4.02n Euler's formula: e^(i*theta) = cos(theta) + i*sin(theta)

117 questions

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OCR FP3 Q8
12 marks Standard +0.8
  1. By expressing \(\sin \theta\) in terms of \(e^{i\theta}\) and \(e^{-i\theta}\), show that $$\sin^6 \theta \equiv \frac{1}{32}(\cos 6\theta - 6\cos 4\theta + 15\cos 2\theta - 10).$$ [5]
  2. Replace \(\theta\) by \(\left(\frac{1}{2}\pi - \theta\right)\) in the identity in part (i) to obtain a similar identity for \(\cos^6 \theta\). [3]
  3. Hence find the exact value of \(\int_0^{2\pi} \left(\sin^6 \theta - \cos^6 \theta\right) d\theta\). [4]
OCR FP3 2008 January Q4
8 marks Standard +0.8
The integrals \(C\) and \(S\) are defined by $$C = \int_0^{3\pi} e^{3x} \cos 3x \, dx \quad \text{and} \quad S = \int_0^{3\pi} e^{3x} \sin 3x \, dx.$$ By considering \(C + iS\) as a single integral, show that $$C = -\frac{1}{3}(2 + 3e^{\pi}),$$ and obtain a similar expression for \(S\). [8] (You may assume that the standard result for \(\int e^{kx} dx\) remains true when \(k\) is a complex constant, so that \(\int e^{(a+ib)x} dx = \frac{1}{a+ib}e^{(a+ib)x}\).)
OCR FP3 2011 January Q3
8 marks Standard +0.3
  1. Express \(\sin \theta\) in terms of \(e^{i\theta}\) and \(e^{-i\theta}\) and show that $$\sin^4 \theta \equiv \frac{1}{8}(\cos 4\theta - 4\cos 2\theta + 3).$$ [4]
  2. Hence find the exact value of \(\int_0^{\frac{\pi}{4}} \sin^4 \theta \, d\theta\). [4]
OCR FP3 2006 June Q7
12 marks Challenging +1.3
The series \(C\) and \(S\) are defined for \(0 < \theta < \pi\) by \begin{align} C &= 1 + \cos \theta + \cos 2\theta + \cos 3\theta + \cos 4\theta + \cos 5\theta,
S &= \sin \theta + \sin 2\theta + \sin 3\theta + \sin 4\theta + \sin 5\theta. \end{align}
  1. Show that \(C + iS = \frac{e^{3i\theta} - e^{-3i\theta}}{e^{i\theta} - e^{-i\theta}} \cdot e^{i\theta}\). [4]
  2. Deduce that \(C = \sin 3\theta \cos \frac{5}{2}\theta \operatorname{cosec} \frac{1}{2}\theta\) and write down the corresponding expression for \(S\). [4]
  3. Hence find the values of \(\theta\), in the range \(0 < \theta < \pi\), for which \(C = S\). [4]
OCR FP3 2010 June Q5
8 marks Challenging +1.2
Convergent infinite series \(C\) and \(S\) are defined by \begin{align} C &= 1 + \frac{1}{4} \cos \theta + \frac{1}{4} \cos 2\theta + \frac{1}{8} \cos 3\theta + \ldots,
S &= \frac{1}{2} \sin \theta + \frac{1}{4} \sin 2\theta + \frac{1}{8} \sin 3\theta + \ldots. \end{align}
  1. Show that \(C + iS = \frac{2}{2 - e^{i\theta}}\). [4]
  2. Hence show that \(C = \frac{4 - 2\cos \theta}{5 - 4\cos \theta}\) and find a similar expression for \(S\). [4]
AQA Further Paper 1 2019 June Q8
10 marks Standard +0.8
  1. If \(z = \cos \theta + i \sin \theta\), use de Moivre's theorem to prove that $$z^n - \frac{1}{z^n} = 2i \sin n\theta$$ [3 marks]
  2. Express \(\sin^5 \theta\) in terms of \(\sin 5\theta\), \(\sin 3\theta\) and \(\sin \theta\) [4 marks]
  3. Hence show that $$\int_0^{\frac{\pi}{3}} \sin^5 \theta \, d\theta = \frac{53}{480}$$ [3 marks]
AQA Further Paper 1 2024 June Q2
1 marks Easy -1.8
The complex number \(z = e^{\frac{i\pi}{3}}\) Which one of the following is a real number? Circle your answer. [1 mark] \(z^4\) \(z^5\) \(z^6\) \(z^7\)
AQA Further Paper 1 2024 June Q10
6 marks Standard +0.8
The complex numbers \(z\) and \(w\) are defined by $$z = \cos\frac{\pi}{4} + i\sin\frac{\pi}{4}$$ and $$w = \cos\frac{\pi}{6} + i\sin\frac{\pi}{6}$$ By evaluating the product \(zw\), show that $$\tan\frac{5\pi}{12} = 2 + \sqrt{3}$$ [6 marks]
AQA Further Paper 1 Specimen Q12
3 marks Challenging +1.8
The function \(f(x) = \cosh(ix)\) is defined over the domain \(\{x \in \mathbb{R} : -a\pi \leq x \leq a\pi\}\), where \(a\) is a positive integer. By considering the graph of \(y = [f(x)]^n\), find the mean value of \([f(x)]^n\), when \(n\) is an odd positive integer. Fully justify your answer. [3 marks]
AQA Further Paper 2 Specimen Q15
10 marks Challenging +1.3
