4.08e Mean value of function: using integral

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AQA Further AS Paper 1 2024 June Q7
3 marks Moderate -0.8
7 The function f is defined by $$f ( x ) = \frac { 1 } { \sqrt { x } } \quad 4 \leq x \leq 7$$ Find the mean value of f over the interval \(4 \leq x \leq 7\) Give your answer in exact form.
AQA Further AS Paper 1 Specimen Q2
1 marks Easy -1.2
2 Find the mean value of \(3 x ^ { 2 }\) over the interval \(1 \leq x \leq 3\) Circle your answer.
[0pt] [1 mark] $$8 \frac { 2 } { 3 } \quad 10 \quad 13 \quad 26$$
AQA Further Paper 2 2022 June Q2
1 marks Easy -1.2
2
3 2 Find the mean value of the function \(\mathrm { f } ( x ) = 10 x ^ { 4 }\) between \(x = 0\) and \(x = a\) Circle your answer.
[0pt] [1 mark] \(10 a ^ { 3 }\) \(40 a ^ { 3 }\) \(2 a ^ { 4 }\) \(4 a ^ { 5 }\)
CAIE FP1 2015 November Q9
Challenging +1.3
9 It is given that \(I _ { n } = \int _ { 1 } ^ { \mathrm { e } } ( \ln x ) ^ { n } \mathrm {~d} x\) for \(n \geqslant 0\). Show that $$I _ { n } = ( n - 1 ) \left[ I _ { n - 2 } - I _ { n - 1 } \right] \text { for } n \geqslant 2$$ Hence find, in an exact form, the mean value of \(( \ln x ) ^ { 3 }\) with respect to \(x\) over the interval \(1 \leqslant x \leqslant \mathrm { e }\).
WJEC Further Unit 6 2024 June Q5
Standard +0.8
  1. The diagram below shows a uniform rod \(A B\) of weight \(W N\) and length \(2 l\), with its lower end \(A\) resting on a rough horizontal floor. A light cable is attached to the other end \(B\). The rod is in equilibrium when it is inclined at an angle of \(\theta\) to the floor, where \(0 ^ { \circ } < \theta \leqslant 45 ^ { \circ }\). The tension in the cable is \(T \mathrm {~N}\) acting at an angle of \(2 \theta\) to the rod, as shown in the diagram. \includegraphics[max width=\textwidth, alt={}, center]{36112cfa-20c4-4ba8-b972-6b7b44e5182f-18_508_1105_559_479}
    1. (i) Show that \(T = \frac { W } { 4 } \operatorname { cosec } \theta\).
      (ii) Hence determine the normal reaction of the floor on the rod at \(A\), giving your answer in terms of \(W\).
    2. Given that the coefficient of friction between the floor and the rod is \(\frac { \sqrt { 3 } } { 3 }\), calculate the minimum possible value for \(\theta\).
    3. The region \(R\), shown in the diagram below, is bounded by the coordinate axes and the curve
    $$y = \frac { a } { b } \sqrt { b ^ { 2 } - x ^ { 2 } }$$ where \(a , b\) are constants. \includegraphics[max width=\textwidth, alt={}, center]{36112cfa-20c4-4ba8-b972-6b7b44e5182f-21_451_1116_644_468} The region \(R\) is rotated through \(360 ^ { \circ }\) about the \(x\)-axis to form a uniform solid \(S\). The volume of \(S\) is \(\frac { 2 } { 3 } \pi a ^ { 2 } b\).
  2. Use integration to show that the distance of the centre of mass of \(S\) from the \(y\)-axis is \(\frac { 3 b } { 8 }\).
    The diagram below shows a small tree growing in a pot. The uniform solid \(S\) described on the previous page may be used to model the part of the tree above the pot. This part of the tree has height \(h \mathrm {~cm}\) and base radius \(\frac { h } { 4 } \mathrm {~cm}\). The pot, including its contents, may be modelled as a solid cylinder of height 50 cm and radius 25 cm . \includegraphics[max width=\textwidth, alt={}, center]{36112cfa-20c4-4ba8-b972-6b7b44e5182f-22_846_839_1596_612} You may assume that the density of the pot, including its contents, is equal to 20 times the density of the part of the tree above the pot.
