Given that \(y = \arcsin x\), \(-1 \leqslant x < 1\),
- show that \(\frac{dy}{dx} = \frac{1}{\sqrt{1-x^2}}\). [3]
Given that \(f(x) = \frac{3x + 2}{\sqrt{4 - x^2}}\),
- show that the mean value of \(f(x)\) over the interval \([0, \sqrt{2}]\), is
$$\frac{\pi\sqrt{2}}{4} + A\sqrt{2} - A,$$
where \(A\) is a constant to be determined. [6]