\).
  4. Write down, in terms of \(n\), the value of \(q\) and find \(\operatorname { Var } ( T )\).
  5. State, giving your reasons, which of \(S\) or \(T\) you would recommend Emily use as an estimator of \(a\). Emily took a sample of 5 values of \(X\) and obtained the following:
    5.3
    4.3 \(\begin{array} { l l } 5.7 & 7.8 \end{array}\) 6.9
  6. Calculate the estimate of \(a\) using your recommended estimator from part (e).
  7. Find the standard error of your estimate, giving your answer to 2 decimal places.
Edexcel S4 2014 June Q6
15 marks Standard +0.3
  1. Explain what is meant by the sampling distribution of an estimator \(T\) of the population parameter \(\theta\).
  2. Explain what you understand by the statement that \(T\) is a biased estimator of \(\theta\). A population has mean \(\mu\) and variance \(\sigma ^ { 2 }\) A random sample \(X _ { 1 } , X _ { 2 } , \ldots , X _ { 10 }\) is taken from this population.
  3. Calculate the bias of each of the following estimators of \(\mu\). $$\begin{aligned} & \hat { \mu } _ { 1 } = \frac { X _ { 3 } + X _ { 5 } + X _ { 7 } } { 3 } \\ & \hat { \mu } _ { 2 } = \frac { 5 X _ { 1 } + 2 X _ { 2 } + X _ { 9 } } { 6 } \\ & \hat { \mu } _ { 3 } = \frac { 3 X _ { 10 } - X _ { 1 } } { 3 } \end{aligned}$$
  4. Find the variance of each of these three estimators.
  5. State, giving a reason, which of these three estimators for \(\mu\) is
    1. the best estimator,
    2. the worst estimator.
Edexcel S4 2016 June Q6
15 marks Challenging +1.2
6. A random sample of size \(n\) is taken from the random variable \(X\), which has a continuous uniform distribution over the interval [ \(0 , a\) ], \(a > 0\) The sample mean is denoted by \(\bar { X }\)
  1. Show that \(Y = 2 \bar { X }\) is an unbiased estimator of \(a\) The maximum value, \(M\), in the sample has probability density function $$f ( m ) = \left\{ \begin{array} { c c } \frac { n m ^ { n - 1 } } { a ^ { n } } & 0 \leqslant m \leqslant a \\ 0 & \text { otherwise } \end{array} \right.$$
  2. Find E(M)
  3. Show that \(\operatorname { Var } ( M ) = \frac { n a ^ { 2 } } { ( n + 2 ) ( n + 1 ) ^ { 2 } }\) The estimator \(S\) is defined by \(S = \frac { n + 1 } { n } M\) Given that \(n > 1\)
  4. state which of \(Y\) or \(S\) is the better estimator for \(a\). Give a reason for your answer.
Edexcel S4 2018 June Q6
19 marks Challenging +1.2
  1. The continuous random variable \(X\) has probability density function \(\mathrm { f } ( x )\)
$$f ( x ) = \left\{ \begin{array} { c c } \frac { x } { 2 \theta ^ { 2 } } & 0 \leqslant x \leqslant 2 \theta \\ 0 & \text { otherwise } \end{array} \right.$$ where \(\theta\) is a constant.
  1. Use integration to show that \(\mathrm { E } \left( X ^ { N } \right) = \frac { 2 ^ { N + 1 } } { N + 2 } \theta ^ { N }\)
  2. Hence
    1. write down an expression for \(\mathrm { E } ( X )\) in terms of \(\theta\)
    2. find \(\operatorname { Var } ( X )\) in terms of \(\theta\) A random sample \(X _ { 1 } , X _ { 2 } , \ldots , X _ { n }\) where \(n \geqslant 2\) is taken to estimate the value of \(\theta\) The random variable \(S _ { 1 } = q \bar { X }\) is an unbiased estimator of \(\theta\)
  3. Write down the value of \(q\) and show that \(S _ { 1 }\) is a consistent estimator of \(\theta\) The continuous random variable \(Y\) is independent of \(X\) and is uniformly distributed over the interval \(\left[ 0 , \frac { 2 \theta } { 3 } \right]\), where \(\theta\) is the same unknown constant as in \(\mathrm { f } ( x )\). The random variable \(S _ { 2 } = a X + b Y\) is an unbiased estimator of \(\theta\) and is based on one observation of \(X\) and one observation of \(Y\).