  3. A gardener suggests that a tree is said to have outgrown its pot if the centre of mass, of both the tree and its pot, lies above the height of the pot. Determine the maximum value of \(h\) before the tree outgrows its pot.
  4. Identify one possible limitation of the model used that could affect your answer to part (b). \section*{END OF PAPER} Additional page, if required. Write the question number(s) in the left-hand margin. \section*{PLEASE DO NOT WRITE ON THIS PAGE} \section*{PLEASE DO NOT WRITE ON THIS PAGE}
Pre-U Pre-U 9794/2 2018 June Q10
10 marks Challenging +1.2
10
  1. By using the substitution \(u = 3 - 2 x\), or otherwise, show that \(\int _ { 0 } ^ { 1 } \left( \frac { 4 x } { 3 - 2 x } \right) ^ { 2 } \mathrm {~d} x = 16 - 12 \ln 3\).
  2. \includegraphics[max width=\textwidth, alt={}, center]{f4b66aaa-16b9-4b15-b3f5-b9657fe98274-4_595_588_927_817} The diagram shows the region \(R\), which is bounded by the curve \(y = \frac { 4 x } { 3 - 2 x }\), the \(y\)-axis and the line \(y = 4\). Find the exact volume generated when the region \(R\) is rotated completely around the \(x\)-axis. {www.cie.org.uk} after the live examination series. }
CAIE FP1 2003 November Q8
11 marks Challenging +1.2
Given that \(z = e^{i\theta}\) and \(n\) is a positive integer, show that $$z^n + \frac{1}{z^n} = 2 \cos n\theta \quad \text{and} \quad z^n - \frac{1}{z^n} = 2i \sin n\theta.$$ [2] Hence express \(\sin^6 \theta\) in the form $$p \cos 6\theta + q \cos 4\theta + r \cos 2\theta + s,$$ where the constants \(p\), \(q\), \(r\), \(s\) are to be determined. [4] Hence find the mean value of \(\sin^6 \theta\) with respect to \(\theta\) over the interval \(0 \leq \theta \leq \frac{1}{4}\pi\). [5]
CAIE FP1 2005 November Q8
9 marks Standard +0.8
Find the coordinates of the centroid of the finite region bounded by the \(x\)-axis and the curve whose equation is $$y = x^2(1 - x).$$ [7] Deduce the coordinates of the centroid of the finite region bounded by the \(x\)-axis and the curve whose equation is $$y = x(1 - x)^2.$$ [2]
CAIE FP1 2015 November Q9
12 marks Challenging +1.3
It is given that \(I_n = \int_{1}^{e} (\ln x)^n \mathrm{d}x\) for \(n \geqslant 0\). Show that $$I_n = (n - 1)[I_{n-2} - I_{n-1}] \text{ for } n \geqslant 2.$$ [6] Hence find, in an exact form, the mean value of \((\ln x)^3\) with respect to \(x\) over the interval \(1 \leqslant x \leqslant \mathrm{e}\). [6]
CAIE FP1 2018 November Q11
28 marks Challenging +1.3
Answer only one of the following two alternatives. EITHER The curve \(C\) is defined parametrically by $$x = 18t - t^2 \quad \text{and} \quad y = 8t^{\frac{1}{2}},$$ where \(0 < t \leqslant 4\).
  1. Show that at all points of \(C\), $$\frac{\mathrm{d}^2 y}{\mathrm{d}x^2} = \frac{-3(9 + t)}{2t^2(9 - t)^3}.$$ [4]
  2. Show that the mean value of \(\frac{\mathrm{d}^2 y}{\mathrm{d}x^2}\) with respect to \(x\) over the interval \(0 < x \leqslant 56\) is \(\frac{3}{70}\). [4]
  3. Find the area of the surface generated when \(C\) is rotated through \(2\pi\) radians about the \(x\)-axis, showing full working. [6]
OR Let \(I_n = \int_1^{\sqrt{2}} (x^2 - 1)^n \mathrm{d}x\).
