\includegraphics{figure_1}
Figure 1 shows the curve \(y = f(x)\) which has a maximum point at \((-45, 7)\) and a minimum point at \((135, -1)\).
- Showing the coordinates of any stationary points, sketch on separate diagrams the graphs of
- \(y = f(|x|)\),
- \(y = 1 + 2f(x)\). [6]
Given that
$$f(x) = A + 2\sqrt{2} \cos x^{\circ} - 2\sqrt{2} \sin x^{\circ}, \quad x \in \mathbb{R}, \quad -180 \leq x \leq 180,$$
where \(A\) is a constant,
- show that f(x) can be expressed in the form
$$f(x) = A + R \cos (x + \alpha)^{\circ},$$
where \(R > 0\) and \(0 < \alpha < 90\), [3]
- state the value of \(A\), [1]
- find, to \(1\) decimal place, the \(x\)-coordinates of the points where the curve \(y = f(x)\) crosses the \(x\)-axis. [4]