  4. Find the value of \(a\) and the value of \(b\) for which \(S _ { 2 }\) has minimum variance.
  5. Show that the minimum variance of \(S _ { 2 }\) is \(\frac { \theta ^ { 2 } } { 11 }\)
  6. Explain which of \(S _ { 1 }\) or \(S _ { 2 }\) is the better estimator for \(\theta\)
OCR MEI Further Statistics B AS 2018 June Q3
10 marks Standard +0.3
3 The probability density function of the continuous random variable \(X\) is given by $$\mathrm { f } ( x ) = \begin{cases} c + x & - c \leqslant x \leqslant 0 \\ c - x & 0 \leqslant x \leqslant c \\ 0 & \text { otherwise } \end{cases}$$ where \(c\) is a positive constant.
  1. (A) Sketch the graph of the probability density function.
    (B) Show that \(c = 1\).
  2. Find \(\mathrm { P } \left( X < \frac { 1 } { 4 } \right)\).
  3. Find
OCR MEI Further Statistics B AS 2018 June Q4
15 marks Easy -1.2
4 The random variable \(X\) has a continuous uniform distribution on [ 0,10 ].
  1. Find \(\mathrm { P } ( 3 < X < 6 )\).
  2. Find each of the following.
    Marisa is investigating the sample mean, \(Y\), of 8 independent values of \(X\). She designs a simulation shown in the spreadsheet in Fig. 4.1. Each of the 25 rows below the heading row consists of 8 values of \(X\) together with the value of \(Y\). All of the values in the spreadsheet have been rounded to 2 decimal places. \begin{table}[h]
    1ABCDEFGHIJ
    1\(X _ { 1 }\)\(X _ { 2 }\)\(X _ { 3 }\)\(X _ { 4 }\)\(X _ { 5 }\)\(X _ { 6 }\)\(X _ { 7 }\)\(X _ { 8 }\)\(Y\)
    26.312.453.273.064.161.530.437.993.65
    31.701.527.108.936.442.709.967.835.77
    49.150.524.956.996.523.150.815.354.68
    50.652.717.929.650.504.876.462.674.43
    63.096.113.960.090.184.670.676.203.12
    77.065.841.973.609.361.974.483.474.72
    81.461.575.450.373.767.568.489.124.72
    99.421.854.911.611.948.001.775.344.36
    102.985.322.914.129.161.769.976.885.39
    112.833.443.287.851.000.938.774.034.01
    124.510.595.849.878.653.947.180.235.10
    134.490.693.658.784.968.963.771.434.59
    146.578.084.856.757.920.279.694.046.02
    158.351.098.638.047.232.122.579.595.95
    165.249.536.088.213.617.076.657.636.75
    177.895.503.090.716.475.496.474.955.07
    188.367.272.359.040.582.263.017.905.10
    193.761.019.619.657.899.986.284.346.56
    209.946.843.385.530.268.535.725.125.66
    217.259.100.342.884.662.656.377.635.11
    227.187.145.380.044.096.474.964.234.94
    238.695.044.902.942.004.234.130.974.11
    243.466.330.489.350.231.187.976.374.42
    252.377.267.161.245.262.803.553.844.19
    262.168.307.173.322.961.309.110.314.33
    27
    \captionsetup{labelformat=empty} \caption{Fig. 4.1}
    \end{table}
  3. Use the spreadsheet to estimate \(\mathrm { P } ( 3 < Y < 6 )\).
  4. Explain why it is not surprising that this estimated probability is substantially greater than the value which you calculated in part (i). Marisa wonders whether, even though the sample size is only 8, use of the Central Limit Theorem will provide a good approximation to \(\mathrm { P } ( 3 < Y < 6 )\).
