The diagram shows the cross-section through the centre of mass of a uniform solid prism. The cross-section is a trapezium ABCD with AB and CD perpendicular to AD. The lengths of AB and AD are each 5 cm and the length of CD is \((a + 5)\) cm.
\includegraphics{figure_7}
- Show the distance of the centre of mass of the prism from AD is
$$\frac{a^2 + 15a + 75}{3(a + 10)} \text{ cm.}$$
[5]
The prism is placed with the face containing AB in contact with a horizontal surface.
- Find the greatest value of \(a\) for which the prism does not topple.
[3]
The prism is now placed on an inclined plane which makes an angle \(\theta^o\) with the horizontal. AB lies along a line of greatest slope with B higher than A.
- Using the value for \(a\) found in part (ii), and assuming the prism does not slip down the plane, find the great value of \(\theta\) for which the prism does not topple.
[6]