1.09f Trapezium rule: numerical integration

378 questions

Sort by: Default | Easiest first | Hardest first
OCR MEI Further Numerical Methods 2019 June Q1
6 marks Moderate -0.5
1 Fig. 1 shows some spreadsheet output concerning the values of a function, \(\mathrm { f } ( x )\). \begin{table}[h]
ABC
1\(x\)\(\mathrm { f } ( x )\)
210.3678794410.367879441
320.0183156390.38619508
430.000123410.38631849
54\(1.12535 \mathrm { E } - 07\)0.386318602
65\(1.38879 \mathrm { E } - 11\)0.386318602
\captionsetup{labelformat=empty} \caption{Fig. 1}
\end{table} The formula in cell B2 is ==EXP(-(A2\^{}2)) and equivalent formulae are in cells B3 to B6. The formula in cell C 2 is \(= \mathrm { B } 2\).
The formula in cell C3 is \(\quad = \mathrm { C } 2 + \mathrm { B } 3\). Equivalent formulae are in cells C4 to C6.
  1. Use sigma notation to express the formula in cell C5 in standard mathematical notation.
  2. Explain why the same value is displayed in cells C 5 and C 6. Now suppose that the value in cell C2 is chopped to 3 decimal places and used to approximate the value in cell C2.
  3. Calculate the relative error when this approximation is used. Suppose that the values in cells B4, B5 and B6 are chopped to 3 decimal places and used as approximations to the original values in cells B4, B5 and B6 respectively.
  4. Explain why the relative errors in these approximations are all the same.
OCR MEI Further Numerical Methods 2019 June Q5
12 marks Standard +0.8
5 Fig. 5 shows spreadsheet output concerning the estimation of the derivative of a function \(\mathrm { f } ( x )\) at \(x = 2\) using the forward difference method. \begin{table}[h]
ABCD
1hestimatedifferenceratio
20.16.3050005
30.016.0300512-0.274949
40.0016.0030018-0.0270490.098379
50.00016.0003014-0.00270.099835
60.000016.0000314-0.000270.099983
70.0000016.0000044\(- 2.7 \mathrm { E } - 05\)0.099994
81E-076.0000016\(- 2.71 \mathrm { E } - 06\)0.100352
91E-086.0000013\(- 3.02 \mathrm { E } - 07\)0.111457
101E-096.0000018\(4.885 \mathrm { E } - 07\)-1.61765
111E-106.0000049\(3.109 \mathrm { E } - 06\)6.363636
121E-116.0000005\(- 4.44 \mathrm { E } - 06\)-1.42857
131E-126.00053340.0005329-120
141E-135.9952043-0.005329-10
151E-146.12843110.1332268-25
161E-155.3290705-0.799361-6
171E-160-5.3290716.666667
\captionsetup{labelformat=empty} \caption{Fig. 5}
\end{table}
  1. Write down suitable cell formulae for
    The formula in cell B2 is \(\quad = ( \mathrm { LN } ( \mathrm { SQRT } ( \mathrm { SINH } ( ( 2 + \mathrm { A } 2 ) \wedge 3 ) ) ) - \mathrm { LN } ( \mathrm { SQRT } ( \mathrm { SINH } ( 2 \wedge 3 ) ) ) ) / \mathrm { A } 2\) and equivalent formulae are entered in cells B3 to B17.
  2. Write \(\mathrm { f } ( x )\) in standard mathematical notation. The value displayed in cell B17 is zero, even though the calculation results in a non-zero answer.
  3. Explain how this has arisen.
OCR MEI Further Numerical Methods 2019 June Q6
10 marks Standard +0.3
6 The spreadsheet output in Fig. 6 shows approximations to \(\int _ { 0 } ^ { 1 } x ^ { - \sqrt { x } } \mathrm {~d} x\) found using the midpoint rule, denoted by \(M _ { n }\), and the trapezium rule, denoted by \(T _ { n }\). \begin{table}[h]
ABC
1\(n\)\(M _ { n }\)\(T _ { n }\)