  5. Calculate an estimate of \(\mathrm { P } ( 3 < Y < 6 )\) using the Central Limit Theorem. A Normal probability plot of the 25 simulated values of \(Y\) is shown in Fig. 4.2. \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{0c58d4d7-10e9-473a-888a-b407ec90bf08-5_800_1291_306_386} \captionsetup{labelformat=empty} \caption{Fig. 4.2}
    \end{figure}
  6. Explain what the Normal probability plot suggests about the use of the Central Limit Theorem to approximate \(\mathrm { P } ( 3 < Y < 6 )\). Marisa now decides to use a spreadsheet with 1000 rows below the heading row, rather than the 25 which she used in the initial simulation shown in Fig. 4.1. She uses a counter to count the number of values of \(Y\) between 3 and 6. This value is 808.
  7. Explain whether the value 808 supports the suggestion that the Central Limit Theorem provides a good approximation to \(\mathrm { P } ( 3 < Y < 6 )\). Marisa decides to repeat each of her two simulations many times in order to investigate how variable the probability estimates are in each case.
  8. Explain whether you would expect there to be more, the same or less variability in the probability estimates based on 1000 rows than in the probability estimates based on 25 rows.
OCR MEI Further Statistics B AS 2019 June Q4
12 marks Standard +0.8
4 The cumulative distribution function of the continuous random variable \(X\) is given by \(\mathrm { F } ( x ) = \begin{cases} 0 & x < 0 , \\ k \left( 12 x - x ^ { 2 } \right) & 0 \leqslant x \leqslant 2 , \\ 1 & x > 2 , \end{cases}\) where \(k\) is a constant.
  1. Show that \(k = 0.05\).
  2. Find \(\mathrm { P } ( 1 \leqslant X \leqslant 1.5 )\).
  3. Find the median of \(X\), correct to 3 significant figures.
  4. Find which of the median, mean and mode of \(X\) is the largest of the three measures of central tendency.
OCR MEI Further Statistics B AS 2022 June Q2
6 marks Moderate -0.8
2 The continuous random variable \(X\) has cumulative distribution function given by \(F ( x ) = \begin{cases} 0 & x < a , \\ \frac { x - a } { b - a } & a \leqslant x \leqslant b , \\ 1 & x > b , \end{cases}\) where \(a\) and \(b\) are constants with \(0 < \mathrm { a } < \mathrm { b }\).
  1. Find \(\mathrm { P } \left( \mathrm { X } < \frac { 1 } { 2 } ( \mathrm { a } + \mathrm { b } ) \right)\).
  2. Sketch the graph of the probability density function of \(X\).
  3. Find the variance of \(X\) when \(a = 2\) and \(b = 8\).
OCR MEI Further Statistics B AS 2022 June Q7
9 marks Standard +0.3
7 Many cars have pollen filters to try to remove as much pollen as possible from the passenger compartment. In a test car, the amount of pollen is regularly monitored. The amount of pollen is measured using a scale from 0 to 1 , and is modelled by the continuous random variable \(X\) with probability density function given by \(f ( x ) = \begin{cases} k \left( 5 x ^ { 4 } - 16 x ^ { 2 } + 11 x \right) & 0 \leqslant x \leqslant 1 , \\ 0 & \text { otherwise } , \end{cases}\) where \(k\) is a positive constant.
  1. Show that \(k = \frac { 6 } { 7 }\).
  2. Determine \(\mathrm { P } ( X < \mathrm { E } ( X ) )\).
  3. Verify that the median amount of pollen according to the model lies between 0.417 and 0.418.
OCR MEI Further Statistics B AS 2021 November Q6
11 marks Standard +0.3
6 The probability density function of the continuous random variable \(X\) is given by \(f ( x ) = \begin{cases} 2 ( 1 + a x ) & 0 \leqslant x \leqslant 1 , \\ 0 & \text { otherwise } , \end{cases}\) where \(a\) is a constant.
