A particle \(P\) moves in a straight line starting from a point \(O\) and comes to rest \(35\) s later. At time \(t\) s after leaving \(O\), the velocity \(v\) m s\(^{-1}\) of \(P\) is given by
$$v = \frac{4}{5}t^2 \quad 0 \leq t \leq 5,$$
$$v = 2t + 10 \quad 5 \leq t \leq 15,$$
$$v = a + bt^2 \quad 15 \leq t \leq 35,$$
where \(a\) and \(b\) are constants such that \(a > 0\) and \(b < 0\).
- Show that the values of \(a\) and \(b\) are \(49\) and \(-0.04\) respectively. [3]
- Sketch the velocity-time graph. [4]
- Find the total distance travelled by \(P\) during the \(35\) s. [5]