211.6325271
321.6414611.316263
441.6230531.478862
581.6102951.550957
6161.6041321.580626
7321.6015051.592379
\captionsetup{labelformat=empty} \caption{Fig. 6}
\end{table}
  1. Write down an efficient spreadsheet formula for cell C3.
  2. By first completing the table in the Printed Answer Booklet using the Simpson's rule, calculate the most accurate estimate of \(\int _ { 0 } ^ { 1 } x ^ { - \sqrt { x } } \mathrm {~d} x\) that you can, justifying the precision quoted. \section*{END OF QUESTION PAPER}
OCR MEI Further Numerical Methods 2022 June Q2
7 marks Moderate -0.5
2 The table shows some values of \(x\) and the associated values of \(y = f ( x )\).
\(x\)2.7533.25
\(\mathrm { f } ( x )\)0.92079911.072858
  1. Calculate an estimate of \(\frac { \mathrm { dy } } { \mathrm { dx } }\) at \(x = 3\) using the forward difference method, giving your answer correct to \(\mathbf { 5 }\) decimal places.
  2. Calculate an estimate of \(\frac { \mathrm { dy } } { \mathrm { dx } }\) at \(x = 3\) using the central difference method, giving your answer correct to \(\mathbf { 5 }\) decimal places.
  3. Explain why your answer to part (b) is likely to be closer than your answer to part (a) to the true value of \(\frac { \mathrm { dy } } { \mathrm { dx } }\) at \(x = 3\). When \(x = 5\) it is given that \(y = 1.4645\) and \(\frac { \mathrm { dy } } { \mathrm { dx } } = 0.1820\), correct to 4 decimal places.
  4. Determine an estimate of the error when \(\mathrm { f } ( 5 )\) is used to estimate \(\mathrm { f } ( 5.024 )\).
OCR MEI Further Numerical Methods 2022 June Q5
9 marks Standard +0.3
5 Kai uses the midpoint rule, trapezium rule and Simpson's rule to find approximations to \(\int _ { \mathrm { a } } ^ { \mathrm { b } } \mathrm { f } ( \mathrm { x } ) \mathrm { dx }\), where \(a\) and \(b\) are constants. The associated spreadsheet output is shown in the table. Some of the values are missing.
FGHI
3\(n\)\(\mathrm { M } _ { \mathrm { n } }\)\(\mathrm { T } _ { \mathrm { n } }\)\(\mathrm { S } _ { 2 \mathrm { n } }\)
410.24366990.1479020
520.2306967
  1. Write down a suitable spreadsheet formula for cell H 5 .
  2. Complete the copy of the table in the Printed Answer Booklet, giving the values correct to 7 decimal places.
  3. Use your answers to part (b) to determine the value of \(\int _ { a } ^ { b } f ( x ) d x\) as accurately as you can, justifying the precision quoted.
OCR MEI Further Numerical Methods 2023 June Q3
6 marks Standard +0.3
3 The diagram shows the graph of \(y = f ( x )\) for values of \(x\) from 1 to 3.5. \includegraphics[max width=\textwidth, alt={}, center]{4023e87c-34b1-4abd-9acc-ede5e4d68c7f-03_945_1248_312_244} The table shows some values of \(x\) and the associated values of \(y\).
\(x\)1.522.5
\(y\)1.6821372.0943952.318559
  1. Use the forward difference method to calculate an approximation to \(\frac { \mathrm { dy } } { \mathrm { dx } }\) at \(x = 2\).
  2. Use the central difference method to calculate an approximation to \(\frac { \mathrm { dy } } { \mathrm { dx } }\) at \(x = 2\).
  3. On the copy of the diagram in the Printed Answer Booklet, show how the central difference method gives the approximation to \(\frac { \mathrm { dy } } { \mathrm { dx } }\) at \(x = 2\) which was found in part (b).
  4. Explain whether your answer to part (a) or your answer to part (b) is likely to give a better approximation to \(\frac { \mathrm { dy } } { \mathrm { dx } }\) at \(x = 2\).
OCR MEI Further Numerical Methods 2023 June Q4
4 marks Moderate -0.8
4 A spreadsheet is used to approximate \(\int _ { a } ^ { b } f ( x ) d x\) using the midpoint rule with 1 strip. The output is shown in the table below.
