1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)

333 questions

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OCR C3 Q1
4 marks Moderate -0.5
Show that $$\int_1^7 \frac{2}{4x-1} \, dx = \ln 3.$$ [4]
OCR MEI C3 Q2
18 marks Standard +0.3
Fig. 9 shows the curve \(y = f(x)\), where $$f(x) = (e^x - 2)^2 - 1, x \in \mathbb{R}.$$ The curve crosses the x-axis at O and P, and has a turning point at Q. \includegraphics{figure_9}
  1. Find the exact x-coordinate of P. [2]
  2. Show that the x-coordinate of Q is \(\ln 2\) and find its y-coordinate. [4]
  3. Find the exact area of the region enclosed by the curve and the x-axis. [5]
The domain of f(x) is now restricted to \(x \geqslant \ln 2\).
  1. Find the inverse function \(f^{-1}(x)\). Write down its domain and range, and sketch its graph on the copy of Fig. 9. [7]
OCR MEI C3 Q2
18 marks Standard +0.3
Fig. 8 shows the line \(y = x\) and parts of the curves \(y = f(x)\) and \(y = g(x)\), where $$f(x) = e^{x-1}, \quad g(x) = 1 + \ln x.$$ The curves intersect the axes at the points A and B, as shown. The curves and the line \(y = x\) meet at the point C. \includegraphics{figure_8}
  1. Find the exact coordinates of A and B. Verify that the coordinates of C are \((1, 1)\). [5]
  2. Prove algebraically that \(g(x)\) is the inverse of \(f(x)\). [2]
  3. Evaluate \(\int_0^1 f(x) \, dx\), giving your answer in terms of \(e\). [3]
  4. Use integration by parts to find \(\int \ln x \, dx\). Hence show that \(\int_{e^{-1}}^1 g(x) \, dx = \frac{1}{e}\). [6]
  5. Find the area of the region enclosed by the lines OA and OB, and the arcs AC and BC. [2]
OCR MEI C3 Q5
4 marks Moderate -0.3
Show that \(\int_1^4 \frac{x}{x^2 + 2} \, dx = \frac{1}{2} \ln 6\). [4]
OCR C4 2006 June Q6
8 marks Standard +0.3
  1. Show that the substitution \(u = e^x + 1\) transforms \(\int \frac{e^{2x}}{e^x + 1} dx\) to \(\int \frac{u - 1}{u} du\). [3]
  2. Hence show that \(\int_0^1 \frac{e^{2x}}{e^x + 1} dx = e - 1 - \ln\left(\frac{e + 1}{2}\right)\). [5]
Edexcel C4 Q6
13 marks Standard +0.8
  1. Find \(\int \tan^2 x \, dx\). [3]
  2. Show that $$\int \tan x \, dx = \ln|\sec x| + c,$$ where \(c\) is an arbitrary constant. [4]
\includegraphics{figure_1} Figure 1 shows part of the curve with equation \(y = x^2 \tan x\). The shaded region bounded by the curve, the \(x\)-axis and the line \(x = \frac{\pi}{3}\) is rotated through \(2\pi\) radians about the \(x\)-axis.
  1. Show that the volume of the solid formed is \(\frac{1}{18}\pi^2(6\sqrt{3} - \pi) - \pi \ln 2\). [6]
OCR C4 Q8
12 marks Challenging +1.2
  1. Find \(\int \tan^2 x \, dx\). [3]
  2. Show that $$\int \tan x \, dx = \ln |\sec x| + c,$$ where \(c\) is an arbitrary constant. [4]
\includegraphics{figure_8} The diagram shows part of the curve with equation \(y = x^{\frac{1}{2}} \tan x\). The shaded region bounded by the curve, the \(x\)-axis and the line \(x = \frac{\pi}{3}\) is rotated through \(360°\) about the \(x\)-axis.
