The gradient at any point \((x, y)\) on a curve is proportional to \(\sqrt{y}\).
Given that the curve passes through the point with coordinates \((0, 4)\),
- show that the equation of the curve can be written in the form
$$2\sqrt{y} = kx + 4,$$
where \(k\) is a positive constant. [5]
Given also that the curve passes through the point with coordinates \((2, 9)\),
- find the equation of the curve in the form \(y = \text{f}(x)\). [4]