BCD
3\(x\)\(\mathrm { f } ( x )\)\(\mathrm { M } _ { 1 }\)
41.51.31037070.65518535
The formula in cell C4 is \(= \mathrm { B } 4 \wedge ( 1 / \mathrm { B } 4 )\).
The formula in cell D4 is \(= 0.5 ^ { * } \mathrm { C } 4\).
  1. Write the integral in standard mathematical notation. A graph of \(y = f ( x )\) is included in the diagram below. \includegraphics[max width=\textwidth, alt={}, center]{4023e87c-34b1-4abd-9acc-ede5e4d68c7f-04_789_1004_1199_235}
  2. Explain whether 0.65518535 is an over-estimate or an under-estimate of \(\int _ { a } ^ { b } f ( x ) d x\).
OCR MEI Further Numerical Methods 2023 June Q9
9 marks Challenging +1.2
9 The trapezium rule is used to calculate 3 approximations to \(\int _ { 0 } ^ { 1 } \sqrt [ 3 ] { \sinh ( x ) } \mathrm { d } x\) with 1,2 and 4 strips respectively. The results are shown in Table 9.1. \begin{table}[h]
\captionsetup{labelformat=empty} \caption{Table 9.1}
\(n\)\(\mathrm {~T} _ { n }\)
10.52764369
20.66617652
40.72534275
\end{table}
  1. Use these results to determine two approximations to \(\int _ { 0 } ^ { 1 } \sqrt [ 3 ] { \sinh ( x ) } \mathrm { d } x\) using Simpson's rule.
  2. Use your answers to part (a) to state the value of \(\int _ { 0 } ^ { 1 } \sqrt [ 3 ] { \sinh ( x ) } \mathrm { d } x\) as accurately as you can, justifying the precision quoted. Table 9.2 shows some further approximations found using the trapezium rule, together with some analysis of these approximations. \begin{table}[h]
    \captionsetup{labelformat=empty} \caption{Table 9.2}
    \(n\)\(\mathrm { T } _ { n }\)differenceratio
    10.5276437
    20.66617650.138533
    40.72534270.0591660.42709
    80.74988210.0245390.41475
    160.75988580.0100040.40766
    320.76392210.0040360.40348
    640.76554040.0016180.40095
    \end{table}
  3. Explain what can be deduced about the order of the method in this case.
  4. Use extrapolation to obtain the value of \(\int _ { 0 } ^ { 1 } \sqrt [ 3 ] { \sinh ( x ) } \mathrm { d } x\) as accurately as you can, justifying the precision quoted.
OCR MEI Further Numerical Methods 2024 June Q1
4 marks Standard +0.8
1 The table shows some values of \(x\), together with the associated values of a function, \(\mathrm { f } ( x )\).
\(x\)1.922.1
\(\mathrm { f } ( x )\)0.58420.63090.6753
  1. Use the information in the table to calculate the most accurate estimate of \(f ^ { \prime } ( 2 )\) possible.
  2. Calculate an estimate of the error when \(f ( 2 )\) is used as an estimate of \(f ( 2.05 )\).
OCR MEI Further Numerical Methods 2024 June Q6
10 marks Standard +0.3
6 Table 6.1 shows some values of \(x\) and the associated values of a function, \(y = f ( x )\). \begin{table}[h]
\captionsetup{labelformat=empty} \caption{Table 6.1}
\(x\)1.512
\(\mathrm { f } ( x )\)0.8408911.18921
\end{table}
  1. Explain why it is not possible to use the central difference method to calculate an estimate of \(\frac { \mathrm { dy } } { \mathrm { dx } }\) when \(x = 1\).
  2. Use the forward difference method to calculate an estimate of \(\frac { \mathrm { dy } } { \mathrm { dx } }\) when \(x = 1\). A student uses the forward difference method to calculate a series of approximations to \(\frac { \mathrm { dy } } { \mathrm { dx } }\) when \(x = 2\) with different values of the step length, \(h\). These approximations are shown in Table 6.2, together with some further analysis. \begin{table}[h]
    \captionsetup{labelformat=empty} \caption{Table 6.2}
    \(h\)0.80.40.20.10.050.0250.01250.00625
    approximation0.1304520.1386470.1433810.1459420.1472770.1479590.1483040.148477
    difference0.0081950.0047340.0025610.0013350.0006820.0003450.000173
    ratio0.5776330.5410990.5211860.5107620.5054240.502723
    \end{table}
    1. Explain what the ratios of differences tell you about the order of the method in this case.
    2. Comment on whether this is unusual.
  3. Determine the value of \(\frac { \mathrm { dy } } { \mathrm { dx } }\) when \(x = 2\) as accurately as possible. You must justify the precision quoted.
