1.08e Area between curve and x-axis: using definite integrals

499 questions

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OCR H240/03 2021 November Q8
11 marks Standard +0.3
\includegraphics{figure_8} The diagram shows the curve \(M\) with equation \(y = xe^{-2x}\).
  1. Show that \(M\) has a point of inflection at the point \(P\) where \(x = 1\). [5]
The line \(L\) passes through the origin \(O\) and the point \(P\). The shaded region \(R\) is enclosed by the curve \(M\) and the line \(L\).
  1. Show that the area of \(R\) is given by $$\frac{1}{4}(a + be^{-2}),$$ where \(a\) and \(b\) are integers to be determined. [6]
OCR H240/03 2022 June Q6
8 marks Standard +0.3
In this question you must show detailed reasoning. \includegraphics{figure_6} The diagram shows the curves \(y = \sqrt{2x + 9}\) and \(y = 4\mathrm{e}^{-2x} - 1\) which intersect on the \(y\)-axis. The shaded region is bounded by the curves and the \(x\)-axis. Determine the area of the shaded region, giving your answer in the form \(p + q \ln 2\) where \(p\) and \(q\) are constants to be determined. [8]
AQA AS Paper 1 2022 June Q7
6 marks Standard +0.3
A curve has equation \(y = a^2 - x^2\), where \(a > 0\) The area enclosed between the curve and the \(x\)-axis is 36 units. Find the value of \(a\). Fully justify your answer. [6 marks]
AQA AS Paper 1 2023 June Q8
7 marks Standard +0.3
  1. Show that $$\int_1^a \left(6 - \frac{12}{\sqrt{x}}\right) dx = 6a - 24\sqrt{a} + 18$$ [3 marks]
  2. The curve \(y = 6 - \frac{12}{\sqrt{x}}\), the line \(x = 1\) and the line \(x = a\) are shown in the diagram below. The shaded region \(R_1\) is bounded by the curve, the line \(x = 1\) and the \(x\)-axis. The shaded region \(R_2\) is bounded by the curve, the line \(x = a\) and the \(x\)-axis. \includegraphics{figure_8} It is given that the areas of \(R_1\) and \(R_2\) are equal. Find the value of \(a\) Fully justify your answer. [4 marks]
AQA AS Paper 2 2020 June Q9
7 marks Moderate -0.3
    1. Find $$\int (4x - x^3) dx$$ [2 marks]
    2. Evaluate $$\int_{-2}^{2} (4x - x^3) dx$$ [1 mark]
  1. Using a sketch, explain why the integral in part (a)(ii) does not give the area enclosed between the curve \(y = 4x - x^3\) and the \(x\)-axis. [2 marks]
  2. Find the area enclosed between the curve \(y = 4x - x^3\) and the \(x\)-axis. [2 marks]
AQA AS Paper 2 2024 June Q9
9 marks Standard +0.3
A curve has equation $$y = x - a\sqrt{x} + b$$ where \(a\) and \(b\) are constants. The curve intersects the line \(y = 2\) at points with coordinates \((1, 2)\) and \((9, 2)\), as shown in the diagram below. \includegraphics{figure_1}
  1. Show that \(a\) has the value 4 and find the value of \(b\) [3 marks]
  2. On the diagram, the region enclosed between the curve and the line \(y = 2\) is shaded. Show that the area of this shaded region is \(\frac{16}{3}\) Fully justify your answer. [6 marks]
AQA AS Paper 2 Specimen Q6
4 marks Moderate -0.3
A curve has equation \(y = 6x^2 + \frac{8}{x^2}\) and is sketched below for \(x > 0\) \includegraphics{figure_6} Find the area of the region bounded by the curve, the \(x\)-axis and the lines \(x = a\) and \(x = 2a\), where \(a > 0\), giving your answer in terms of \(a\) [4 marks]
AQA Paper 1 2019 June Q14
10 marks Standard +0.3
The graph of \(y = \frac{2x^3}{x^2 + 1}\) is shown for \(0 \leq x \leq 4\)
[diagram]
Caroline is attempting to approximate the shaded area, A, under the curve using the trapezium rule by splitting the area into \(n\) trapezia.