  1. Show that, for \(n \geqslant 1\), $$(2n + 1)I_n = \sqrt{2} - 2nI_{n-1}.$$ [5]
  2. Using the substitution \(x = \sec \theta\), show that $$I_n = \int_0^{\frac{1}{4}\pi} \tan^{2n+1} \theta \sec \theta \, \mathrm{d}\theta.$$ [4]
  3. Deduce the exact value of $$\int_0^{\frac{1}{4}\pi} \frac{\sin^7 \theta}{\cos^8 \theta} \, \mathrm{d}\theta.$$ [5]
CAIE FP1 2019 November Q1
6 marks Standard +0.8
The curve \(C\) has equation \(y = x^a\) for \(0 \leqslant x \leqslant 1\), where \(a\) is a positive constant. Find, in terms of \(a\), the coordinates of the centroid of the region enclosed by \(C\), the line \(x = 1\) and the \(x\)-axis. [6]
CAIE FP1 2019 November Q1
6 marks Standard +0.8
The curve \(C\) has equation \(y = x^a\) for \(0 \leq x \leq 1\), where \(a\) is a positive constant. Find, in terms of \(a\), the coordinates of the centroid of the region enclosed by \(C\), the line \(x = 1\) and the \(x\)-axis. [6]
AQA Further AS Paper 1 2020 June Q12
2 marks Standard +0.8
The mean value of the function \(\mathbf{f}\) over the interval \(1 \leq x \leq 5\) is \(m\). The graph of \(y = \mathbf{g}(x)\) is a reflection in the \(x\)-axis of \(y = \mathbf{f}(x)\). The graph of \(y = \mathbf{h}(x)\) is a translation of \(y = \mathbf{g}(x)\) by \(\begin{bmatrix} 3 \\ 7 \end{bmatrix}\) Determine, in terms of \(m\), the mean value of the function \(\mathbf{h}\) over the interval \(4 \leq x \leq 8\) [2 marks]
AQA Further Paper 1 2019 June Q3
1 marks Moderate -0.8
The function \(f(x) = x^2 - 1\) Find the mean value of \(f(x)\) from \(x = -0.5\) to \(x = 1.7\) Give your answer to three significant figures. Circle your answer. [1 mark] \(-0.521\) \quad \(-0.434\) \quad \(-0.237\) \quad \(0.786\)
AQA Further Paper 1 2024 June Q3
1 marks Easy -1.2
The function f is defined by $$f(x) = x^2 \quad (x \in \mathbb{R})$$ Find the mean value of \(f(x)\) between \(x = 0\) and \(x = 2\) Circle your answer. [1 mark] \(\frac{2}{3}\) \(\frac{4}{3}\) \(\frac{8}{3}\) \(\frac{16}{3}\)
AQA Further Paper 1 2024 June Q15
5 marks Challenging +1.2
A curve is defined parametrically by the equations $$x = \frac{3}{2}t^3 + 5$$ $$y = t^{\frac{3}{2}} \quad (t \geq 0)$$ Show that the arc length of the curve from \(t = 0\) to \(t = 2\) is equal to 26 units. [5 marks]
AQA Further Paper 1 Specimen Q12
3 marks Challenging +1.8
The function \(f(x) = \cosh(ix)\) is defined over the domain \(\{x \in \mathbb{R} : -a\pi \leq x \leq a\pi\}\), where \(a\) is a positive integer. By considering the graph of \(y = [f(x)]^n\), find the mean value of \([f(x)]^n\), when \(n\) is an odd positive integer. Fully justify your answer. [3 marks]
OCR MEI Further Pure Core Specimen Q12
13 marks Standard +0.3
In this question you must show detailed reasoning.