  1. Show that \((1-\frac{1}{4}e^{2i\theta})(1-\frac{1}{4}e^{-2i\theta}) = \frac{1}{16}(17-8\cos 2\theta)\) [3 marks]
  2. Given that the series \(e^{2i\theta} + \frac{1}{4}e^{4i\theta} + \frac{1}{16}e^{6i\theta} + \frac{1}{64}e^{8i\theta} + \ldots\) has a sum to infinity, express this sum to infinity in terms of \(e^{2i\theta}\) [2 marks]
  3. Hence show that \(\sum_{n=1}^{\infty} \frac{1}{4^{n-1}} \cos 2n\theta = \frac{16\cos 2\theta - 4}{17 - 8\cos 2\theta}\) [4 marks]
  4. Deduce a similar expression for \(\sum_{n=1}^{\infty} \frac{1}{4^{n-1}} \sin 2n\theta\) [1 mark]
OCR MEI Further Pure Core Specimen Q14
18 marks Challenging +1.2
  1. Starting with the result $$e^{i\theta} = \cos \theta + i \sin \theta,$$ show that
    1. \((\cos \theta + i \sin \theta)^n = \cos n\theta + i \sin n\theta\) [2]
    2. \(\cos \theta = \frac{1}{2}(e^{i\theta} + e^{-i\theta})\). [2]
  2. Using the result in part (i) (A), obtain the values of the constants \(a\), \(b\), \(c\) and \(d\) in the identity $$\cos 6\theta = a \cos^6 \theta + b \cos^4 \theta + c \cos^2 \theta + d.$$ [6]
  3. Using the result in part (i) (B), obtain the values of the constants \(P\), \(Q\), \(R\) and \(S\) in the identity $$\cos^6 \theta = P \cos 6\theta + Q \cos 4\theta + R \cos 2\theta + S.$$ [5]
  4. Show that \(\cos \frac{\pi}{12} = \left(\frac{26 + 15\sqrt{3}}{64}\right)^{\frac{1}{4}}\). [3]
WJEC Further Unit 4 2022 June Q9
12 marks Challenging +1.3
    1. Expand \(\left(\cos\frac{\theta}{3} + i\sin\frac{\theta}{3}\right)^3\).
    2. Hence, by using de Moivre's theorem, show that \(\cos\theta\) can be expressed as $$4\cos^3\frac{\theta}{3} - 3\cos\frac{\theta}{3}.$$ [6]
  1. Hence, or otherwise, find the general solution of the equation \(\frac{\cos\theta}{\cos\frac{\theta}{3}} = 1\). [6]
SPS SPS FM Pure 2025 February Q11
8 marks Challenging +1.8
The infinite series \(C\) and \(S\) are defined by $$C = \cos \theta + \frac{1}{2}\cos 5\theta + \frac{1}{4}\cos 9\theta + \frac{1}{8}\cos 13\theta + \ldots$$ $$S = \sin \theta + \frac{1}{2}\sin 5\theta + \frac{1}{4}\sin 9\theta + \frac{1}{8}\sin 13\theta + \ldots$$ Given that the series \(C\) and \(S\) are both convergent,
  1. show that $$C + iS = \frac{2e^{i\theta}}{2 - e^{4i\theta}}$$ [4]
  2. Hence show that $$S = \frac{4\sin \theta + 2\sin 3\theta}{5 - 4\cos 4\theta}$$ [4]
OCR Further Pure Core 2 2021 June Q5
7 marks Challenging +1.8
\(C\) is the locus of numbers, \(z\), for which \(\ln\left(\frac{z + 7i}{z - 24}\right) = \frac{1}{4}\). By writing \(z = x + iy\) give a complete description of the shape of \(C\) on an Argand diagram. [7]
OCR Further Pure Core 2 2018 March Q9
14 marks Challenging +1.2
In this question you must show detailed reasoning.
  1. Show that \(e^{i\theta} - e^{-i\theta} = 2i\sin\theta\). [1]
  2. Hence, show that \(\frac{2}{e^{2i\theta} - 1} = -(1 + i\cot\theta)\). [3]
  3. Two series, \(C\) and \(S\), are defined as follows. $$C = 2 + 2\cos\frac{\pi}{10} + 2\cos\frac{\pi}{5} + 2\cos\frac{3\pi}{10} + 2\cos\frac{2\pi}{5}$$ $$S = 2\sin\frac{\pi}{10} + 2\sin\frac{\pi}{5} + 2\sin\frac{3\pi}{10} + 2\sin\frac{2\pi}{5}$$ By considering \(C + iS\), find a simplified expression for \(C\) in terms of only integers and \(\cot\frac{\pi}{10}\). [8]
  4. Verify that \(S = C - 2\) and, by considering the series in their original form, explain why this is so. [2]
OCR Further Pure Core 2 2018 December Q9
5 marks Standard +0.8
  1. By using Euler's formula show that \(\cosh(\text{iz}) = \cos z\). [3]
  2. Hence, find, in logarithmic form, a root of the equation \(\cos z = 2\). [You may assume that \(\cos z = 2\) has complex roots.] [2]
Pre-U Pre-U 9795/1 2015 June Q6
9 marks Challenging +1.2
  1. Given the complex number \(z = \cos \theta + \text{i} \sin \theta\), show that \(z^n + \frac{1}{z^n} = 2 \cos n\theta\). [1]
  2. Deduce the identity \(16 \cos^5 \theta \equiv \cos 5\theta + 5 \cos 3\theta + 10 \cos \theta\). [4]
  3. For \(0 < \theta < 2\pi\), solve the equation \(\cos 5\theta + 5 \cos 3\theta + 9 \cos \theta = 0\). [4]