  1. Show that the volume of the solid formed is \(\frac{1}{18}\pi^2(6\sqrt{3} - \pi) - \pi \ln 2\). [5]
OCR MEI C4 Q1
18 marks Moderate -0.3
In a chemical process, the mass \(M\) grams of a chemical at time \(t\) minutes is modelled by the differential equation $$\frac{dM}{dt} = \frac{M}{t(1+t^2)}.$$
  1. Find \(\int \frac{t}{1+t^2} dt\). [3]
  2. Find constants \(A\), \(B\) and \(C\) such that $$\frac{1}{t(1+t^2)} = \frac{A}{t} + \frac{Bt+C}{1+t^2}.$$ [5]
  3. Use integration, together with your results in parts (i) and (ii), to show that $$M = \frac{Kt}{\sqrt{1+t^2}},$$ where \(K\) is a constant. [6]
  4. When \(t = 1\), \(M = 25\). Calculate \(K\). What is the mass of the chemical in the long term? [4]
OCR MEI C4 Q2
8 marks Standard +0.3
  1. Express \(\cos \theta + \sqrt{3} \sin \theta\) in the form \(R \cos(\theta - \alpha)\), where \(R > 0\) and \(\alpha\) is acute, expressing \(\alpha\) in terms of \(\pi\). [4]
  2. Write down the derivative of \(\tan \theta\). Hence show that \(\int_0^{\frac{\pi}{6}} \frac{1}{(\cos \theta + \sqrt{3} \sin \theta)^2} d\theta = \frac{\sqrt{3}}{4}\). [4]
OCR MEI C4 Q3
18 marks Standard +0.3
In a chemical process, the mass \(M\) grams of a chemical at time \(t\) minutes is modelled by the differential equation $$\frac{dM}{dt} = -\frac{M}{2(1 + \frac{t}{2})}$$
  1. Find \(\int \frac{1}{1 + \frac{t}{2}} dt\) [3]
  2. Find constants \(A\), \(B\) and \(C\) such that $$\frac{1}{t(1 + \frac{t}{2})} = \frac{A}{t} + \frac{Bt + C}{1 + \frac{t}{2}}$$ [5]
  3. Use integration, together with your results in parts (i) and (ii), to show that $$M \sim \frac{K}{.1 + \frac{t}{2}}$$ where \(K\) is a constant. [6]
  4. When \(t = 1\), \(M = 25\). Calculate \(K\) What is the mass of the chemical in the long term? [4]
OCR C4 Q9
8 marks Standard +0.3
  1. Express \(\cos\theta + \sqrt{3}\sin\theta\) in the form \(R\cos(\theta - \alpha)\), where \(R > 0\) and \(\alpha\) is acute, expressing \(\alpha\) in terms of \(\pi\). [4]
  2. Write down the derivative of \(\tan\theta\). Hence show that \(\int_0^{\frac{\pi}{3}} \frac{1}{(\cos\theta + \sqrt{3}\sin\theta)^2} \, d\theta = \frac{\sqrt{3}}{4}\). [4]
OCR M1 Q3
11 marks Moderate -0.3
A motorcyclist starts from rest at a point \(O\) and travels in a straight line. His velocity after \(t\) seconds is \(v\) m s\(^{-1}\), for \(0 \leq t \leq T\), where \(v = 7.2t - 0.45t^2\). The motorcyclist's acceleration is zero when \(t = T\).
  1. Find the value of \(T\). [4]
  2. Show that \(v = 28.8\) when \(t = T\). [1]
For \(t \geq T\) the motorcyclist travels in the same direction as before, but with constant speed \(28.8\) m s\(^{-1}\).