  1. Given that \(y = \arctan x\), show that \(\frac{dy}{dx} = \frac{1}{1+x^2}\). [3]
Fig. 12 shows the curve \(y = \frac{1}{1+x^2}\). \includegraphics{figure_12}
  1. Find, in exact form, the mean value of the function \(f(x) = \frac{1}{1+x^2}\) for \(-1 \leq x \leq 1\). [3]
  2. The region bounded by the curve, the \(x\)-axis, and the lines \(x = 1\) and \(x = -1\) is rotated through \(2\pi\) radians about the \(x\)-axis. Find, in exact form, the volume of the solid of revolution generated. [7]
WJEC Further Unit 4 2019 June Q5
8 marks Standard +0.8
  1. Show that \(\sin \theta - \sin 3\theta\) can be expressed in the form \(a\cos b\theta \sin \theta\), where \(a\), \(b\) are integers whose values are to be determined. [3]
  2. Find the mean value of \(y = 2\cos 2\theta \sin \theta + 7\) between \(\theta = 1\) and \(\theta = 3\), giving your answer correct to two decimal places. [5]
WJEC Further Unit 4 2023 June Q8
11 marks Challenging +1.2
The function \(f\) is defined by $$f(x) = \frac{1}{\sqrt{x^2 + 4x + 3}}.$$
  1. Find the mean value of the function \(f\) for \(0 \leqslant x \leqslant 2\), giving your answer correct to three decimal places. [5]
  2. The region \(R\) is bounded by the curve \(y = f(x)\), the \(x\)-axis and the lines \(x = 0\) and \(x = 2\). Find the exact value of the volume of the solid generated when \(R\) is rotated through four right angles about the \(x\)-axis. [6]
WJEC Further Unit 4 2024 June Q7
12 marks Challenging +1.8
  1. A curve C is defined by the equation \(y = \frac{1}{\sqrt{16-6x-x^2}}\) for \(-3 \leq x \leq 1\).
    1. Find the mean value of \(y = \frac{1}{\sqrt{16-6x-x^2}}\) between \(x = -3\) and \(x = 1\). [4]
    2. The region \(R\) is bounded by the curve C, the \(x\)-axis and the lines \(x = -3\) and \(x = 1\). Find the volume of the solid generated when \(R\) is rotated through four right-angles about the \(x\)-axis. [5]
  2. Evaluate the improper integral $$\int_1^{\infty} \frac{8e^{-2x}}{4e^{-2x} - 5} \mathrm{d}x,$$ giving your answer correct to three decimal places. [3]
SPS SPS FM Pure 2021 May Q7
9 marks Standard +0.3
Given that \(y = \arcsin x\), \(-1 \leqslant x < 1\),
  1. show that \(\frac{dy}{dx} = \frac{1}{\sqrt{1-x^2}}\). [3]
Given that \(f(x) = \frac{3x + 2}{\sqrt{4 - x^2}}\),
  1. show that the mean value of \(f(x)\) over the interval \([0, \sqrt{2}]\), is $$\frac{\pi\sqrt{2}}{4} + A\sqrt{2} - A,$$ where \(A\) is a constant to be determined. [6]
SPS SPS FM Pure 2024 February Q2
2 marks Easy -1.2
Find the mean value of \(f(x) = x^2 + 6x\) over the interval \([0, 3]\). [2]
OCR Further Pure Core 2 2018 March Q5
5 marks Standard +0.8
In this question you must show detailed reasoning. An ant starts from a fixed point \(O\) and walks in a straight line for \(1.5\) s. Its velocity, \(v\) cms\(^{-1}\), can be modelled by \(v = \frac{1}{\sqrt{9-t^2}}\). By finding the mean value of \(v\) in \(0 \leq t \leq 1.5\), deduce the average velocity of the ant. [5]
Pre-U Pre-U 9795/1 2018 June Q12
15 marks Challenging +1.8
The curve \(C\) is given by \(y = \frac{1}{4}x^2 - \frac{1}{2}\ln x\) for \(2 \leq x \leq 8\).
  1. Find, in its simplest exact form, the length of \(C\). [5]
  2. When \(C\) is rotated through \(2\pi\) radians about the \(x\)-axis, a surface of revolution is formed. Show that the area of this surface is \(\pi(270 - 47\ln 2 - 2(\ln 2)^2)\). [10]