Edexcel M2 (Mechanics 2) 2006 January

Question 1
View details
  1. A brick of mass 3 kg slides in a straight line on a horizontal floor. The brick is modelled as a particle and the floor as a rough plane. The initial speed of the brick is \(8 \mathrm {~m} \mathrm {~s} ^ { - 1 }\). The brick is brought to rest after moving 12 m by the constant frictional force between the brick and the floor.
    1. Calculate the kinetic energy lost by the brick in coming to rest, stating the units of your answer.
    2. Calculate the coefficient of friction between the brick and the floor.
    3. A particle \(P\) of mass 0.4 kg is moving so that its position vector \(\mathbf { r }\) metres at time \(t\) seconds is given by
    $$\mathbf { r } = \left( t ^ { 2 } + 4 t \right) \mathbf { i } + \left( 3 t - t ^ { 3 } \right) \mathbf { j } .$$
  2. Calculate the speed of \(P\) when \(t = 3\). When \(t = 3\), the particle \(P\) is given an impulse ( \(8 \mathbf { i } - 12 \mathbf { j }\) ) N s.
  3. Find the velocity of \(P\) immediately after the impulse.
Question 3
View details
3. A car of mass 1000 kg is moving along a straight horizontal road. The resistance to motion is modelled as a constant force of magnitude \(R\) newtons. The engine of the car is working at a rate of 12 kW . When the car is moving with speed \(15 \mathrm {~m} \mathrm {~s} ^ { - 1 }\), the acceleration of the car is \(0.2 \mathrm {~m} \mathrm {~s} ^ { - 2 }\).
  1. Show that \(R = 600\). The car now moves with constant speed \(U \mathrm {~m} \mathrm {~s} ^ { - 1 }\) downhill on a straight road inclined at \(\theta\) to the horizontal, where \(\sin \theta = \frac { 1 } { 40 }\). The engine of the car is now working at a rate of 7 kW . The resistance to motion from non-gravitational forces remains of magnitude \(R\) newtons.
  2. Calculate the value of \(U\).
    (5)
Question 4
View details
4. A particle \(A\) of mass \(2 m\) is moving with speed \(3 u\) in a straight line on a smooth horizontal table. The particle collides directly with a particle \(B\) of mass \(m\) moving with speed \(2 u\) in the opposite direction to \(A\). Immediately after the collision the speed of \(B\) is \(\frac { 8 } { 3 } u\) and the direction of motion of \(B\) is reversed.
  1. Calculate the coefficient of restitution between \(A\) and \(B\).
  2. Show that the kinetic energy lost in the collision is \(7 m u ^ { 2 }\). After the collision \(B\) strikes a fixed vertical wall that is perpendicular to the direction of motion of \(B\). The magnitude of the impulse of the wall on \(B\) is \(\frac { 14 } { 3 } m u\).
  3. Calculate the coefficient of restitution between \(B\) and the wall.
    (4)
Question 5
View details
5. \begin{figure}[h]
\captionsetup{labelformat=empty} \caption{Figure 1} \includegraphics[alt={},max width=\textwidth]{97fbfac6-6c1c-4a5c-ab5d-adc3193bfedc-4_805_1265_258_312}
\end{figure} Figure 1 shows a triangular lamina \(A B C\). The coordinates of \(A , B\) and \(C\) are ( 0,4 ), ( 9,0 ) and \(( 0 , - 4 )\) respectively. Particles of mass \(4 m , 6 m\) and \(2 m\) are attached at \(A , B\) and \(C\) respectively.
  1. Calculate the coordinates of the centre of mass of the three particles, without the lamina. The lamina \(A B C\) is uniform and of mass \(k m\). The centre of mass of the combined system consisting of the three particles and the lamina has coordinates \(( 4 , \lambda )\).
  2. Show that \(k = 6\).
  3. Calculate the value of \(\lambda\). The combined system is freely suspended from \(O\) and hangs at rest.
  4. Calculate, in degrees to one decimal place, the angle between \(A C\) and the vertical.
    (3) \section*{6.} \begin{figure}[h]
    \captionsetup{labelformat=empty} \caption{Figure 2} \includegraphics[alt={},max width=\textwidth]{97fbfac6-6c1c-4a5c-ab5d-adc3193bfedc-5_693_556_338_712}
    \end{figure} A ladder \(A B\), of weight \(W\) and length \(4 a\), has one end \(A\) on rough horizontal ground. The coefficient of friction between the ladder and the ground is \(\mu\). The other end \(B\) rests against a smooth vertical wall. The ladder makes an angle \(\theta\) with the horizontal, where \(\tan \theta = 2\). A load of weight \(4 W\) is placed at the point \(C\) on the ladder, where \(A C = 3 a\), as shown in Figure 2. The ladder is modelled as a uniform rod which is in a vertical plane perpendicular to the wall. The load is modelled as a particle. Given that the system is in limiting equilibrium,
Question 6
View details
  1. show that \(\mu = 0.35\).
    (6) A second load of weight \(k W\) is now placed on the ladder at \(A\). The load of weight \(4 W\) is removed from \(C\) and placed on the ladder at \(B\). The ladder is modelled as a uniform rod which is in a vertical plane perpendicular to the wall. The loads are modelled as particles. Given that the ladder and the loads are in equilibrium,
  2. find the range of possible values of \(k\).
    (7)
Question 7
View details
7. \begin{figure}[h]
\captionsetup{labelformat=empty} \caption{Figure 3} \includegraphics[alt={},max width=\textwidth]{97fbfac6-6c1c-4a5c-ab5d-adc3193bfedc-6_501_1284_306_386}
\end{figure} The object of a game is to throw a ball \(B\) from a point \(A\) to hit a target \(T\) which is placed at the top of a vertical pole, as shown in Figure 3. The point \(A\) is 1 m above horizontal ground and the height of the pole is 2 m . The pole is at a horizontal distance of 10 m from \(A\). The ball \(B\) is projected from \(A\) with a speed of \(11 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) at an angle of elevation of \(30 ^ { \circ }\). The ball hits the pole at the point \(C\). The ball \(B\) and the target \(T\) are modelled as particles.
  1. Calculate, to 2 decimal places, the time taken for \(B\) to move from \(A\) to \(C\).
  2. Show that \(C\) is approximately 0.63 m below \(T\).
    (4) The ball is thrown again from \(A\). The speed of projection of \(B\) is increased to \(V \mathrm {~m} \mathrm {~s} ^ { - 1 }\), the angle of elevation remaining \(30 ^ { \circ }\). This time \(B\) hits \(T\).
  3. Calculate the value of \(V\).
    (6)
  4. Explain why, in practice, a range of values of \(V\) would result in \(B\) hitting the target.