OCR MEI Further Numerical Methods 2024 June Q7
14 marks Standard +0.3
7 A student is using a spreadsheet to find approximations to \(\int _ { 0 } ^ { 1 } f ( x ) d x\) using the midpoint rule, the trapezium rule and Simpson's rule. Some of the associated spreadsheet output with \(n = 1\) and \(n = 2\), is shown in Table 7.1. \begin{table}[h]
\captionsetup{labelformat=empty} \caption{Table 7.1}
\(n\)\(\mathrm { M } _ { n }\)\(\mathrm {~T} _ { n }\)\(\mathrm {~S} _ { 2 n }\)
10.6125471
20.639735
\end{table}
  1. Complete the copy of Table 7.1 in the Printed Answer Booklet. Give your answers correct to 5 decimal places.
  2. State the value of \(\int _ { 0 } ^ { 1 } \mathrm { f } ( x ) \mathrm { d } x\) as accurately as possible. You must justify the precision quoted. The student calculates some more approximations using Simpson's rule. These approximations are shown in the associated spreadsheet output, together with some further analysis, in Table 7.2. The values of \(S _ { 2 }\) and \(S _ { 4 }\) have been blacked out, together with the associated difference and ratio. \begin{table}[h]
    \captionsetup{labelformat=empty} \caption{Table 7.2}
    n\(\mathrm { S } _ { 2 n }\)differenceratio
    1
    2
    40.674353-0.0209
    80.665199-0.009150.438059
    160.661297-0.00390.426286
    320.659675-0.001620.415762
    640.659015-0.000660.406785
    \end{table}
  3. The student checks some of her values with a calculator. She does not obtain 0.406785 when she calculates \(- 0.00066 \div ( - 0.00162 )\). Explain whether the value in the spreadsheet, or her value, is a more precise approximation to the ratio of differences in this case.
    1. State the order of convergence of the values in the ratio column. You must justify your answer.
    2. Explain what the values in the ratio column tell you about the order of the method in this case.
    3. Comment on whether this is unusual.
  4. Determine the value of \(\int _ { 0 } ^ { 1 } f ( x ) d x\) as accurately as you can. You must justify the precision quoted.
OCR MEI Further Numerical Methods 2020 November Q4
10 marks Challenging +1.2
4
  1. Use the trapezium rule with 1 strip to calculate an estimate of \(\int _ { 1 } ^ { 2 } \sqrt { 1 + x ^ { 3 } } \mathrm {~d} x\), giving your
    answer correct to six decimal places.
    [0pt] [2]
    Fig. 4 shows some spreadsheet output containing further approximations to this integral using the trapezium rule, denoted by \(T _ { n }\), and Simpson's rule, denoted by \(S _ { 2 n }\). \begin{table}[h]
    ABC
    1\(n\)\(T _ { n }\)\(S _ { 2 n }\)
    212.130135
    322.149378
    442.1347512.129862
    582.131084
    \captionsetup{labelformat=empty} \caption{Fig. 4}
    \end{table}
  2. Write down an efficient formula for cell C 4.
  3. Find the value of \(S _ { 4 }\), giving your answer correct to 6 decimal places.
  4. Without doing any further calculation, state the value of \(\int _ { 1 } ^ { 2 } \sqrt { 1 + x ^ { 3 } } \mathrm {~d} x\) as accurately as
    possible, justifying the precision quoted.
    [0pt] [2]
  5. Use the fact that Simpson's rule is a fourth order method to obtain an improved approximation to the value of \(\int _ { 1 } ^ { 2 } \sqrt { 1 + x ^ { 3 } } \mathrm {~d} x\), stating the value of this integral to a precision which seems justified.
