5.02n Sum of Poisson variables: is Poisson

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AQA Further AS Paper 2 Statistics 2019 June Q6
7 marks Standard +0.3
6 A company owns two machines, \(A\) and \(B\), which make toys. Both machines run continuously and independently. Machine \(A\) makes an average of 2 errors per hour.
6
  1. Using a Poisson model, find the probability that the machine makes exactly 5 errors in 4 hours, giving your answer to three significant figures. 6
  2. Machine \(B\) makes an average of 5 errors per hour. Both machines are switched on and run for 1 hour. The company finds the probability that the total number of errors made by machines \(A\) and \(B\) in 1 hour is greater than 8 . If the probability is greater than 0.4 , a new machine will be purchased.
    Using a Poisson model, determine whether or not the toy company will purchase a new machine.
    6
  3. After investigation, the standard deviation of errors made by machine \(A\) is found to be 0.5 errors per hour and the standard deviation of errors made by machine \(B\) is also found to be 0.5 errors per hour. Explain whether or not the use of Poisson models in parts (a) and (b) is appropriate.
AQA Further AS Paper 2 Statistics 2023 June Q6
8 marks Standard +0.3
6 An insurance company models the number of motor claims received in 1 day using a Poisson distribution with mean 65 6
  1. Find the probability that the company receives at most 60 motor claims in 1 day. Give your answer to three decimal places. 6
  2. The company receives motor claims using a telephone line which is open 24 hours a day. Find the probability that the company receives exactly 2 motor claims in 1 hour. Give your answer to three decimal places.
    6
  3. The company models the number of property claims received in 1 day using a Poisson distribution with mean 23 Assume that the number of property claims received is independent of the number of motor claims received. 6 (c) (i) Find the standard deviation of the variable that represents the total number of motor claims and property claims received in 1 day. Give your answer to three significant figures.
    6 (c) (ii) Find the probability that the company receives a total of more than 90 motor claims and property claims in 1 day. Give your answer to three significant figures.
AQA Further Paper 3 Statistics 2021 June Q8
13 marks Challenging +1.2
8 A company records the number of complaints, \(X\), that it receives over 60 months. The summarised results are $$\sum x = 102 \quad \text { and } \quad \sum ( x - \bar { x } ) ^ { 2 } = 103.25$$ 8
  1. Using this data, explain why it may be appropriate to model the number of complaints received by the company per month by a Poisson distribution with mean 1.7
    8
  2. The company also receives enquiries as well as complaints. The number of enquiries received is independent of the number of complaints received. The company models the number of complaints per month with a Poisson distribution with mean 1.7 and the number of enquiries per month with a Poisson distribution with mean 5.2 The company starts selling a new product.
    The company records a total of 3 complaints and enquiries in one randomly chosen month. Investigate if the mean total number of complaints and enquiries received per month has changed following the introduction of the new product, using the \(10 \%\) level of significance.
    8
  3. It is later found that the mean total number of complaints and enquiries received per month is 6.1 Find the power of the test carried out in part (b), giving your answer to four decimal places. \includegraphics[max width=\textwidth, alt={}, center]{3ef4c3fd-cbf0-4ac0-a072-a07d763fd50a-15_2492_1721_217_150}
    \includegraphics[max width=\textwidth, alt={}]{3ef4c3fd-cbf0-4ac0-a072-a07d763fd50a-20_2496_1723_214_148}
AQA Further Paper 3 Statistics 2022 June Q4
5 marks Standard +0.3
4 Daisies and dandelions are the only flowers growing in a field. The number of daisies per square metre in the field has a mean of 16
The number of dandelions per square metre in the field has a mean of 10
The number of daisies per square metre and the number of dandelions per square metre are independent. 4
  1. Using a Poisson model, find the probability that a randomly selected square metre from the field has a total of at least 30 flowers, giving your answer to three decimal places.
    4
  2. A survey of the entire field is taken.
    The standard deviation of the total number of flowers per square metre is 10 State, with a reason, whether the model used in part (a) is valid.
