2 A student is studying the speed of sound, \(u\), in a gas under different conditions.
He assumes that \(u\) depends on the pressure, \(p\), of the gas, the density, \(\rho\), of the gas and the wavelength, \(\lambda\), of the sound in the relationship \(u = k p ^ { \alpha } \rho ^ { \beta } \lambda ^ { \gamma }\), where \(k\) is a dimensionless constant. (The wavelength of a sound is the distance between successive peaks in the sound wave.)
- Use the fact that density is mass per unit volume to find \([ \rho ]\).
- Given that the units of \(p\) are \(\mathrm { Nm } ^ { - 2 }\), determine the values of \(\alpha , \beta\) and \(\gamma\).
- Comment on what the value of \(\gamma\) means about how fast sounds of different wavelengths travel through the gas.
The student carries out two experiments, \(A\) and \(B\), to measure \(u\). Only the density of the gas varies between the experiments, all other conditions being unchanged. He finds that the value of \(u\) in experiment \(B\) is double the value in experiment \(A\).
- By what factor has the density of the gas in experiment \(A\) been multiplied to give the density of the gas in experiment \(B\) ?
Particles \(A\) of mass \(2 m\) and \(B\) of mass \(m\) are on a smooth horizontal floor. \(A\) is moving with speed \(u\) directly towards a vertical wall, and \(B\) is at rest between \(A\) and the wall (see diagram).
\includegraphics[max width=\textwidth, alt={}, center]{d6a0d7a6-4166-4c26-a461-39b2414c0412-03_211_795_285_244}
\(A\) collides directly with \(B\). The coefficient of restitution in this collision is \(\frac { 1 } { 2 }\).
\(B\) then collides with the wall, rebounds, and collides with \(A\) for a second time. - Show that the speed of \(B\) after its second collision with \(A\) is \(\frac { 1 } { 2 } u\).
The first collision between \(A\) and \(B\) occurs at a distance \(d\) from the wall. The second collision between \(A\) and \(B\) occurs at a distance \(\frac { 1 } { 5 } d\) from the wall.
- Find the coefficient of restitution for the collision between \(B\) and the wall.
\section*{Total Marks for Question Set 3: 28}
\section*{Mark scheme}
\section*{Marking Instructions}
a An element of professional judgement is required in the marking of any written paper. Remember that the mark scheme is designed to assist in marking incorrect solutions. Correct solutions leading to correct answers are awarded full marks but work must not always be judged on the answer alone, and answers that are given in the question, especially, must be validly obtained; key steps in the working must always be looked at and anything unfamiliar must be investigated thoroughly. Correct but unfamiliar or unexpected methods are often signalled by a correct result following an apparently incorrect method. Such work must be carefully assessed.
b The following types of marks are available.
\section*{M}
A suitable method has been selected and applied in a manner which shows that the method is essentially understood. Method marks are not usually lost for numerical errors, algebraic slips or errors in units. However, it is not usually sufficient for a candidate just to indicate an intention of using some method or just to quote a formula; the formula or idea must be applied to the specific problem in hand, e.g. by substituting the relevant quantities into the formula. In some cases the nature of the errors allowed for the award of an M mark may be specified.
A method mark may usually be implied by a correct answer unless the question includes the DR statement, the command words "Determine" or "Show that", or some other indication that the method must be given explicitly.
\section*{A}
Accuracy mark, awarded for a correct answer or intermediate step correctly obtained. Accuracy marks cannot be given unless the associated Method mark is earned (or implied). Therefore M0 A1 cannot ever be awarded.
\section*{B}
Mark for a correct result or statement independent of Method marks.
\section*{E}
A given result is to be established or a result has to be explained. This usually requires more working or explanation than the establishment of an unknown result.
Unless otherwise indicated, marks once gained cannot subsequently be lost, e.g. wrong working following a correct form of answer is ignored. Sometimes this is reinforced in the mark scheme by the abbreviation isw. However, this would not apply to a case where a candidate passes through the correct answer as part of a wrong argument.
c When a part of a question has two or more 'method' steps, the M marks are in principle independent unless the scheme specifically says otherwise; and similarly where there are several B marks allocated. (The notation 'dep*' is used to indicate that a particular mark is dependent on an earlier, asterisked, mark in the scheme.) Of course, in practice it may happen that when a candidate has once gone wrong in a part of a question, the work from there on is worthless so that no more marks can sensibly be given. On the other hand, when two or more steps are successfully run together by the candidate, the earlier marks are implied and full credit must be given.
d The abbreviation FT implies that the A or B mark indicated is allowed for work correctly following on from previously incorrect results. Otherwise, A and B marks are given for correct work only - differences in notation are of course permitted. A (accuracy) marks are not given for answers obtained from incorrect working. When A or B marks are awarded for work at an intermediate stage of a solution, there may be various alternatives that are equally acceptable. In such cases, what is acceptable will be detailed in the mark scheme. Sometimes the answer to one part of a question is used in a later part of the same question. In this case, A marks will often be 'follow through'.
e We are usually quite flexible about the accuracy to which the final answer is expressed; over-specification is usually only penalised where the scheme explicitly says so.