OCR MEI Further Numerical Methods 2020 November Q7
11 marks Challenging +1.2
7 Fig. 7.1 shows two values of \(x\) and the associated values of \(\mathrm { f } ( x )\). \begin{table}[h]
\(x\)33.5
\(\mathrm { f } ( x )\)6.0827634.596194
\captionsetup{labelformat=empty} \caption{Fig. 7.1}
\end{table}
  1. Use the forward difference method to calculate an estimate of the gradient of \(\mathrm { f } ( x )\) at \(x = 3\), giving your answer correct to 4 decimal places. Fig. 7.2 shows some spreadsheet output with additional values of \(x\) and the associated values of \(\mathrm { f } ( x )\). \begin{table}[h]
    \(x\)33.000013.00013.0013.013.1
    \(\mathrm { f } ( x )\)6.0827636.082746.0825416.080546.0604545.848846
    \captionsetup{labelformat=empty} \caption{Fig. 7.2}
    \end{table} These values have been used to produce a sequence of estimates of the gradient of \(\mathrm { f } ( x )\) at \(x = 3\), together with some further analysis. This is shown in the spreadsheet output in Fig. 7.3. \begin{table}[h]
    \(h\)0.10.010.0010.00010.00001
    estimate-2.339165-2.230883-2.220532-2.219501-2.219398
    difference0.10828150.0103520.00103070.000103
    ratio0.0956020.0995670.0999568
    \captionsetup{labelformat=empty} \caption{Fig. 7.3}
    \end{table} Tommy states that the differences between successive estimates is decreasing so rapidly that the order of convergence of this sequence of estimates is much faster than first order.
  2. Explain whether or not Tommy is correct.
  3. Use extrapolation to determine the value of the gradient of \(\mathrm { f } ( x )\) at \(x = 3\) as accurately as possible, justifying the precision quoted.
  4. Calculate an estimate of the absolute error when \(\mathrm { f } ( 3 )\) is used as an approximation to \(\mathrm { f } ( 3.02 )\).
OCR MEI Further Numerical Methods 2021 November Q2
6 marks Challenging +1.2
2 The table shows some values of \(x\) and the associated values of \(\mathrm { f } ( x )\).
\(x\)12345
\(\mathrm { f } ( x )\)- 0.65- 0.351.775.7111.47
  1. Complete the difference table in the Printed Answer Booklet.
  2. Explain why the data may be interpolated by a polynomial of degree 2.
  3. Use Newton's forward difference interpolation formula to obtain a polynomial of degree 2 for the data.
OCR MEI Further Numerical Methods 2021 November Q7
15 marks Standard +0.8
7 Sarah uses the trapezium rule to find a sequence of approximations to \(\int _ { 0 } ^ { 1 } \sqrt { \tanh ( x ) } \mathrm { d } x\).
Her spreadsheet output is shown in Fig. 7.1. \begin{table}[h]
\(n\)\(T _ { n }\)differenceratio
10.43634681
20.55806940.121723
40.601998430.0439290.36089
80.617870730.0158720.36132
160.623576010.0057050.35945
320.625617160.0020410.35777
\captionsetup{labelformat=empty} \caption{Fig. 7.1}
\end{table}
  1. Write down the value of \(h\) used to find the approximation 0.62357601 .
  2. Without doing any further calculation, state the value of \(\int _ { 0 } ^ { 1 } \sqrt { \tanh ( x ) } \mathrm { d } x\) as accurately as you
    can, justifying the precision quoted.
  3. Explain what the values in the ratio column tell you about the order of convergence of this sequence of approximations. Sarah carries out further work using the midpoint rule and Simpson's rule. Her results are shown in Fig. 7.2. \begin{table}[h]
    MNOPQR
    1\(n\)\(T _ { n }\)\(M _ { n }\)\(S _ { 2 n }\)differenceratio
    210.436346810.6797920.5986436
    320.55806940.645927450.616641440.018
    440.601998430.633743040.62316150.006520.362269
    580.617870730.629281290.625477770.002320.355253
    6160.623576010.627658310.626297550.000820.35392
    7320.625617160.62707259
    \captionsetup{labelformat=empty} \caption{Fig. 7.2}
    \end{table}
  4. Write down an efficient spreadsheet formula for calculating \(S _ { 16 }\).
  5. Determine the missing values in row 7.
  6. Use extrapolation to determine the value of \(\int _ { 0 } ^ { 1 } \sqrt { \tanh ( x ) } d x\) as accurately as you can, justifying
    the precision quoted.