OCR FS1 AS 2021 June Q2
6 marks Moderate -0.8
2 In the manufacture of fibre optical cable (FOC), flaws occur randomly. Whether any point on a cable is flawed is independent of whether any other point is flawed. The number of flaws in 100 m of FOC of standard diameter is denoted by \(X\).
  1. State a further assumption needed for \(X\) to be well modelled by a Poisson distribution. Assume now that \(X\) can be well modelled by the distribution \(\operatorname { Po } ( 0.7 )\).
  2. Find the probability that in 300 m of FOC of standard diameter there are exactly 3 flaws. The number of flaws in 100 m of FOC of a larger diameter has the distribution \(\mathrm { Po } ( 1.6 )\).
  3. Find the probability that in 200 m of FOC of standard diameter and 100 m of FOC of the larger diameter the total number of flaws is at least 4 . Judith believes that mathematical ability and chess-playing ability are related. She asks 20 randomly chosen chess players, with known British Chess Federation (BCF) ratings \(X\), to take a mathematics aptitude test, with scores \(Y\). The results are summarised as follows. $$n = 20 , \Sigma x = 3600 , \Sigma x ^ { 2 } = 660500 , \Sigma y = 1440 , \Sigma y ^ { 2 } = 105280 , \Sigma x y = 260990$$
    1. Calculate the value of Pearson's product-moment correlation coefficient \(r\).
    2. State an assumption needed to be able to carry out a significance test on the value of \(r\).
    3. Assume now that the assumption in part (b) is valid. Test at the \(5 \%\) significance level whether there is evidence that chess players with higher BCF ratings are better at mathematics.
    4. There are two different grading systems for chess players, the BCF system and the international ELO system. The two sets of ratings are related by $$\text { ELO rating } = 8 \times \text { BCF rating } + 650$$ Magnus says that the experiment should have used ELO ratings instead of BCF ratings. Comment on Magnus's suggestion.
    5. Calculate the value of Pearson's product-moment correlation coefficient \(r\).
    6. State an assumption needed to be able to carry out a significance test on the value of \(r\).
    7. Assume now that the assumption in part (b) is valid. Test at the \(5 \%\) significance level whether there is evidence that chess players with higher BCF ratings are better at mathematics.
    8. There are two different grading systems for chess players, the BCF system and the international ELO system. The two sets of ratings are related by $$\mathrm { ELO } \text { rating } = 8 \times \mathrm { BCF } \text { rating } + 650 .$$ Magnus says that the experiment should have used ELO ratings instead of BCF ratings. Comment on Magnus's suggestion. An environmentalist measures the mean concentration, \(c\) milligrams per litre, of a particular chemical in a group of rivers, and the mean mass, \(m\) pounds, of fish of a certain species found in those rivers. The results are given in the table.
      QuestionAnswerMarksAOGuidance
      1(a)\(\begin{aligned}0.25 + 0.36 + x + x ^ { 2 } = 1
      x ^ { 2 } + x - 0.39 = 0
      x = 0.3 \text { (or } - 1.3 \text { ) }
      x \text { cannot be negative }
      \mathrm { E } ( W ) = 2.23
      \mathrm { E } \left( W ^ { 2 } \right) = \Sigma w ^ { 2 } \mathrm { p } ( w ) \quad [ = 5.83 ]
      \text { Subtract } [ \mathrm { E } ( W ) ] ^ { 2 } \text { to get } \mathbf { 0 . 8 5 7 1 } \end{aligned}\)\(\begin{gathered} \text { M1 }
      \text { A1 }
      \text { A1 }
      \text { B1ft }
      \text { B1 }
      \text { M1 }
      \text { A1 }
      { [ 7 ] } \end{gathered}\)
      3.1a
      1.1b
      1.1b
      2.3
      1.1b
      1.1
      2.1
      Equation using \(\Sigma p = 1\)
      Correct simplified quadratic Correctly obtain \(x = 0.3\)
      Explicitly reject other solution
      2.23 or exact equivalent only Use \(\Sigma w ^ { 2 } \mathrm { p } ( w )\)
      Correctly obtain given answer, www
      Can be implied
      Method needed ft on their quadratic Allow for \(\mathrm { E } ( W ) ^ { 2 } = 4.9729\)
      Need 2.23 or 4.9729 and 5.83 or full numerical \(\Sigma w ^ { 2 } \mathrm { p } ( w )\)
      1(b)\(9 \times 0.8571 = 7.7139\)
      B1
      [1]
      1.1bAllow 7.71 or 7.714
      2(a)Flaws must occur at constant average rate (uniform rate)
      B1
      [1]
      1.2
      Context (e.g. "flaws") needed
      Extra answers, e.g. "singly": B0
      Not "constant rate" or "average constant rate".