- When a value is given in the paper only accept an answer correct to at least as many significant figures as the given value.
- When a value is not given in the paper accept any answer that agrees with the correct value to \(\mathbf { 3 ~ s } . \mathbf { f }\). unless a different level of accuracy has been asked for in the question, or the mark scheme specifies an acceptable range.
Follow through should be used so that only one mark in any question is lost for each distinct accuracy error.
Candidates using a value of \(9.80,9.81\) or 10 for \(g\) should usually be penalised for any final accuracy marks which do not agree to the value found with 9.8 which is given in the rubric.
f Rules for replaced work and multiple attempts:
- If one attempt is clearly indicated as the one to mark, or only one is left uncrossed out, then mark that attempt and ignore the others.
- If more than one attempt is left not crossed out, then mark the last attempt unless it only repeats part of the first attempt or is substantially less complete.
- if a candidate crosses out all of their attempts, the assessor should attempt to mark the crossed out answer(s) as above and award marks appropriately.
For a genuine misreading (of numbers or symbols) which is such that the object and the difficulty of the question remain unaltered, mark according to the scheme but following through from the candidate's data. A penalty is then applied; 1 mark is generally appropriate, though this may differ for some units. This is achieved by withholding one A or B mark in the question. Marks designated as cao may be awarded as long as there are no other errors.
If a candidate corrects the misread in a later part, do not continue to follow through. Note that a miscopy of the candidate's own working is not a misread but an accuracy error.
h If a calculator is used, some answers may be obtained with little or no working visible. Allow full marks for correct answers, provided that there is nothing in the wording of the question specifying that analytical methods are required such as the bold "In this question you must show detailed reasoning", or the command words "Show" or "Determine". Where an answer is wrong but there is some evidence of method, allow appropriate method marks. Wrong answers with no supporting method score zero.
\begin{table}[h]
\captionsetup{labelformat=empty}
\caption{Abbreviations}
| Abbreviations used in the mark scheme | Meaning |
| dep* | Mark dependent on a previous mark, indicated by *. The * may be omitted if only one previous M mark |
| cao | Correct answer only |
| ое | Or equivalent |
| rot | Rounded or truncated |
| soi | Seen or implied |
| www | Without wrong working |
| AG | Answer given |
| awrt | Anything which rounds to |
| BC | By Calculator |
| DR | This question included the instruction: In this question you must show detailed reasoning. |
\end{table}
| Question | Answer | Marks | AOs | Guidance |
| 1 | (a) | | | Initial (kinetic) energy \(= \frac { 1 } { 2 } \times m \times 8.4 ^ { 2 }\) | | Energy at \(0.8 \mathrm { rad } = \frac { 1 } { 2 } m v ^ { 2 } + m \times 9.8 \times 2.5 ( 1 - \cos 0.8 )\) | | \(=\) Initial energy | | \(v ^ { 2 } = 55.698 \ldots \Rightarrow\) speed is \(7.46 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) |
| | | | \(35.28 m\) | | Attempt to find \(\mathrm { KE } + \mathrm { PE }\) at 0.8 rad (or \(45.8 ^ { \circ }\) ) and equate to initial kinetic energy (KE must use correct formula) | | \(\mathrm { NB } \Delta h = 0.7582 \ldots\) | | SC1 for use of constant acceleration without justification |
| | \(m\) may be implied \(\frac { 1 } { 2 } m v ^ { 2 } + 7.4306 \ldots m\) | | Or subtract PE from initial KE (to give final KE) (Final KE is \(27.849 . . . m\) ) |
|
| 1 | (b) | | | Minimum energy to reach top \(= m \times 9.8 \times ( 2 \times 2.5 )\) \(= 49 \mathrm {~m}\) | | \(49 m > 35.28 m\) so insufficient energy to reach top |
| | | | Or attempt to find angle when \(v = 0 35.28 m = 24.5 m ( 1 - \cos \theta ) \left( + \frac { 1 } { 2 } m ( 0 ) ^ { 2 } \right)\) | | Condone missing \(m \theta = 2.03 \mathrm { rads }\) or \(116 ^ { \circ }\) | | Comparison between their numerical multiples of \(m\) ( \(m\) could be missing) | | Allow \(\neq\) | | and consistent ft conclusion |
