Among the families with two children in a large city, the probability that the elder child is a boy is \(\frac{5}{12}\) and the probability that the younger child is a boy is \(\frac{9}{16}\). The probability that the younger child is a girl, given that the elder child is a girl, is \(\frac{1}{4}\).
One of the families is chosen at random. Using a tree diagram, or otherwise,
- show that the probability that both children are boys is \(\frac{1}{8}\). [5 marks]
Find the probability that
- one child is a boy and the other is a girl, [3 marks]
- one child is a boy given that the other is a girl. [3 marks]
If three of the families are chosen at random,
- find the probability that exactly two of the families have two boys. [3 marks]
- State an assumption that you have made in answering part (d). [1 mark]