      2(b)\(\operatorname { Po(2.1)~or~ } e ^ { - \lambda } \frac { \lambda ^ { 3 } } { 3 ! }\)
      M1
      A1
      [2]
      1.1
      1.1b
      Po(2.1) stated or implied, or formula with \(\lambda = 2.1\) stated Awrt 0.189
      2(c)
      Po(3)
      \(1 - \mathrm { P } ( \leq 3 )\)
      M1
      M1
      A1
      [3]
      1.1
      1.1
      1.1b
      \(\operatorname { Po } ( 2 \times 0.7 + 1.6 )\) stated or implied
      Allow \(1 - \mathrm { P } ( \leq 4 ) = 0.1847\), or from wrong \(\lambda\)
      Awrt 0.353
      Or all combinations \(\leq 3\)
      \(1 -\) above, not just \(= 3\)
      QuestionAnswerMarksAOGuidance
      3(a)0.4(00)
      B2
      [2]
      1.1
      1.1b
      SC: if B0, give SC B1 for two of \(S _ { x x } = 12500 , S _ { y y } = 1600 , S _ { x y } = 1790\) and \(S _ { x y } / \sqrt { } \left( S _ { x x } S _ { y y } \right)\)Also allow SC B1 for equivalent methods using Covariance \SDs
      3(b)Data needs to have a bivariate normal distribution
      B1
      [1]
      1.2Needs "bivariate normal" or clear equivalent. Not just "both normally distributed"Allow "scatter diagram forms ellipse"
      3(c)
      \(\mathrm { H } _ { 0 }\) : higher maths scores are not associated with higher BCF grading; \(\mathrm { H } _ { 1 }\) : positively associated
      CV 0.3783
      \(0.400 > 0.3783\) so reject \(\mathrm { H } _ { 0 }\)
      Significant evidence that higher maths scores are associated with higher BCF grading
      B1
      B1
      M1ft
      A1ft
      [4]
      2.5
      1.1b
      2.2b
      3.5a
      Needs context and clearly onetailed \(O R \rho\) used and defined Not "evidence that ..."
      Allow 0.378
      Reject/do not reject \(\mathrm { H } _ { 0 }\)
      Contextualised, not too definite Needn't say "positive" if \(\mathrm { H } _ { 1 } \mathrm { OK }\)
      SC 2-tail: B0; 0.4438, or 0.3783 B1; then M1A0
      \(\mathrm { H } _ { 0 } : \rho = 0 , \mathrm { H } _ { 1 } : \rho > 0\) where \(\rho\) is population pmcc (not \(r\) )
      FT on their \(r\), but not CV
      Not "scores are associated
      ...". FT on their \(r\) only
      3(d)It makes no difference as this is a linear transformation
      B1
      [1]
      2.2aNeed both "unchanged" oe and reason, need "linear" or exact equivalent"oe" includes "their 0.4"
      4(a)Neither
      B1
      [1]
      2.5OENot "neither is independent of the other"
      4(b)\(c = 2.848 - 0.1567 m\)
      B1
      B1
      B1
      [3]
      1.1
      1.1
      1.1
      Correct \(a\), awrt 2.85
      Correct \(b\), awrt 0.157
      Letters correct from correct method
      (If both wrongly rounded, e.g. \(c = 2.84 - 0.156 m\), give B2)
      \(\mathrm { SC } : m\) on \(c\) :
      \(m = 15.65 - 4.832 c\) : B2
      \(y = 15.65 - 4.832 x\) : B1
      \(c = 15.65 - 4.832 m : \mathrm { B } 1\)
      If B0B0, give B1 for correct letters from valid working
      QuestionAnswerMarksAOGuidance
      4(c)\(a\) unchanged, \(b\) multiplied by 2.2 (allow " \(a\) unchanged, \(b\) increases", etc)B1 [1]2.2aoe, e.g. \(c = 2.848 - 0.345 m\); \(m = 7.114 - 2.196 c\)SC: \(m\) on \(c\) in (b): Both divided by 2.2 B1
      4(d)
      Draw approximate line of best fit
      Draw at least one vertical from line to point
      Say that "Best fit" line minimises the sum of squares of these distances