  1. Find the displacement of the motorcyclist from \(O\) when \(t = 31\). [6]
OCR H240/02 2020 November Q1
9 marks Easy -1.3
  1. Differentiate the following with respect to \(x\).
    1. \((2x + 3)^7\) [2]
    2. \(x^3 \ln x\) [3]
  2. Find \(\int \cos 5x \, dx\). [2]
  3. Find the equation of the curve through \((1, 3)\) for which \(\frac{dy}{dx} = 6x - 5\). [2]
OCR H240/02 2023 June Q3
3 marks Moderate -0.8
In this question you must show detailed reasoning. Find the exact area of the region enclosed by the curve \(y = \frac{1}{x+2}\), the two axes and the line \(x = 2.5\). [3]
AQA AS Paper 1 2023 June Q8
7 marks Standard +0.3
  1. Show that $$\int_1^a \left(6 - \frac{12}{\sqrt{x}}\right) dx = 6a - 24\sqrt{a} + 18$$ [3 marks]
  2. The curve \(y = 6 - \frac{12}{\sqrt{x}}\), the line \(x = 1\) and the line \(x = a\) are shown in the diagram below. The shaded region \(R_1\) is bounded by the curve, the line \(x = 1\) and the \(x\)-axis. The shaded region \(R_2\) is bounded by the curve, the line \(x = a\) and the \(x\)-axis. \includegraphics{figure_8} It is given that the areas of \(R_1\) and \(R_2\) are equal. Find the value of \(a\) Fully justify your answer. [4 marks]
AQA AS Paper 2 2023 June Q3
5 marks Moderate -0.8
  1. Find \(\int \left(2x^3 + \frac{8}{x^2}\right) dx\) [3 marks]
  2. A curve has gradient function \(\frac{dy}{dx} = 2x^3 + \frac{8}{x^2}\) The \(x\)-intercept of the curve is at the point \((2, 0)\) Find the equation of the curve. [2 marks]
AQA Paper 3 2018 June Q8
9 marks Standard +0.3
  1. Prove the identity \(\frac{\sin 2x}{1 + \tan^2 x} = 2\sin x \cos^3 x\) [3 marks]
  2. Hence find \(\int \frac{4\sin 4\theta}{1 + \tan^2 2\theta} d\theta\) [6 marks]
AQA Paper 3 2024 June Q6
5 marks Easy -1.2
\begin{enumerate}[label=(\alph*)] \item Find \(\int \left(6x^2 - \frac{5}{\sqrt{x}}\right) dx\) [3 marks] \item The gradient of a curve is given by $$\frac{dy}{dx} = 6x^2 - \frac{5}{\sqrt{x}}$$ The curve passes through the point \((4, 90)\). Find the equation of the curve. [2 marks]
Edexcel AS Paper 1 Specimen Q5
5 marks Moderate -0.3
Given that $$f(x) = 2x + 3 + \frac{12}{x^2}, \quad x > 0$$ show that \(\int_1^{2\sqrt{2}} f(x)\,dx = 16 + 3\sqrt{2}\) [5]
OCR MEI Paper 2 Specimen Q3
3 marks Easy -1.2
Evaluate \(\int_0^{\frac{\pi}{12}} \cos 3x \, dx\), giving your answer in exact form. [3]
WJEC Unit 3 Specimen Q8
14 marks Standard +0.3
  1. Integrate
    1. \(e^{-3x+5}\) [2]
    2. \(x^2 \ln x\) [4]
  2. Use an appropriate substitution to show that $$\int_0^{\frac{1}{2}} \frac{x^2}{\sqrt{1-x^2}} dx = \frac{\pi}{12} - \frac{\sqrt{3}}{8}.$$ [8]
WJEC Unit 4 2019 June Q6
9 marks Standard +0.3
A particle \(P\) of mass \(0.5\) kg moves on a horizontal plane such that its velocity vector \(\mathbf{v}\) ms\(^{-1}\) at time \(t\) seconds is given by $$\mathbf{v} = 12\cos(3t)\mathbf{i} - 5\sin(2t)\mathbf{j}.$$
  1. Find an expression for the force acting on \(P\) at time \(t\) s. [3]
  2. Given that when \(t = 0\), \(P\) has position vector \((\mathbf{4i} + \mathbf{7j})\) m relative to the origin \(O\), find an expression for the position vector of \(P\) at time \(t\) s. [4]
  3. Hence determine the distance of \(P\) from \(O\) at time \(t = \frac{\pi}{2}\). [2]
SPS SPS FM 2020 December Q2
4 marks Moderate -0.3
Let \(a, b\) satisfy \(0 < a < b\).
  1. Find, in terms of \(a\) and \(b\), the value of $$\int_a^b \frac{81}{x^4} dx$$ [2]
  2. Explaining clearly any limiting processes used, find the value of \(a\), given that $$\int_a^{\infty} \frac{81}{x^4} dx = \frac{216}{125}$$ [2]
SPS SPS FM 2021 March Q7
6 marks Challenging +1.2
This is the graph of \(y = \frac{5}{4x-3} - \frac{3}{2}\) \includegraphics{figure_7} Find the area between the graph, the \(x\) axis, and the lines \(x = 1\) and \(x = 7\) in the form \(a \ln b + c\) where \(a, b, c \in Q\) [6]
SPS SPS FM 2021 April Q1
11 marks Moderate -0.3
  1. Differentiate the following with respect to \(x\), simplifying your answers fully
    1. \(y = e^{3x} + \ln 2x\) [1]
    2. \(y = (5 + x^2)^{\frac{3}{2}}\) [1]
    3. \(y = \frac{2x}{(5-3x^2)^{\frac{1}{2}}}\) [2]
    4. \(y = e^{-\frac{3}{x}} \ln(1 + x^3)\) [2]
  2. Integrate with respect to \(x\)
    1. \(\frac{7}{(2x-5)^8} - \frac{3}{2x-5}\) [2]
    2. \(\frac{4x^2+5x-3}{2x-5}\) [3]