    [0pt] [6]
OCR MEI Further Numerical Methods Specimen Q5
10 marks Standard +0.3
5 A vehicle is moving in a straight line. Its velocity at different times is recorded and shown below. The velocities are recorded to 5 significant figures and the times may be assumed to be exact.
Time \(( t\) seconds \()\)5101215
Velocity \(( v\) metres per second \()\)5.125011.00014.00018.375
It is suggested initially that a quadratic model may be appropriate for this situation.
  1. Given that the vehicle is modelled as a particle with constant mass, what assumption about the net force acting on the vehicle leads to a quadratic model?
  2. Find Newton's interpolating polynomial of degree 2 to model this situation. Write your answer in the form \(v = a t ^ { 2 } + b t + c\).
  3. Comment on whether this model appears to be appropriate.
  4. Use this model to find an approximation to the distance travelled over the interval \(5 \leq t \leq 15\). Further investigation suggests that a cubic model may be more appropriate.
  5. What technique would you use to fit a cubic model to the data in the table?
OCR MEI Further Numerical Methods Specimen Q7
19 marks Challenging +1.2
7 Fig. 7 shows the graph of \(y = \mathrm { f } ( x )\) for values of \(x\) from 0 to 1 . \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{662c2d48-228a-4b94-a4b4-cdd31634ef21-6_693_673_390_696} \captionsetup{labelformat=empty} \caption{Fig. 7}
\end{figure} The following spreadsheet printout shows estimates of \(\int _ { 0 } ^ { 1 } f ( x ) d x\) found using the midpoint and trapezium rules for different values of \(h\), the strip width.
AABC
1\(h\)MidpointTrapezium
211.998517421.751283839
30.51.96385911.874900631
40.251.951352591.919379864
50.1251.946821021.935366229
  1. Without doing any further calculation, write down the smallest possible interval which contains the value of the integral. Justify your answer.
  2. (A) - Calculate the ratio of differences, \(r\), for the sequence of estimates calculated using the trapezium rule.
    Using a similar approach with the sequence of estimates calculated using the midpoint rule, the approximation to the integral from extrapolation was found to be 1.94427 correct to 5 decimal places.
  3. Andrea uses the extrapolated midpoint rule value and the value found in part (ii) ( \(B\) ) to write down an interval which contains the value of the integral. Comment on the validity of Andrea's method.
  4. Use the values from the spreadsheet output to calculate an approximation to the integral using Simpson's rule with \(h = 0.125\). Give your answer to 5 decimal places. Approximations to the integral using Simpson's rule are given in the spreadsheet output below. The number of applications of Simpson's rule is given in column N.
    NOPQ
    \(n\)Simpsondifferencesratio
    11.916106230.018100050.3584931
    21.934206280.006488740.3556525
    41.940695020.002307740.3544828
    81.943002750.000818050.3539885
    161.943820810.000289580.3537638
    321.944110390.000102440.3536568
    641.94421283\(3.623 \mathrm { E } - 05\)
    1281.94424906
  5. Use the spreadsheet output to find the value of the integral as accurately as possible. Justify the precision quoted. \section*{END OF QUESTION PAPER} }{www.ocr.org.uk}) after the live examination series. If OCR has unwittingly failed to correctly acknowledge or clear any third-party content in this assessment material, OCR will be happy to correct its mistake at the earliest possible opportunity. For queries or further information please contact the Copyright Team, First Floor, 9 Hills Road, Cambridge CB2 1GE.