      M1
      M1
      A1
      [3]
      1.1
      2.4
      2.4
      Needs M2 and "minimises" and "sums of squares" oe
      SC: Horizontal(s):
      full marks (indept of (b))
OCR FS1 AS 2021 June Q1
6 marks Standard +0.3
1 On any day, the number of orders received in one randomly chosen hour by an online supplier can be modelled by the distribution \(\mathrm { Po } ( 120 )\).
  1. Find the probability that at least 28 orders are received in a randomly chosen 10 -minute period.
  2. Find the probability that in a randomly chosen 10-minute period on one day and a randomly chosen 10-minute period on the next day a total of at least 56 orders are received.
  3. State a necessary assumption for the validity of your calculation in part (b).
OCR Further Statistics 2021 June Q3
11 marks Standard +0.3
3 The numbers of CD players sold in a shop on three consecutive weekends were 7,6 and 2 . It may be assumed that sales of CD players occur randomly and that nobody buys more than one CD player at a time. The number of CD players sold on a randomly chosen weekend is denoted by \(X\).
  1. How appropriate is the Poisson distribution as a model for \(X\) ? Now assume that a Poisson distribution with mean 5 is an appropriate model for \(X\).
  2. Find
    1. \(\mathrm { P } ( X = 6 )\),
    2. \(\mathrm { P } ( X \geqslant 8 )\). The number of integrated sound systems sold in a weekend at the same shop can be assumed to have the distribution \(\operatorname { Po } ( 7.2 )\).
  3. Find the probability that on a randomly chosen weekend the total number of CD players and integrated sound systems sold is between 10 and 15 inclusive.
  4. State an assumption needed for your answer to part (c) to be valid.
  5. Give a reason why the assumption in part (d) may not be valid in practice.
Pre-U Pre-U 9795/2 2010 June Q9
10 marks Challenging +1.2
9
  1. Two independent discrete random variables \(X\) and \(Y\) follow Poisson distributions with means \(\lambda\) and \(\mu\) respectively. Prove that the discrete random variable \(Z = X + Y\) follows a Poisson distribution with mean \(\lambda + \mu\). A garage has a white limousine and a green limousine for hire. Demands to hire the white limousine occur at a constant mean rate of 3 per week and demands to hire the green limousine occur at a constant mean rate of 2 per week. Demands for hire are received independently and randomly.
  2. Calculate the probability that in a period of two weeks
    1. no demands for hire are received, giving your answer to 3 significant figures,
    2. seven demands for hire are received.
    3. Find the least value of \(n\) such that the probability of at least \(n\) demands for hire in a period of three weeks is less than 0.005 .
Pre-U Pre-U 9795/2 2012 June Q4
10 marks Challenging +1.3
4
  1. The random variable \(X\) has the distribution \(\operatorname { Po } ( \lambda )\). Prove that the probability generating function, \(\mathrm { G } _ { X } ( t )\), is given by $$\mathrm { G } _ { X } ( t ) = \mathrm { e } ^ { \lambda ( t - 1 ) } .$$
  2. The independent random variables \(X\) and \(Y\) have distributions \(\operatorname { Po } ( \lambda )\) and \(\operatorname { Po } ( \mu )\) respectively. Use probability generating functions to show that the distribution of \(X + Y\) is \(\operatorname { Po } ( \lambda + \mu )\).
