A lorry of mass \(M\) is moving along a straight horizontal road. The engine produces a constant driving force of magnitude \(F\). The total resistance to motion is modelled as having magnitude \(kv^2\), where \(k\) is a constant, and \(v\) is the speed of the lorry.
Given the lorry moves with constant speed \(V\),
- show that \(V = \sqrt{\frac{F}{k}}\). [2]
Given instead that the lorry starts from rest,
- show that the distance travelled by the lorry in attaining a speed of \(\frac{1}{2}V\) is
$$\frac{M}{2k}\ln\left(\frac{4}{3}\right).$$ [9]