6. Take \(\mathbf { g } = \mathbf { 1 0 } \mathbf { m s } ^ { - \mathbf { 2 } }\) in this question.
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A golfer hits a ball from a point \(T\) at an angle \(\theta\) to the horizontal, where \(\sin \theta = \frac { 5 } { 13 }\), giving it an initial speed of \(52 \mathrm {~ms} ^ { - 1 }\). The ball lands on top of a mound, 15 m above the level of \(T\), as shown.
- Show that the height, \(y \mathrm {~m}\), of the ball above \(T\) at time \(t\) seconds after it was hit is given by
$$y = 20 t - 5 t ^ { 2 } .$$
- Find the time for which the ball is in flight.
- Find the horizontal distance travelled by the ball.
- Show that, if the ball is \(x \mathrm {~m}\) horizontally from \(T\) at time \(t\) seconds, then
$$y = \frac { 5 } { 12 } x - \frac { 5 } { 2304 } x ^ { 2 } .$$
- Name a force that has been ignored in your mathematical model and state whether the answer to part (b) would be larger or smaller if this force were taken into account.