  3. Given that \(X \sim \operatorname { Po } ( 1.5 )\) and \(Y \sim \operatorname { Po } ( 2.5 )\), find \(\mathrm { P } ( X \leqslant 2 \mid X + Y = 4 )\).
Pre-U Pre-U 9795/2 2015 June Q4
11 marks Challenging +1.2
4
  1. (a) Derive the moment generating function for a Poisson distribution with mean \(\lambda\).
    (b) The independent random variables \(X\) and \(Y\) are such that \(X \sim \operatorname { Po } ( \mu )\) and \(Y \sim \operatorname { Po } ( v )\). Use moment generating functions to show that \(( X + Y ) \sim \operatorname { Po } ( \mu + v )\).
  2. The number of goals scored per match by Camford Academicals FC may be modelled by a Poisson distribution with mean 2. The number of goals scored against Camford during a match may be modelled by an independent Poisson distribution with mean \(k\). The probability that no goals are scored, by either side, in a match involving Camford is 0.045 . Find
    (a) the value of \(k\),
    (b) the probability that exactly 3 goals are scored against Camford in a match,
    (c) the probability that the total number of goals scored, in a match involving Camford, is between 2 and 5 inclusive.
Pre-U Pre-U 9795/2 2016 June Q4
7 marks Standard +0.3
4 In a Football League match, the number of goals scored by the home team can be modelled by the distribution \(\mathrm { Po } ( 2.4 )\). The number of goals scored by the away team can be modelled by the distribution Po(1.8).
  1. State a necessary assumption for the total number of goals scored in one match to be modelled by the distribution \(\operatorname { Po } ( 4.2 )\).
  2. Assume now that this assumption holds.
    1. Write down an expression for the probability that the total number of goals scored in \(n\) randomly chosen games is less than 4 .
    2. Find the probability that the result of a randomly chosen game is either 0-0 or 1-1.
Pre-U Pre-U 9795/2 2016 Specimen Q4
10 marks Challenging +1.2
4
  1. The random variable \(X\) has the distribution \(\operatorname { Po } ( \lambda )\). Prove that the probability generating function, \(\mathrm { G } _ { X } ( t )\), is given by $$\mathrm { G } _ { X } ( t ) = \mathrm { e } ^ { \lambda ( t - 1 ) }$$
  2. The independent random variables \(X\) and \(Y\) have distributions \(\operatorname { Po } ( \lambda )\) and \(\operatorname { Po } ( \mu )\) respectively. Use probability generating functions to show that the distribution of \(X + Y\) is \(\operatorname { Po } ( \lambda + \mu )\).
  3. Given that \(X \sim \operatorname { Po } ( 1.5 )\) and \(Y \sim \operatorname { Po } ( 2.5 )\), find \(\mathrm { P } ( X \leqslant 2 \mid X + Y = 4 )\).
Pre-U Pre-U 9795/2 2018 June Q1
Moderate -0.3
1
  1. The random variable \(X\) has the distribution \(\mathrm { B } ( 200,0.2 )\). Use a suitable approximation to find \(\mathrm { P } ( X \leqslant 30 )\).
  2. The random variable \(Y\) has the distribution \(\mathrm { B } ( 200,0.02 )\). Use a suitable approximation to find \(\mathrm { P } ( Y \leqslant 3 )\).
Pre-U Pre-U 9795/2 2018 June Q2
Moderate -0.8
2 Secret radio messages received under difficult conditions are subject to errors caused by random instantaneous breaks in transmission. The number of errors caused by breaks in transmission in a 10-minute period is denoted by \(B\).
  1. State two conditions, other than randomness, needed for a Poisson distribution to be a suitable model for \(B\). Assume now that \(B \sim \mathrm { Po } ( 5 )\).