  1. Show that \(a = - 1\).
  2. Find the cumulative distribution function of \(X\).
  3. Find \(\mathrm { P } ( X < 0.5 )\).
  4. Show that \(\mathrm { E } ( X )\) is greater than the median of \(X\).
OCR MEI Further Statistics B AS Specimen Q2
7 marks Standard +0.3
2 The cumulative distribution function of the continuous random variable, \(Y\), is given below. $$\mathrm { F } ( y ) = \left\{ \begin{array} { c c } 0 & y < 0 \\ \frac { y ^ { 3 } - y ^ { 2 } } { 4 } & 1 \leq y \leq 2 \\ 1 & y > 2 \end{array} \right.$$
  1. Find \(\mathrm { P } ( Y \leq 1.5 )\)
  2. Verify that the median of \(Y\) lies between 1.6 and 1.7.
  3. Find the probability density function of \(Y\).
OCR MEI Further Statistics B AS Specimen Q3
11 marks Standard +0.3
3 At a factory, flour is packed into bags. A model for the mass in grams of flour packed into each bag is \(1500 + X\), where \(X\) is a continuous random variable with probability density function $$f ( x ) = \left\{ \begin{array} { c c } k x ( 6 - x ) & 0 \leq x \leq 6 \\ 0 & \text { elsewhere, } \end{array} \right.$$ where \(k\) is a constant.
  1. Show that \(k = \frac { 1 } { 36 }\).
  2. Find the probability that a randomly selected bag of flour contains 1505 grams of flour or more.
  3. Find
OCR MEI Further Statistics Major 2019 June Q9
15 marks Moderate -0.5
9 Every weekday Jonathan takes an underground train to work. On any weekday the time in minutes that he has to wait at the station for a train is modelled by the continuous uniform distribution over \([ 0,5 ]\).
  1. Find the probability that Jonathan has to wait at least 3 minutes for a train. The total time that Jonathan has to wait on two days is modelled by the continuous random variable \(X\) with probability density function given by \(\mathrm { f } ( x ) = \begin{cases} \frac { 1 } { 25 } x & 0 \leqslant x \leqslant 5 , \\ \frac { 1 } { 25 } ( 10 - x ) & 5 < x \leqslant 10 , \\ 0 & \text { otherwise } . \end{cases}\)
  2. Find the probability that Jonathan has to wait a total of at most 6 minutes on two days. Jonathan's friend suggests that the total waiting time for 5 days, \(T\) minutes, will almost certainly be less than 18 minutes. In order to investigate this suggestion, Jonathan constructs the simulation shown in Fig. 9. All of the numbers in the simulation have been rounded to 2 decimal places. \begin{table}[h]
    ABCDEF
    1MonTueWedThuFriTotal T
    21.784.362.743.884.6417.41
    30.951.304.834.291.8113.18
    44.274.904.571.413.6618.81
    50.800.063.201.760.356.17
    60.034.821.263.530.139.77
    73.884.731.193.751.2914.84
    84.113.544.330.774.5017.25
    93.540.113.852.861.5811.94
    101.871.823.003.531.8312.05
    114.002.984.591.731.7615.06
    121.913.852.081.722.8212.38
    130.104.862.510.522.1710.15
    141.244.260.951.331.789.57
    152.990.693.853.412.4213.36
    164.671.762.133.483.1015.14
    171.941.070.910.633.347.89
    180.112.290.714.210.868.18
    190.434.584.891.862.8414.60
    204.230.882.714.884.2016.91
    213.724.583.114.893.1819.49
    \captionsetup{labelformat=empty} \caption{Fig. 9}
    \end{table}
  3. Use the simulation to estimate \(\mathrm { P } ( T > 18 )\).
  4. Explain how Jonathan could obtain a better estimate. Jonathan thinks that he can use the Central Limit Theorem to provide a very good approximation to the distribution of \(T\).
  5. Find each of the following.
    Jonathan travels to work on 200 days in a year.
  6. Find the probability that the total waiting time for Jonathan in a year is more than 510 minutes.
    [0pt] [3]
OCR MEI Further Statistics Major 2019 June Q10
14 marks Standard +0.8
10 The probability density function of the continuous random variable \(X\) is given by \(f ( x ) = \begin{cases} k x ^ { m } & 0 \leqslant x \leqslant a , \\ 0 & \text { otherwise, } \end{cases}\) where \(a , k\) and \(m\) are positive constants.