  1. When \(n = 4\)
    1. State the number of ordinates that Caroline uses. [1 mark]
    2. Calculate the area that Caroline should obtain using this method. Give your answer correct to two decimal places. [3 marks]
  2. Show that the exact area of \(A\) is $$16 - \ln 17$$ Fully justify your answer. [5 marks]
  3. Explain what would happen to Caroline's answer to part (a)(ii) as \(n \to \infty\) [1 mark]
AQA Paper 1 2019 June Q16
16 marks Standard +0.8
  1. \(y = e^{-x}(\sin x + \cos x)\) Find \(\frac{dy}{dx}\) Simplify your answer. [3 marks]
  2. Hence, show that $$\int e^{-x}\sin x \, dx = ae^{-x}(\sin x + \cos x) + c$$ where \(a\) is a rational number. [2 marks]
  3. A sketch of the graph of \(y = e^{-x}\sin x\) for \(x \geq 0\) is shown below. The areas of the finite regions bounded by the curve and the \(x\)-axis are denoted by \(A_1, A_2, \ldots, A_n, \ldots\) \includegraphics{figure_16c}
    1. Find the exact value of the area \(A_1\) [3 marks]
    2. Show that $$\frac{A_2}{A_1} = e^{-\pi}$$ [4 marks]
    3. Given that $$\frac{A_{n+1}}{A_n} = e^{-\pi}$$ show that the exact value of the total area enclosed between the curve and the \(x\)-axis is $$\frac{1 + e^\pi}{2(e^\pi - 1)}$$ [4 marks]
AQA Paper 2 2018 June Q3
1 marks Easy -1.8
The graph of \(y = x^3\) is shown. \includegraphics{figure_1} Find the total shaded area. Circle your answer. [1 mark] \(-68\) 60 68 128
AQA Paper 2 2024 June Q2
1 marks Easy -1.2
The graph of \(y = f(x)\) intersects the \(x\)-axis at \((-3, 0)\), \((0, 0)\) and \((2, 0)\) as shown in the diagram below. \includegraphics{figure_2} The shaded region \(A\) has an area of 189 The shaded region \(B\) has an area of 64 Find the value of \(\int_{-3}^{2} f(x) \, dx\) Circle your answer. [1 mark] \(-253\) \(\quad\) \(-125\) \(\quad\) \(125\) \(\quad\) \(253\)
AQA Paper 3 2022 June Q2
1 marks Easy -1.8
The shaded region, shown in the diagram below, is defined by $$x^2 - 7x + 7 \leq y \leq 7 - 2x$$ \includegraphics{figure_2} Identify which of the following gives the area of the shaded region. Tick (\(\checkmark\)) one box. [1 mark] \(\int (7 - 2x) \, dx - \int (x^2 - 7x + 7) \, dx\) \(\int_0^5 (x^2 - 5x) \, dx\) \(\int_0^5 (5x - x^2) \, dx\) \(\int_0^5 (x^2 - 9x + 14) \, dx\)
AQA Paper 3 Specimen Q1
1 marks Easy -1.8
The graph of \(y = x^2 - 9\) is shown below. \includegraphics{figure_1} Find the area of the shaded region. Circle your answer. [1 mark] \(-18\) \quad\quad \(-6\) \quad\quad \(6\) \quad\quad \(18\)
Edexcel AS Paper 1 Q15
Challenging +1.2
\includegraphics{figure_5} Figure 5 shows a sketch of part of the curve \(y = 2x + \frac{8}{x^2} - 5\), \(x > 0\). The point \(A(4, \frac{7}{2})\) lies on C. The line \(l\) is the tangent to C at the point A. The region \(R\), shown shaded in figure 5 is bounded by the line \(l\), the curve C, the line with equation \(x = 1\) and the \(x\)-axis. Find the exact area of \(R\). (Solutions based entirely on graphical or numerical methods are not acceptable.)
OCR PURE Q5
6 marks Standard +0.3
In this question you must show detailed reasoning. The diagram shows part of the graph of \(y = x^3 - 4x\). \includegraphics{figure_3} Determine the total area enclosed by the curve and the \(x\)-axis. [6]
Edexcel CP1 2021 June Q5
7 marks Moderate -0.3
  1. Evaluate the improper integral $$\int_1^{\infty} 2e^{-\frac{1}{2}x} dx$$ [3]
  2. The air temperature, \(\theta ^{\circ}C\), on a particular day in London is modelled by the equation $$\theta = 8 - 5\sin\left(\frac{\pi}{12}t\right) - \cos\left(\frac{\pi}{6}t\right) \quad 0 \leq t \leq 24$$ where \(t\) is the number of hours after midnight.
    1. Use calculus to show that the mean air temperature on this day is \(8^{\circ}C\), according to the model. [3] Given that the actual mean air temperature recorded on this day was higher than \(8^{\circ}C\),
    2. explain how the model could be refined. [1]
OCR MEI Further Mechanics Major 2023 June Q8
8 marks Challenging +1.8
\includegraphics{figure_8} The diagram shows the shaded region R bounded by the curve \(y = \sqrt{3x + 4}\), the \(x\)-axis, the \(y\)-axis, and the straight line that passes through the points \((k, 0)\) and \((4, 4)\), where \(0 < k < 4\). Region R is occupied by a uniform lamina.