  2. Calculate the probability that in a 15-minute period there are between 6 and 10 errors, inclusive, caused by random breaks in transmission. Secret radio messages are also subject to errors caused by mistakes made by the sender. The number of errors caused by mistakes made by the sender in a 10 -minute period, \(M\), has the independent distribution \(\operatorname { Po } ( 8 )\).
  3. Calculate the period of time, in seconds, for which the probability that a message contains no errors of either sort is 0.6 .
Pre-U Pre-U 9795/2 2019 Specimen Q2
5 marks Standard +0.3
2
  1. The probability that a shopper obtains a parking space on the river embankment on any given Saturday morning is 0.2 . Using a suitable normal approximation, find the probability that, over a period of 100 Saturday mornings, the shopper finds a parking space at least 15 times. Justify the use of the normal approximation in this case.
  2. The number of parking tickets that a traffic warden issues on the river embankment during the course of a week has a Poisson distribution with mean 36 . The probability that the traffic warden issues more than \(N\) parking tickets is less than 0.05 . Using a suitable normal approximation, find the least possible value of \(N\).
Pre-U Pre-U 9795/2 Specimen Q10
4 marks Standard +0.3
10
  1. \(X , Y\) and \(Z\) are independent random variables having Poisson distributions with means \(\lambda , \mu\) and \(\lambda + \mu\) respectively. Find \(\mathrm { P } ( X = 0\) and \(Y = 2 ) , \mathrm { P } ( X = 1\) and \(Y = 1 )\) and \(\mathrm { P } ( X = 2\) and \(Y = 0 )\). Hence verify that \(\mathrm { P } ( X + Y = 2 ) = \mathrm { P } ( Z = 2 )\).
  2. In an office the male absence rate, i.e. the number of working days lost each month due to the absence of male employees, has a Poisson distribution with mean 4.5. In the same office the female absence rate has an independent Poisson distribution with mean 4.1. Calculate the probability that
    1. during a particular month both the male absence rate and the female absence rate are equal to 3,
    2. during a particular month the total of the male and female absence rates is equal to 6,
    3. during a particular month the male and female absence rates were each equal to 3 , given that the total of the male and female absence rates was equal to 6 .
CAIE S2 2021 June Q1
4 marks Standard +0.3
Accidents at two factories occur randomly and independently. On average, the numbers of accidents per month are 3.1 at factory \(A\) and 1.7 at factory \(B\). Find the probability that the total number of accidents in the two factories during a 2-month period is more than 3. [4]
CAIE S2 2024 November Q6
9 marks Standard +0.3
The numbers of customers arriving at service desks \(A\) and \(B\) during a \(10\)-minute period have the independent distributions \(\text{Po}(1.8)\) and \(\text{Po}(2.1)\) respectively.
  1. Find the probability that during a randomly chosen \(15\)-minute period more than \(2\) customers will arrive at desk \(A\). [2]
  2. Find the probability that during a randomly chosen \(5\)-minute period the total number of customers arriving at both desks is less than \(4\). [3]
  3. An inspector waits at desk \(B\). She wants to wait long enough to be \(90\%\) certain of seeing at least one customer arrive at the desk. Find the minimum time for which she should wait, giving your answer correct to the nearest minute. [4]
CAIE S2 2011 June Q5
9 marks Standard +0.3
The number of adult customers arriving in a shop during a 5-minute period is modelled by a random variable with distribution \(\text{Po}(6)\). The number of child customers arriving in the same shop during a 10-minute period is modelled by an independent random variable with distribution \(\text{Po}(4.5)\).
  1. Find the probability that during a randomly chosen 2-minute period, the total number of adult and child customers who arrive in the shop is less than 3. [3]
  2. During a sale, the manager claims that more adult customers are arriving than usual. In a randomly selected 30-minute period during the sale, 49 adult customers arrive. Test the manager's claim at the 2.5\% significance level. [6]
CAIE S2 2016 June Q6
9 marks Standard +0.3
\(X\) and \(Y\) are independent random variables with distributions \(\mathrm{Po}(1.6)\) and \(\mathrm{Po}(2.3)\) respectively.
  1. Find \(\mathrm{P}(X + Y = 4)\). [3]
A random sample of 75 values of \(X\) is taken.