| | Or attempt to find \(h\) when \(v = 0 \left( h = \frac { 35.28 } { g } \right)\) | | \(h = 3.6\) | | or comparison of their angle with \(2 \pi\) or \(180 ^ { \circ }\) | | Or show that \(h = 3.6 < 5\) or show that \(v ^ { 2 } = - 27.44 < 0\) (is not valid) |
|
| 2 | (a) | | \([ \rho ] = \mathrm { ML } ^ { - 3 }\) | | 3.3 | If M, L and T not used B0, but do not penalise any further instances of non-standard notation as long as it is used consistently. | |
| 2 | (b) | | | \([ p ] = \mathrm { MLT } ^ { - 2 } \mathrm {~L} ^ { - 2 } = \mathrm { ML } ^ { - 1 } \mathrm {~T} ^ { - 2 }\) \(\mathrm { LT } ^ { - 1 } = \mathrm { M } ^ { \alpha } \mathrm { L } ^ { - \alpha } \mathrm { T } ^ { - 2 \alpha } \mathrm { M } ^ { \beta } \mathrm { L } ^ { - 3 \beta } \mathrm {~L} ^ { \gamma }\) | | M: \(\alpha + \beta = 0\) \(\begin{aligned} | \text { T: } - 2 \alpha = - 1 | | \alpha = \frac { 1 } { 2 } , \beta = - \frac { 1 } { 2 } \end{aligned}\) \(\mathrm { L } : \quad 1 = - \alpha - 3 \beta + \gamma\) | | \(\gamma = 0 \quad\) www |
| | | 2.1 | | 3.3 | | 3.3 | | 3.4 | | 3.4 | | 1.1 | | 1.1 | | 3.4 | | 1.1 |
| Allow this mark as long as the equations for M and T are correct. | Do not allow any marks for using addition instead of multiplication |
| | | | | | | |
| 2 | (c) | Sounds of any wavelength have the same speed through the gas | E1FT | 2.2b | Follow from their \(\gamma\) : If \(\gamma > 0\) then speed increases as wavelength increases (or better - e.g. \(\gamma = 1 / 2 \rightarrow\) speed is proportional to \(\sqrt { } \lambda\) ); if \(\gamma < 0\) then speed decreases as wavelength increases (or better) | |
| | | [1] | | | |
| 2 | (d) | | \(u \propto \frac { 1 } { \sqrt { \rho } } \text { or } u = k \sqrt { \frac { p } { \rho } } \text { oe }\) | | \(\frac { 1 } { 4 }\) |
| | | | \(2 = \left( \frac { \rho _ { B } } { \rho _ { A } } \right) ^ { - \frac { 1 } { 2 } }\) | | Award if no working seen provided \(\beta = - \frac { 1 } { 2 }\) |
| Using their value of \(\beta\) Allow missing k or use of \(=\) instead of proportion symbol |
| 3 | (a) | | \(1 ^ { \text {st } }\) collision for \(A \ | B : 2 m u = 2 m v _ { A } + m v _ { B }\) \(\frac { 1 } { 2 } = \frac { v _ { B } - v _ { A } } { u }\) | | \(v _ { A } = \frac { 1 } { 2 } u\) | | \(2 ^ { \text {nd } }\) collision for \(A \ | B : 2 m \times \frac { 1 } { 2 } u + m U _ { B } = 2 m V _ { A } + m V _ { B }\) \(\begin{aligned} | \frac { 1 } { 2 } = \frac { V _ { B } - V _ { A } } { \frac { 1 } { 2 } u - U _ { B } } | | u + U _ { B } = 2 V _ { A } + V _ { B } \text { and } u - 2 U _ { B } = 4 V _ { B } - 4 V _ { A } | | \Rightarrow 3 u = 6 V _ { B } \Rightarrow V _ { B } = \frac { 1 } { 2 } u \end{aligned}\) |
| | | | Conservation of momentum | | Restitution | | Conservation of momentum | | Restitution | | AG Intermediate work towards cancellation must be seen |
| | May see \(- U _ { B }\) or \(\pm e u\) Do not allow assumed value of \(U _ { B }\) e.g. \(\frac { 1 } { 2 } u\) or \(u\). Do not allow assumed value of \(U _ { B }\) e.g. \(\frac { 1 } { 2 } u\) or \(u\). | | SC1 if assumed value for \(V _ { B }\) has been used (giving M0M0), provided \(\left| U _ { B } \right| \leq u\), direction of travel is towards A and equations are otherwise correct. |
|
| 3 | (b) | | \(v _ { B } = u\) | | Collision for \(B \ | \) wall: \(e = \pm \frac { U _ { B } } { u }\) or \(U _ { B } = \pm e u\) \(\frac { \frac { 4 } { 5 } d } { \frac { 1 } { 2 } u } = \frac { d } { u } + \frac { \frac { 1 } { 5 } d } { e u }\) | | \(\frac { 3 } { 5 } = \frac { 1 } { 5 e }\) | | So coefficient of restitution between \(B\) and wall is \(\frac { 1 } { 3 }\) |
| | | | Restitution | | May see \(V _ { 2 B }\) or similar instead of \(\pm e u\) with use of restitution at the end. | | Seeing that \(A\) travels \(\frac { 4 } { 5 } d\) at \(\frac { 1 } { 2 } u\) in the same time as \(B\) travels \(d\) at \(u\) and \(\frac { 1 } { 5 } d\) at \(e u\) | | Correctly cancelling \(d\) and \(u\) and simplifying their 3 term equation including e in the denominator |
| | Award if seen in (a). Award if seen in (a) | | Do not allow assumed rebound speed |
|