  1. Determine, in terms of \(k\), an expression for the \(y\)-coordinate of the centre of mass of the lamina. Give your answer in the form \(\frac{a + bk}{c + dk}\), where \(a\), \(b\), \(c\) and \(d\) are integers to be determined. [6]
  2. Show that the \(y\)-coordinate of the centre of mass of the lamina cannot be \(\frac{3}{2}\). [2]
WJEC Unit 1 2019 June Q16
8 marks Standard +0.8
The diagram below shows a curve with equation \(y = (x + 2)(x - 2)(x + 1)\). \includegraphics{figure_16} Calculate the total area of the two shaded regions. [8]
WJEC Unit 1 2022 June Q11
15 marks Standard +0.3
The diagram below shows a sketch of the curve \(y = f(x)\), where \(f(x) = 10x + 3x^2 - x^3\). The curve intersects the \(x\)-axis at the origin \(O\) and at the points \(A(-2, 0)\), \(B(5, 0)\). The tangent to the curve at the point \(C(2, 24)\) intersects the \(y\)-axis at the point \(D\). \includegraphics{figure_11}
  1. Find the coordinates of \(D\). [5]
  2. Find the area of the shaded region. [6]
  3. Determine the range of values of \(x\) for which \(f(x)\) is an increasing function. [4]
WJEC Unit 1 2023 June Q13
12 marks Standard +0.3
  1. Find \(\int \left(4x^{-\frac{2}{3}} + 5x^3 + 7\right) dx\). [3]
  2. The diagram below shows the graph of \(y = x(x + 6)(x - 3)\). \includegraphics{figure_13} Calculate the total area of the regions enclosed by the graph and the \(x\)-axis. [9]
WJEC Unit 1 2024 June Q14
8 marks Moderate -0.3
The diagram below shows a sketch of the curve C with equation \(y = 2 - 3x - 2x^2\) and the line L with equation \(y = x + 2\). The curve and the line intersect the coordinate axes at the points A and B. \includegraphics{figure_14}
  1. Write down the coordinates of A and B. [2]
  2. Calculate the area enclosed by C and L. [6]
WJEC Unit 1 Specimen Q17
12 marks Standard +0.3
\includegraphics{figure_17} The diagram above shows a sketch of the curve \(y = 3x - x^2\). The curve intersects the \(x\)-axis at the origin and at the point \(A\). The tangent to the curve at the point \(B(2, 2)\) intersects the \(x\)-axis at the point \(C\).
  1. Find the equation of the tangent to the curve at \(B\). [4]
  2. Find the area of the shaded region. [8]
WJEC Unit 3 2023 June Q9
8 marks Moderate -0.3
The aerial view of a patio under construction is shown below. \includegraphics{figure_9} The curved edge of the patio is described by the equation \(9x^2 + 16y^2 = 144\), where \(x\) and \(y\) are measured in metres. To construct the patio, the area enclosed by the curve and the coordinate axes is to be covered with a layer of concrete of depth 0.06 m.
  1. Show that the volume of concrete required for the construction of the patio is given by \(0.015 \int_0^4 \sqrt{144 - 9x^2}\,dx\). [3]
  2. Use the trapezium rule with six ordinates to estimate the volume of concrete required. [4]
  3. State whether your answer in part (b) is an overestimate or an underestimate of the volume required. Give a reason for your answer. [1]
SPS SPS SM 2020 June Q13
6 marks Standard +0.3
\includegraphics{figure_5} Figure 5 shows a sketch of the curve \(C\) with equation \(y = (x - 2)^2(x + 3)\) The region \(R\), shown shaded in Figure 5, is bounded by \(C\), the vertical line passing through the maximum turning point of \(C\) and the \(x\)-axis. Find the exact area of \(R\). *(Solutions based entirely on graphical or numerical methods are not acceptable.)* [6]
SPS SPS FM 2020 December Q7
7 marks Standard +0.3
The diagram below shows part of a curve C with equation \(y = 1 + 3x - \frac{1}{2}x^2\). \includegraphics{figure_7}
  1. The curve crosses the \(y\) axis at the point A. The straight line L is normal to the curve at A and meets the curve again at B. Find the equation of L and the \(x\) coordinate of the point B. [4]
  2. The region R is bounded by the curve C and the line L. Find the exact area of R. [3]