  1. Show that \(k = \frac { m + 1 } { a ^ { m + 1 } }\).
  2. Find the cumulative distribution function of \(X\) in terms of \(x , a\) and \(m\).
  3. Given that \(\mathrm { P } \left( \frac { 1 } { 4 } a < X < \frac { 1 } { 2 } a \right) = \frac { 1 } { 10 }\),
    1. show that \(2 p ^ { 2 } - 10 p + 5 = 0\), where \(p = 2 ^ { m }\),
    2. find the value of \(m\). \section*{END OF QUESTION PAPER}
OCR MEI Further Statistics Major 2022 June Q12
14 marks Challenging +1.2
12 The continuous random variable \(X\) has cumulative distribution function given by $$F ( x ) = \begin{cases} 0 & x < 0 \\ k \left( a x - 0.5 x ^ { 2 } \right) & 0 \leqslant x \leqslant a \\ 1 & x > a \end{cases}$$ where \(a\) and \(k\) are positive constants.
  1. Determine the median of \(X\) in terms of \(a\).
  2. Given that \(a = 10\), determine the probability that \(X\) is within one standard deviation of its mean.
OCR MEI Further Statistics Major 2023 June Q8
12 marks Moderate -0.5
8 The random variable \(X\) has a continuous uniform distribution over [0,10].
  1. Find the probability that, if two independent values of \(X\) are taken, one is less than 3 and the other is greater than 3 . The random variable \(T\) denotes the sum of 5 independent values of \(X\).
  2. State the value of \(\mathrm { P } ( T \leqslant 25 )\). The spreadsheet below shows the heading row and the first 20 data rows from a total of 100 data rows of a simulation of the distribution of \(X\). Each of the 100 rows shows a simulation of 5 independent values of \(X\), together with \(T\), the sum of the 5 values. All of the values have been rounded to 2 decimal places. In column I the spreadsheet shows the number of values of \(T\) that are less than or equal to the corresponding values in column H . For example, there are 75 simulated values of \(T\) that are less than or equal to 30 .
    ABcDEFGHI
    1\(\mathrm { X } _ { 1 }\)\(\mathrm { X } _ { 2 }\)\(\mathrm { X } _ { 3 }\)\(\mathrm { X } _ { 4 }\)\(\mathrm { X } _ { 5 }\)TtNumber \(\leqslant \mathrm { t }\)
    23.736.654.930.419.3325.0600
    34.956.584.482.517.2625.7950
    48.104.874.263.830.7921.85101
    56.704.105.101.826.7624.48154
    63.738.388.499.871.3131.792023
    73.224.360.121.349.4918.532548
    89.177.135.474.352.4428.553075
    93.421.936.042.998.8523.243593
    100.980.689.829.837.2828.584099
    115.861.677.774.087.1426.5245100
    129.200.315.825.316.4527.1050100
    137.044.302.060.064.1617.62
    140.315.021.485.371.7713.94
    153.776.041.217.675.0123.69
    161.215.541.901.436.9117.00
    179.271.985.809.379.3435.76
    184.305.662.801.561.1915.51
    197.153.196.895.412.1824.82
    206.186.323.016.499.1231.13
    215.035.995.196.973.5526.73
  3. Use the spreadsheet output to estimate each of the following.
    The random variable \(Y\) is the mean of 100 independent values of \(T\). Determine an estimate of \(\mathrm { P } ( Y > 26 )\).
OCR MEI Further Statistics Major 2023 June Q10
15 marks Challenging +1.2
10 The continuous random variable \(X\) has probability density function given by \(f ( x ) = \begin{cases} \frac { 4 } { 15 } \left( \frac { a } { x ^ { 2 } } + 3 x ^ { 2 } - \frac { 7 } { 2 } \right) & 1 \leqslant x \leqslant 2 , \\ 0 & \text { otherwise, } \end{cases}\) where \(a\) is a positive constant.
  1. Find the cumulative distribution function of \(X\) in terms of \(a\).
  2. Hence or otherwise determine the value of \(a\).
  3. Show that the median value \(m\) of \(X\) satisfies the equation $$8 m ^ { 4 } - 28 m ^ { 2 } + 9 m - 4 = 0 .$$
  4. Verify that the median value of \(X\) is 1.74, correct to \(\mathbf { 2 }\) decimal places.
  5. Find \(\mathrm { E } ( X )\).
  6. Determine the mode of \(X\).