Edexcel FS1 AS (Further Statistics 1 AS) 2018 June

Question 1
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  1. A researcher is investigating the distribution of orchids in a field. He believes that the Poisson distribution with a mean of 1.75 may be a good model for the number of orchids in each square metre. He randomly selects 150 non-overlapping areas, each of one square metre, and counts the number of orchids present in each square.
The results are recorded in the table below.
Number of orchids in
each square metre
0123456
Number of squares304235261160
He calculates the expected frequencies as follows
Number of orchids in
each square metre
012345More than 5
Number of squares26.0745.6239.9123.2810.193.57\(r\)
  1. Find the value of \(r\) giving your answer to 2 decimal places. The researcher will test, at the \(5 \%\) level of significance, whether or not the data can be modelled by a Poisson distribution with mean 1.75
  2. State clearly the hypotheses required to test whether or not this Poisson distribution is a suitable model for these data. The test statistic for this test is 2.0 and the number of degrees of freedom to be used is 4
  3. Explain fully why there are 4 degrees of freedom.
  4. Stating your critical value clearly, determine whether or not these data support the researcher's belief. The researcher works in another field where the number of orchids in each square metre is known to have a Poisson distribution with mean 1.5 He randomly selects 200 non-overlapping areas, each of one square metre, in this second field, and counts the number of orchids present in each square.
  5. Using a Poisson approximation, show that the probability that he finds at least one square with exactly 6 orchids in it is 0.506 to 3 decimal places.
Question 2
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  1. The number of heaters, \(H\), bought during one day from Warmup supermarket can be modelled by a Poisson distribution with mean 0.7
    1. Calculate \(\mathrm { P } ( H \geqslant 2 )\)
    The number of heaters, \(G\), bought during one day from Pumraw supermarket can be modelled by a Poisson distribution with mean 3, where \(G\) and \(H\) are independent.
  2. Show that the probability that a total of fewer than 4 heaters are bought from these two supermarkets in a day is 0.494 to 3 decimal places.
  3. Calculate the probability that a total of fewer than 4 heaters are bought from these two supermarkets on at least 5 out of 6 randomly chosen days. December was particularly cold. Two days in December were selected at random and the total number of heaters bought from these two supermarkets was found to be 14
  4. Test whether or not the mean of the total number of heaters bought from these two supermarkets had increased. Use a \(5 \%\) level of significance and state your hypotheses clearly.
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Question 3
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  1. A fair six-sided black die has faces numbered \(1,2,2,3,3\) and 4
The random variable \(B\) represents the score when the black die is rolled.
  1. Write down the value of \(\mathrm { E } ( B )\) A white die has 6 faces numbered \(1,1,2,4,5\) and \(c\) where \(c > 5\)
    The discrete random variable \(W\) represents the score when the white die is rolled and has probability distribution given by
    \(w\)1245\(c\)
    \(\mathrm { P } ( W = w )\)\(a + b\)\(a\)0.3\(a\)\(b\)
    Greg and Nilaya play a game with these dice.
    Greg throws the black die and Nilaya throws the white die. Greg wins the game if he scores at least two more than Nilaya, otherwise Greg loses.
    The probability of Greg winning the game is \(\frac { 1 } { 6 }\)
  2. Find the value of \(a\) and the value of \(b\) Show your working clearly. The random variable \(X = 2 W - 5\)
    Given that \(\mathrm { E } ( X ) = 2.6\)
  3. find the exact value of \(\operatorname { Var } ( X )\)
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Question 4
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  1. Abram carried out a survey of two treatments for a plant fungus. The contingency table below shows the results of a survey of a random sample of 125 plants with the fungus.
\multirow{2}{*}{}Treatment
No actionPlant sprayed oncePlant sprayed every day
\multirow{3}{*}{Outcome}Plant died within a month151625
Plant survived for 1-6 months82510
Plant survived beyond 6 months7145
Abram calculates expected frequencies to carry out a suitable test. Seven of these are given in the partly-completed table below.
\multirow{2}{*}{}Treatment
No actionPlant sprayed oncePlant sprayed every day
\multirow{3}{*}{Outcome}Plant died within a month17.92
Plant survived for 1-6 months10.3218.9213.76
Plant survived beyond 6 months6.2411.448.32
The value of \(\sum \frac { ( O - E ) ^ { 2 } } { E }\) for the 7 given values is 8.29
Test at the \(2.5 \%\) level of significance, whether or not there is an association between the treatment of the plants and their survival. State your hypotheses and conclusion clearly.