Answer only one of the following two alternatives.
EITHER
The curve \(C\) is defined parametrically by
$$x = 18t - t^2 \quad \text{and} \quad y = 8t^{\frac{1}{2}},$$
where \(0 < t \leqslant 4\).
- Show that at all points of \(C\),
$$\frac{\mathrm{d}^2 y}{\mathrm{d}x^2} = \frac{-3(9 + t)}{2t^2(9 - t)^3}.$$ [4]
- Show that the mean value of \(\frac{\mathrm{d}^2 y}{\mathrm{d}x^2}\) with respect to \(x\) over the interval \(0 < x \leqslant 56\) is \(\frac{3}{70}\). [4]
- Find the area of the surface generated when \(C\) is rotated through \(2\pi\) radians about the \(x\)-axis, showing full working. [6]
OR
Let \(I_n = \int_1^{\sqrt{2}} (x^2 - 1)^n \mathrm{d}x\).
- Show that, for \(n \geqslant 1\),
$$(2n + 1)I_n = \sqrt{2} - 2nI_{n-1}.$$ [5]
- Using the substitution \(x = \sec \theta\), show that
$$I_n = \int_0^{\frac{1}{4}\pi} \tan^{2n+1} \theta \sec \theta \, \mathrm{d}\theta.$$ [4]
- Deduce the exact value of
$$\int_0^{\frac{1}{4}\pi} \frac{\sin^7 \theta}{\cos^8 \theta} \, \mathrm{d}\theta.$$ [5]