A light elastic string, of natural length \(l\) m and modulus of elasticity \(\frac{mg}{2}\) newtons, has one end fastened to a fixed point \(O\). A particle \(P\), of mass \(m\) kg, is attached to the other end of the string. \(P\) hangs in equilibrium at the point \(E\), vertically below \(O\), where \(OE = (l + e)\) m
- Find the numerical value of the ratio \(e : l\). [2 marks]
\(P\) is now pulled down a further distance \(\frac{3l}{2}\) m from \(E\) and is released from rest.
In the subsequent motion, the string remains taut. At time \(t\) s after being released, \(P\) is at a distance \(x\) m below \(E\).
- Write down a differential equation for the motion of \(P\) and show that the motion is simple harmonic. [4 marks]
- Write down the period of the motion. [2 marks]
- Find the speed with which \(P\) first passes through \(E\) again. [2 marks]
- Show that the time taken by \(P\) after it is released to reach the point \(A\) above \(E\), where \(AE = \frac{3l}{4}\) m, is \(\frac{2\pi}{3}\sqrt{\frac{2l}{g}}\) s. [5 marks]