A circle has centre \(C\) which lies on the \(x\)-axis, as shown in the diagram. The line \(y = x\) meets the circle at \(A\) and \(B\). The midpoint of \(AB\) is \(M\).
\includegraphics{figure_9}
The equation of the circle is \(x^2 - 6x + y^2 + a = 0\), where \(a\) is a constant.
- In this question you must show detailed reasoning.
Find the \(x\)-coordinate of \(M\) and hence show that the area of triangle \(ABC\) is \(\frac{3}{2}\sqrt{9 - 2a}\).
[6]
- Find the value of \(a\) when the area of triangle \(ABC\) is zero.
[1]
- Give a geometrical interpretation of the case in part (b)(i).
[1]
- Give a geometrical interpretation of the case where \(a = 5\).
[1]