    OCR is part of the }\section*{}
Edexcel FP1 2019 June Q1
5 marks Moderate -0.8
  1. Use Simpson's rule with 4 intervals to estimate
$$\int _ { 0.4 } ^ { 2 } e ^ { x ^ { 2 } } d x$$
Edexcel FP1 2020 June Q2
6 marks Standard +0.3
2. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{9f127ab1-0e03-4f9f-87c2-01c553c54ee9-04_807_649_251_708} \captionsetup{labelformat=empty} \caption{Figure 1}
\end{figure} Figure 1 shows a sketch of the vertical cross-section of the entrance to a tunnel. The width at the base of the tunnel entrance is 2 metres and its maximum height is 3 metres. The shape of the cross-section can be modelled by the curve with equation \(y = \mathrm { f } ( x )\) where $$f ( x ) = 3 \cos \left( \frac { \pi } { 2 } x ^ { 2 } \right) \quad x \in [ - 1,1 ]$$ A wooden door of uniform thickness 85 mm is to be made to seal the tunnel entrance.
Use Simpson's rule with 6 intervals to estimate the volume of wood required for this door, giving your answer in \(\mathrm { m } ^ { 3 }\) to 4 significant figures.
Edexcel FP1 2024 June Q1
5 marks Moderate -0.8
  1. Given that $$y = \ln \left( 3 + x ^ { 2 } \right)$$ complete the table with the value of \(y\) corresponding to \(x = 3\), giving your answer to 4 significant figures.
    \(\boldsymbol { x }\)22.533.544.55
    \(\boldsymbol { y }\)1.9462.2252.7252.9443.1463.332
    In part (b) you must show all stages of your working. \section*{Solutions relying entirely on calculator technology are not acceptable.}
  2. Use Simpson's rule with all the values of \(y\) in the completed table to estimate, to 3 significant figures, the value of $$\int _ { 2 } ^ { 5 } \ln \left( 3 + x ^ { 2 } \right) \mathrm { d } x$$
  3. Using your answer to part (b) and making your method clear, estimate the value of $$\int _ { 2 } ^ { 5 } \ln \sqrt { \left( 3 + x ^ { 2 } \right) } \mathrm { d } x$$
Edexcel FP1 Specimen Q1
5 marks Moderate -0.8
  1. Use Simpson's Rule with 6 intervals to estimate
$$\int _ { 1 } ^ { 4 } \sqrt { 1 + x ^ { 3 } } d x$$
CAIE P2 2024 June Q6
9 marks Moderate -0.3
  1. Use the trapezium rule with two intervals to find an approximation to the area of the shaded region. Give your answer correct to 2 significant figures.
  2. The shaded region is rotated completely about the \(x\)-axis. Find the exact volume of the solid produced. \includegraphics[max width=\textwidth, alt={}, center]{971a1d8d-a82e-4a3a-b72d-3c147e4f30bb-11_65_1548_379_349} \includegraphics[max width=\textwidth, alt={}]{971a1d8d-a82e-4a3a-b72d-3c147e4f30bb-11_67_1566_466_328} ........................................................................................................................................ \includegraphics[max width=\textwidth, alt={}, center]{971a1d8d-a82e-4a3a-b72d-3c147e4f30bb-11_70_1570_646_324} \includegraphics[max width=\textwidth, alt={}, center]{971a1d8d-a82e-4a3a-b72d-3c147e4f30bb-11_72_1570_735_324} \includegraphics[max width=\textwidth, alt={}, center]{971a1d8d-a82e-4a3a-b72d-3c147e4f30bb-11_72_1570_826_324} \includegraphics[max width=\textwidth, alt={}]{971a1d8d-a82e-4a3a-b72d-3c147e4f30bb-11_74_1570_916_324} ........................................................................................................................................ . \includegraphics[max width=\textwidth, alt={}, center]{971a1d8d-a82e-4a3a-b72d-3c147e4f30bb-11_72_1572_1096_322} \includegraphics[max width=\textwidth, alt={}, center]{971a1d8d-a82e-4a3a-b72d-3c147e4f30bb-11_70_1570_1187_324} \includegraphics[max width=\textwidth, alt={}, center]{971a1d8d-a82e-4a3a-b72d-3c147e4f30bb-11_67_1570_1279_324} \includegraphics[max width=\textwidth, alt={}, center]{971a1d8d-a82e-4a3a-b72d-3c147e4f30bb-11_70_1570_1367_324} \includegraphics[max width=\textwidth, alt={}]{971a1d8d-a82e-4a3a-b72d-3c147e4f30bb-11_62_1570_1462_324} .......................................................................................................................................... ......................................................................................................................................... . \includegraphics[max width=\textwidth, alt={}]{971a1d8d-a82e-4a3a-b72d-3c147e4f30bb-11_72_1570_1724_324} .......................................................................................................................................... . \includegraphics[max width=\textwidth, alt={}, center]{971a1d8d-a82e-4a3a-b72d-3c147e4f30bb-11_71_1570_1905_324} \includegraphics[max width=\textwidth, alt={}, center]{971a1d8d-a82e-4a3a-b72d-3c147e4f30bb-11_74_1570_1994_324} \includegraphics[max width=\textwidth, alt={}]{971a1d8d-a82e-4a3a-b72d-3c147e4f30bb-11_76_1570_2083_324} ......................................................................................................................................... . ........................................................................................................................................ ......................................................................................................................................... ........................................................................................................................................ . ......................................................................................................................................... . ........................................................................................................................................