  1. State the approximate distribution of the sample mean, \(\overline{X}\), including the values of the parameters. [2]
  2. Hence find the probability that the sample mean is more than 1.7. [3]
  3. Explain whether the Central Limit theorem was needed to answer part (ii). [1]
CAIE S2 2002 November Q5
8 marks Standard +0.3
\(X\) and \(Y\) are independent random variables each having a Poisson distribution. \(X\) has mean 2.5 and \(Y\) has mean 3.1.
  1. Find P\((X + Y > 3)\). [4]
  2. A random sample of 80 values of \(X\) is taken. Find the probability that the sample mean is less than 2.4. [4]
CAIE S2 2011 November Q7
11 marks Standard +0.8
The numbers of men and women who visit a clinic each hour are independent Poisson variables with means 2.4 and 2.8 respectively.
  1. Find the probability that, in a half-hour period,
    1. 2 or more men and 1 or more women will visit the clinic, [4]
    2. a total of 3 or more people will visit the clinic. [3]
  2. Find the probability that, in a 10-hour period, a total of more than 60 people will visit the clinic. [4]
AQA S2 2016 June Q1
13 marks Standard +0.3
The water in a pond contains three different species of a spherical green algae: Volvox globator, at an average rate of 4.5 spheres per 1 cm³; Volvox aureus, at an average rate of 2.3 spheres per 1 cm³; Volvox tertius, at an average rate of 1.2 spheres per 1 cm³. Individual Volvox spheres may be considered to occur randomly and independently of all other Volvox spheres. Random samples of water are collected from this pond. Find the probability that:
  1. a 1 cm³ sample contains no more than 5 Volvox globator spheres; [1 mark]
  2. a 1 cm³ sample contains at least 2 Volvox aureus spheres; [3 marks]
  3. a 5 cm³ sample contains more than 8 but fewer than 12 Volvox tertius spheres; [3 marks]
  4. a 0.1 cm³ sample contains a total of exactly 2 Volvox spheres; [3 marks]
  5. a 1 cm³ sample contains at least 1 sphere of each of the three different species of algae. [3 marks]
OCR S2 2012 January Q2
5 marks Standard +0.3
The random variable \(Y\) has the distribution B(140, 0.03). Use a suitable approximation to find P(\(Y = 5\)). Justify your approximation. [5]
OCR MEI S2 2007 January Q3
18 marks Standard +0.3
An electrical retailer gives customers extended guarantees on washing machines. Under this guarantee all repairs in the first 3 years are free. The retailer records the numbers of free repairs made to 80 machines.
Number of repairs0123\(>3\)
Frequency5320610
  1. Show that the sample mean is 0.4375. [1]
  2. The sample standard deviation \(s\) is 0.6907. Explain why this supports a suggestion that a Poisson distribution may be a suitable model for the distribution of the number of free repairs required by a randomly chosen washing machine. [2]
The random variable \(X\) denotes the number of free repairs required by a randomly chosen washing machine. For the remainder of this question you should assume that \(X\) may be modelled by a Poisson distribution with mean 0.4375.
  1. Find P\((X = 1)\). Comment on your answer in relation to the data in the table. [4]
  2. The manager decides to monitor 8 washing machines sold on one day. Find the probability that there are at least 12 free repairs in total on these 8 machines. You may assume that the 8 machines form an independent random sample. [3]
  3. A launderette with 8 washing machines has needed 12 free repairs. Why does your answer to part (iv) suggest that the Poisson model with mean 0.4375 is unlikely to be a suitable model for free repairs on the machines in the launderette? Give a reason why the model may not be appropriate for the launderette. [3]
The retailer also sells tumble driers with the same guarantee. The number of free repairs on a tumble drier in three years can be modelled by a Poisson distribution with mean 0.15. A customer buys a tumble drier and a washing machine.
  1. Assuming that free repairs are required independently, find the probability that
    1. the two appliances need a total of 3 free repairs between them,
    2. each appliance needs exactly one free repair.
    [5]