Edexcel F2 (Further Pure Mathematics 2) Specimen

Question 4
View details
4. $$z = - 8 + ( 8 \sqrt { } 3 ) \mathrm { i }$$
  1. Find the modulus of \(z\) and the argument of \(z\). Using de Moivre's theorem,
  2. find \(z ^ { 3 }\),
  3. find the values of \(w\) such that \(w ^ { 4 } = z\), giving your answers in the form \(a + \mathrm { i } b\), where \(a , b \in \mathbb { R }\).
Question 5
View details
5. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{cd449136-cb09-49eb-8812-c863c0e7bd4e-10_506_728_267_632} \captionsetup{labelformat=empty} \caption{Figure 1}
\end{figure} Figure 1 shows the curves given by the polar equations $$r = 2 , \quad 0 \leqslant \theta \leqslant \frac { \pi } { 2 }$$ and \(\quad r = 1.5 + \sin 3 \theta , \quad 0 \leqslant \theta \leqslant \frac { \pi } { 2 }\).
  1. Find the coordinates of the points where the curves intersect. The region \(S\), between the curves, for which \(r > 2\) and for which \(r < ( 1.5 + \sin 3 \theta )\), is shown shaded in Figure 1.
  2. Find, by integration, the area of the shaded region \(S\), giving your answer in the form \(a \pi + b \sqrt { 3 }\), where \(a\) and \(b\) are simplified fractions. $$\left[ \begin{array} { l l l } \text { Leave }
    \text { blank }
    \text { " }
    \text { " } \end{array} &
    \text { " } &
    \text { " } &
    \text { " } &
    \text { " } &
    \text { " } &
    \text { " } &
    \text { " } &
    \text { " } & \end{array} \right.$$
Question 6
View details
  1. A complex number \(z\) is represented by the point \(P\) in the Argand diagram.
    1. Given that \(| z - 6 | = | z |\), sketch the locus of \(P\).
    2. Find the complex numbers \(z\) which satisfy both \(| z - 6 | = | z |\) and \(| z - 3 - 4 \mathrm { i } | = 5\).
    The transformation \(T\) from the \(z\)-plane to the \(w\)-plane is given by \(w = \frac { 30 } { z }\).
  2. Show that \(T\) maps \(| z - 6 | = | z |\) onto a circle in the \(w\)-plane and give the cartesian equation of this circle.
Question 7
View details
  1. (a) Show that the transformation \(z = y ^ { \frac { 1 } { 2 } }\) transforms the differential equation
$$\frac { \mathrm { d } y } { \mathrm {~d} x } - 4 y \tan x = 2 y ^ { \frac { 1 } { 2 } }$$ into the differential equation $$\frac { \mathrm { d } z } { \mathrm {~d} x } - 2 z \tan x = 1$$ (b) Solve the differential equation (II) to find \(z\) as a function of \(x\).
(c) Hence obtain the general solution of the differential equation (I).
$$\left[ \begin{array} { l l l } \text { Leave }
\text { blank }
\text { " }
\text { " }
\text { " } \end{array} &
\text { " } &
\text { " } &
\text { " } &
\text { " } &
\text { " } &
\text { " } &
\text { " } & \end{array} \right.$$
Question 8
View details
  1. (a) Find the value of \(\lambda\) for which \(y = \lambda x \sin 5 x\) is a particular integral of the differential equation
$$\frac { \mathrm { d } ^ { 2 } y } { \mathrm {~d} x ^ { 2 } } + 25 y = 3 \cos 5 x$$ (b) Using your answer to part (a), find the general solution of the differential equation $$\frac { \mathrm { d } ^ { 2 } y } { \mathrm {~d} x ^ { 2 } } + 25 y = 3 \cos 5 x$$ Given that at \(x = 0 , y = 0\) and \(\frac { \mathrm { d } y } { \mathrm {~d} x } = 5\),
(c) find the particular solution of this differential equation, giving your solution in the form \(y = \mathrm { f } ( x )\).
(d) Sketch the curve with equation \(y = \mathrm { f } ( x )\) for \(0 \leqslant x \leqslant \pi\).