CAIE P2 2024 November Q6
9 marks Moderate -0.3
  1. Use the trapezium rule with two intervals to find an approximation to the area of region \(A\). Give your answer correct to 3 significant figures. \includegraphics[max width=\textwidth, alt={}, center]{18aea465-b5b0-48f0-970a-e9ede1dc9370-10_2720_38_105_2010} \includegraphics[max width=\textwidth, alt={}, center]{18aea465-b5b0-48f0-970a-e9ede1dc9370-11_2716_29_107_22}
  2. Find the exact total area of regions \(A\) and \(B\). Give your answer in the form \(k \ln m\), where \(k\) and \(m\) are constants.
  3. Deduce an approximation to the area of region \(B\). Give your answer correct to 3 significant figures.
  4. State, with a reason, whether your answer to part (c) is an over-estimate or an under-estimate of the area of region \(B\).
AQA C2 2011 June Q6
10 marks Moderate -0.3
  1. The area of the shaded region is given by \(\int _ { 0 } ^ { 2 } \sin x \mathrm {~d} x\), where \(x\) is in radians. Use the trapezium rule with five ordinates (four strips) to find an approximate value for the area of the shaded region, giving your answer to three significant figures.
  2. Describe the geometrical transformation that maps the graph of \(y = \sin x\) onto the graph of \(y = 2 \sin x\).
  3. Use a trigonometrical identity to solve the equation $$2 \sin x = \cos x$$ in the interval \(0 \leqslant x \leqslant 2 \pi\), giving your solutions in radians to three significant figures.
OCR MEI C2 Q11
12 marks Moderate -0.8
  1. The speed-time graph on the insert sheet provides the axes and the first two points plotted. Plot the remainder of these points and join them with a smooth curve. The area between this curve and the \(t\)-axis represents the distance travelled by the car in this time.
  2. Using the trapezium rule with 6 values of \(t\) estimate the area under the curve to give the distance travelled. Illustrate on your graph the area found.
  3. John's teacher suggests that the equation of the curve could be \(v = 6 t - \frac { 1 } { 2 } t ^ { 2 }\). Find, by calculus, the area between this curve and the \(t\) axis.
  4. Plot this curve on your graph. Comment on whether the estimates obtained in parts (ii) and (iii) are overestimates or underestimates. 12 Fig. 12 shows a window. The base and sides are parts of a rectangle with dimensions \(2 x\) metres horizontally by \(y\) metres vertically. The top is a semicircle of radius \(x\) metres. The perimeter of the window is 10 metres. \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{73d1c02b-1b7b-426d-a171-c762597cfed4-4_428_433_1638_766} \captionsetup{labelformat=empty} \caption{Fig. 12}
    \end{figure}
  1. Express \(y\) as a function of \(x\).
  2. Find the total area, \(A \mathrm {~m} ^ { 2 }\), in terms of \(x\) and \(y\). Use your answer to part (i) to show that this simplifies to $$A = 10 x - 2 x ^ { 2 } - \frac { 1 } { 2 } \pi x ^ { 2 }$$
  3. Prove that for the maximum value of \(A\), \(y = x\) exactly.
    \section*{MEI STRUCTURED MATHEMATICS } \section*{CONCEPTS FOR ADVANCED MATHEMATICS, C2} \section*{Practice Paper C2-B
    Insert sheet for question 11}